blocks|key|1155510|text|如果两种格式相同，则只需使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1155511|DateFormat+dateFormat+=+new+SimpleDateFormat("dd/MM/yyyy");|code-block|syntax|javascript|1155512|如果它们不同：|1155513|private+static+Map<Locale,+String>+formats+=+new+HashMap<Locale,+String>();

static+{
++++formats.put(new+Locale("en_US"),+"MM/dd/yyyy");
++++formats.put(new+Locale("da_DK"),+"dd.MM.yyyy");
}|1155514|然后不使用DateFormat.getDateInstance(..)，而是使用|offset|length|style|CODE|1155515|new+SimpleDateFormat(formats.get(locale)).format(..);|1155516|entityMap^0|0|0|0|0|5|U|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@$M|Z|N|10|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

If both formats are the same, then simply use:
<pre><code>DateFormat dateFormat = new SimpleDateFormat(&quot;dd/MM/yyyy&quot;);
</code></pre>
If they differ:
<pre><code>private static Map&lt;Locale, String&gt; formats = new HashMap&lt;Locale, String&gt;();

static {
 formats.put(new Locale(&quot;en_US&quot;), &quot;MM/dd/yyyy&quot;);
 formats.put(new Locale(&quot;da_DK&quot;), &quot;dd.MM.yyyy&quot;);
}
</code></pre>
And then instead of using <code>DateFormat.getDateInstance(..)</code> use
<pre><code>new SimpleDateFormat(formats.get(locale)).format(..);
</code></pre>

blocks|key|1155564|text|java.time|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1155565|您可以使用java.time类来替代旧的date-time类。使用从DateTimeFormatterBuilder派生的DateTimeFormatter而不是DateFormat。|offset|length|style|CODE|1155566|DateTimeFormatterBuilder可以提供一个可以与DateTimeFormatter一起使用的模式。使用String.replace，您可以在FormatStyle.SHORT日期模式中插入yyyy而不是yy：|1155567|++++++++String+pattern+=
++++++++++++DateTimeFormatterBuilder
++++++++++++++++.getLocalizedDateTimePattern
++++++++++++++++++++(+FormatStyle.SHORT
++++++++++++++++++++,+null
++++++++++++++++++++,+IsoChronology.INSTANCE
++++++++++++++++++++,+locale
++++++++++++++++++++);
++++++++pattern+=+pattern.replace("yy",+"yyyy");
++++++++DateTimeFormatter+dtf+=
++++++++++++DateTimeFormatter.ofPattern(pattern);|code-block|syntax|javascript|1155568|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/time/package-summary.html|1|https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatterBuilder.html|2|https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html|3|https://docs.oracle.com/javase/8/docs/api/java/text/DateFormat.html|4|https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#replace-java.lang.CharSequence-java.lang.CharSequence-|5|http://docs.oracle.com/javase/8/docs/api/java/time/format/FormatStyle.html#SHORT^0|0|Y|O|1P|H|29|A|5|9|0|Y|O|1|1P|H|2|29|A|3|0|0|O|X|H|1O|E|2V|4|32|2|1O|E|4|27|H|5|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|17|8|@$D|18|E|19|F|G]|$D|1A|E|1B|F|G]|$D|1C|E|1D|F|G]]|9|@$D|1E|E|1F|1|1G]|$D|1H|E|1I|1|1J]|$D|1K|E|1L|1|1M]|$D|1N|E|1O|1|1P]]|A|$]]|$1|H|3|I|5|6|7|1Q|8|@$D|1R|E|1S|F|G]|$D|1T|E|1U|F|G]|$D|1V|E|1W|F|G]|$D|1X|E|1Y|F|G]|$D|1Z|E|20|F|G]]|9|@$D|21|E|22|1|23]|$D|24|E|25|1|26]]|A|$]]|$1|J|3|K|5|L|7|27|8|@]|9|@]|A|$M|N]]|$1|O|3|-4|5|6|7|28|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]|Y|$5|R|S|T|A|$U|Z]]|10|$5|R|S|T|A|$U|11]]|12|$5|R|S|T|A|$U|13]]|14|$5|R|S|T|A|$U|15]]]]

<h1>java.time</h1>

You can use the <a href="https://docs.oracle.com/javase/8/docs/api/java/time/package-summary.html" rel="nofollow">java.time</a> classes that supplant the old date-time classes. Instead of <a href="https://docs.oracle.com/javase/8/docs/api/java/text/DateFormat.html" rel="nofollow"><code>DateFormat</code></a>, use a <a href="https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html" rel="nofollow"><code>DateTimeFormatter</code></a> derived from a <a href="https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatterBuilder.html" rel="nofollow"><code>DateTimeFormatterBuilder</code></a>.

