Python套接字如何处理客户端意外关闭
Python套接字如何处理客户端意外关闭
提问于 2013-06-04 18:05:06
我的python套接字服务器监听，然后连接到一个客户端，然后该客户端将从用户发送不确定数量的字符串。然后，客户端可能会关闭或断开与服务器的连接。
这会导致错误。
Errno 10053已建立的连接被主机中的软件中止。或Errno 10054现有连接被远程主机强制关闭
如何处理此事件，以便关闭连接并重新启动服务器以侦听重新连接？
Python服务器示例：
# Echo server program
import socket
import sys
HOST = None # Symbolic name meaning all available interfaces
PORT = 7001 # Arbitrary non-privileged port
s = None
def startListening():
print "starting to listen"
for res in socket.getaddrinfo(HOST, PORT, socket.AF_UNSPEC,
socket.SOCK_STREAM, 0, socket.AI_PASSIVE):
af, socktype, proto, canonname, sa = res
try:
s = socket.socket(af, socktype, proto)
except socket.error as msg:
s = None
continue
try:
s.bind(sa)
s.listen(1)
except socket.error as msg:
s.close()
s = None
continue
break
if s is None:
print 'could not open socket'
sys.exit(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data:
break
print data
message = ""
while not "quit" in message:
message = raw_input('Say Something : ')
conn.sendall(message)
#conn.send("I got that, over!")
conn.close()
print "connection closed"
while 1:
startListening()python客户端示例：
# Echo client program
import socket
import sys
HOST = 'localhost' # The remote host
PORT = 7001 # The same port as used by the server
s = None
for res in socket.getaddrinfo(HOST, PORT, socket.AF_UNSPEC, socket.SOCK_STREAM):
af, socktype, proto, canonname, sa = res
try:
s = socket.socket(af, socktype, proto)
except socket.error as msg:
s = None
continue
try:
s.connect(sa)
except socket.error as msg:
s.close()
s = None
continue
break
if s is None:
print 'could not open socket'
sys.exit(1)
s.sendall("Please send me some strings")
data = ""
while ("quit" not in data):
data = s.recv(1024)
print 'Received', repr(data)
s.close()要重现此错误，请在一个命令窗口中运行服务器，在第二个命令窗口中运行客户端，然后关闭客户端窗口。
回答 3
Stack Overflow用户
发布于 2013-06-04 20:27:36
在服务器脚本中的data send和data recv周围添加try: except:可以缓解这个问题：
# Echo server program
import socket
import sys
HOST = None # Symbolic name meaning all available interfaces
PORT = 7001 # Arbitrary non-privileged port
s = None
def startListening():
print "starting to listen"
for res in socket.getaddrinfo(HOST, PORT, socket.AF_UNSPEC,
socket.SOCK_STREAM, 0, socket.AI_PASSIVE):
af, socktype, proto, canonname, sa = res
try:
s = socket.socket(af, socktype, proto)
except socket.error as msg:
s = None
continue
try:
s.bind(sa)
s.listen(1)
except socket.error as msg:
s.close()
s = None
continue
break
if s is None:
print 'could not open socket'
sys.exit(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
try:
data = conn.recv(1024)
except:
print "cannot recieve data"
break
if not data:
break
print data
message = ""
while not "quit" in message:
message = raw_input('Say Something : ')
try:
conn.sendall(message)
except Exception as exc:
#print exc # or something.
print "message could not be sent"
break
#conn.send("I got that, over!")
conn.close()
print "connection closed"
while 1:
startListening()Stack Overflow用户
发布于 2013-06-04 18:07:56
只需关闭连接的一端，并准备好再次接受新连接。
处理此问题的最佳方法是将服务器套接字的创建和接受/读/写循环分开：
create_server_socket()
while True:
accept_new_connection();
try:
read_request();
write_response()
finally:
close_connection()Stack Overflow用户
发布于 2013-06-04 20:17:16
我认为当客户端意外关闭时，根据SIGPIPE，您应该处理信号
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/16915023
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