在通过在线课程学习Java的同时,我还尝试了一些使用本教程编写的代码。有一种方法,它应该连接“课程”,并在最后打印出来。我想使用递归而不是循环。
private String courses = "";
private int tuitionBalance = 0;
public void enroll() {
System.out.println("Enter course to enroll or \"Q\" to quit.");
Scanner in = new Scanner(System.in);
String course = in.nextLine();
if (!course.equalsIgnoreCase("q")) {
courses = courses + "\n" + course;
tuitionBalance = tuitionBalance + costOfCourse;
enroll();
}
System.out.println("Enrolled in: " + courses);
System.out.println("Tuition balance: " + tuitionBalance);
return; // even with "return", this method executes multiple times after leaving if statement.
}
当此方法运行时,它会一直提示输入,直到按下'Q‘为止。串联工作正常。然后它留下"if statement“和(对我来说很奇怪的是),它运行最后两行println代码的次数与提供的输入一样多。
例如,当我输入三种类型的"course“,然后按'Q',输出是:
Enter course to enroll or "Q" to quit.
History // My entry
Enter course to enroll or "Q" to quit.
Math // My entry
Enter course to enroll or "Q" to quit.
Biology // My entry
Enter course to enroll or "Q" to quit.
q // My entry
Enrolled in:
History
Math
Biology
Tuition balance: 1800
Enrolled in:
History
Math
Biology
Tuition balance: 1800
Enrolled in:
History
Math
Biology
Tuition balance: 1800
Enrolled in:
History
Math
Biology
Tuition balance: 1800
Process finished with exit code 0
你能告诉我发生了什么事吗?
编辑:我已经阅读了Understanding recursion [closed],但我没有找到任何关于递归如何影响调用堆栈的信息。有很多关于如何使用递归的很好的信息,但我仍然没有找到我的问题的答案。
发布于 2018-08-26 01:50:50
问题是,您不希望在用户已经进入课程的情况下打印递归,否则一个简单的方法就可以解决问题
private String courses = "";
private int tuitionBalance = 0;
public void enroll() {
System.out.println("Enter course to enroll or \"Q\" to quit.");
Scanner in = new Scanner(System.in);
String course = in.nextLine();
if (!course.equalsIgnoreCase("q")) {
courses = courses + "\n" + course;
tuitionBalance = tuitionBalance + costOfCourse;
enroll();
}
else{//now it would come here only once after user has entered q after which it returns
System.out.println("Enrolled in: " + courses);
System.out.println("Tuition balance: " + tuitionBalance);
}
return;
}
https://stackoverflow.com/questions/52019653
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