<code>DateTimeFormatterBuilder</code> can provide a pattern that can be used with <code>DateTimeFormatter</code>. Using <a href="https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#replace-java.lang.CharSequence-java.lang.CharSequence-" rel="nofollow"><code>String.replace</code></a> you can insert <code>yyyy</code> instead of <code>yy</code> in the <a href="http://docs.oracle.com/javase/8/docs/api/java/time/format/FormatStyle.html#SHORT" rel="nofollow">FormatStyle.SHORT</a> date pattern:

<pre><code> String pattern =
 DateTimeFormatterBuilder
 .getLocalizedDateTimePattern
 ( FormatStyle.SHORT
 , null
 , IsoChronology.INSTANCE
 , locale
 );
 pattern = pattern.replace("yy", "yyyy");
 DateTimeFormatter dtf =
 DateTimeFormatter.ofPattern(pattern);
</code></pre>

blocks|key|1155576|text|http://www.java2s.com/Tutorials/Java/Data_Type_How_to/Legacy_Date/Display_the_year_in_full_four_digits_when_using_localization.htm|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1155577|DateFormat+df+=+DateFormat.getDateInstance(DateFormat.SHORT,+locale);
++++if+(df+instanceof+SimpleDateFormat)+{
++++++SimpleDateFormat+sdf+=+(SimpleDateFormat)+df;
++++++//+To+show+Locale+specific+short+date+expression+with+full+year
++++++String+pattern+=+sdf.toPattern().replaceAll("y%2B",+"yyyy");
++++++sdf.applyPattern(pattern);
++++++return+sdf.format(cal.getTime());
++++}|code-block|syntax|javascript|1155578|entityMap|0|LINK|mutability|MUTABLE|url^0|0|3M|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|4]]]]

<a href="http://www.java2s.com/Tutorials/Java/Data_Type_How_to/Legacy_Date/Display_the_year_in_full_four_digits_when_using_localization.htm" rel="nofollow noreferrer">http://www.java2s.com/Tutorials/Java/Data_Type_How_to/Legacy_Date/Display_the_year_in_full_four_digits_when_using_localization.htm</a>

<pre><code>DateFormat df = DateFormat.getDateInstance(DateFormat.SHORT, locale);
 if (df instanceof SimpleDateFormat) {
 SimpleDateFormat sdf = (SimpleDateFormat) df;
 // To show Locale specific short date expression with full year
 String pattern = sdf.toPattern().replaceAll("y+", "yyyy");
 sdf.applyPattern(pattern);
 return sdf.format(cal.getTime());
 }
</code></pre>

Is there any way to make <a href="https://docs.oracle.com/javase/8/docs/api/java/text/DateFormat.html" rel="nofollow noreferrer"><code>DateFormat</code></a> format a date with a full year (eg. 12/12/2010), when using <a href="https://docs.oracle.com/javase/8/docs/api/java/text/DateFormat.html#SHORT" rel="nofollow noreferrer"><code>DateFormat.SHORT</code></a> as the pattern? I have to format dates in both en_US and da_DK.

I know I could use <a href="https://docs.oracle.com/javase/8/docs/api/java/text/DateFormat.html#MEDIUM" rel="nofollow noreferrer"><code>DateFormat.MEDIUM</code></a>, but the date have to be formatted using only numbers and separators, and <code>DateFormat.MEDIUM</code> for en_US produces something like 'Dec 12, 2010'.

Java DateFormat.SHORT with full year

有没有办法使格式的日期与完整的一年(例如，12/12/2010)，什么时候使用作为模式？我必须在en_US和da_DK中格式化日期。我知道我可以使用，但日期必须只使用数字和分隔符进行格式化，而en_US的DateFormat.MEDIUM生成的结果类似于'Dec 12,2010‘。

问Java DateFormat.SHORT全年版
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