我正在尝试让我的c++应用程序根据web数据库对用户/通过进行身份验证。为此,我为user/pass创建了一个简单的html表单,它将触发身份验证php脚本。
我很难理解cURL,因为我对它完全是个新手。现在,我可以将数据发送到html表单,但我甚至不知道我是否做得正确。
理想情况下,我希望你教我如何做到这一点,以及如何阅读回复。我的意思是,如果登录是正确的,我怎么让c++知道?
我拥有的所有代码:
HTML
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<form method="post" action="check.php">
<input type="text" name="uname"/>
<input type="password" name="password"/>
<input type="submit"/>
</form>
</html>
PHP
<?php
$fileDir = '/var/www/html/forums/';
require($fileDir . '/src/XF.php');
XF::start($fileDir);
$app = \XF::setupAPP('XF\App');
$username = $_POST['uname']; $password = $_POST['password'];
$ip = $app->request->getIp();
$loginService = $app->service('XF:User\Login', $username, $ip);
$userValidate = $loginService->validate($password, $error);
if(!$userValidate)
{
//Not good pass / user
$data = ['validated' => false];
}
else $data = ['validated' => true];
header('Content-type: application/json');
echo json_encode($data);
?>
C++
#include "stdafx.h"
#include <iostream>
#include <stdio.h>
#include <curl/curl.h>
using namespace std;
int main()
{
char username[20];
char password[25];
cout << "Username: ";
cin >> username;
cout << "Password: ";
cin >> password;
/*------------------------------------------*/
CURL *curl;
CURLcode res;
curl_global_init(CURL_GLOBAL_ALL);
curl = curl_easy_init();
if (curl) {
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(curl, CURLOPT_URL, "https://localhost/index.hmtl");
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, "uname=?&password=?", username, password);
res = curl_easy_perform(curl);
if (res != CURLE_OK) {
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
}
curl_easy_cleanup(curl);
}
curl_global_cleanup();
}
编辑:工作解决方案
#include "stdafx.h"
#include <iostream>
#include <stdio.h>
#include <string>
#include <curl/curl.h>
using namespace std;
string urlencode(const string &str) {
char *escaped = curl_escape(str.c_str(), str.length());
if (escaped == NULL) throw runtime_error("curl_escape failed!");
string ret = escaped;
curl_free(escaped);
return ret;
}
size_t my_write_function(const void * indata, const size_t size, const size_t count, void *out) {
(*(string*)out).append((const char*)indata, size*count);
return size * count;
}
int main()
{
string username;
string password;
cout << "Username: ";
getline(cin, username);
cout << "Password: ";
getline(cin, password);
/*------------------------------------------*/
CURL *curl;
CURLcode res;
curl_global_init(CURL_GLOBAL_ALL);
curl = curl_easy_init();
if (curl) {
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(curl, CURLOPT_URL, "https://urlto/index.html");
curl_easy_setopt(curl, CURLOPT_COPYPOSTFIELDS, string("uname=" + urlencode(username) + "&password=" + urlencode(password)).c_str());
string response;
curl_easy_setopt(curl, CURLOPT_URL, "https://urlto/check.php");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, my_write_function);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &response);
res = curl_easy_perform(curl);
//cout << "Response from website: " << response << endl;
if (response.find("true") == string::npos) {
cout << "Failed to login";
}
else cout << "Log in successful";
if (res != CURLE_OK) {
fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res));
}
curl_easy_cleanup(curl);
}
curl_global_cleanup();
}
发布于 2018-08-26 23:59:23
i dont even know if im doing properly.
-好吧,你的代码中肯定有几个bug,
首先,如果用户名超过20个字节,或者密码超过25个字节,您认为会发生什么?试一试
string username;
getline(cin, username);
而不是。c++会根据需要不断增加用户名的大小,直到内存用完。
我发现你在使用CURLOPT_POSTFIELDS
(而且是错误的),在你知道你在做什么之前,我建议你改用CURLOPT_COPYPOSTFIELDS
。(顺便说一句,我自己几乎总是使用COPYPOSTFIELDS )这一行是错误的:
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, "uname=?&password=?", username, password);`
因为curl_easy_setopt()只接受3个参数,但您试图给它5个参数。我认为这甚至不会编译,但即使它编译了,它也肯定不会在运行时工作。试试下面这样的代码:
string urlencode(const string& str)
{
char *escaped = curl_escape(str.c_str(), str.length());
if (unlikely(escaped==NULL))
{
throw runtime_error("curl_escape failed!");
}
string ret = escaped;
curl_free(escaped);
return ret;
}
curl_easy_setopt(curl, CURLOPT_COPYPOSTFIELDS, string("uname="+urlencode(username)+"&password="+urlencode(password)).c_str());
至于读取(和捕获)输出,有很多方法可以做到这一点,但是如何挂钩CURLOPT_WRITEFUNCTION呢?这往往是可行的,比如:
size_t my_write_function( const void * indata, const size_t size, const size_t count, void *out){
(*(string*)out).append((const char*)indata,size*count);
return size*count;
}
然后
string response;
curl_easy_setopt(curl,CURLOPT_WRITEFUNCTION,my_write_function);
curl_easy_setopt(curl,CURLOPT_WRITEDATA,&response);
res = curl_easy_perform(curl);
cout << "response from website: " << response << endl;
现在,您可以通过检查响应中是否存在字符串"true“来检查您是否登录(因为如果您登录了,它应该会响应类似于{validated:true}
的内容),例如
if(response.find("true")==string::npos){
cout << "failed to authenticate!";
}else{
cout << "authenticated successfully!";
}
(还有一个警告,虽然在CURLOPT_WRITEFUNCTION中使用lambda回调可能很诱人,但这是一个陷阱,当将c++ lambda作为回调函数提供给curl时,可能会崩溃……经历过,做到了。)
https://stackoverflow.com/questions/52027006
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