blocks|key|2630242|text|要获取一个月中的工作日数，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2630243|import+calendar

weekdays+=+0
cal+=+calendar.Calendar()

for+week+in+cal.monthdayscalendar(2018,+7):
++++for+i,+day+in+enumerate(week):
++++++++#+Check+if+is+a+weekday+and+the+day+is+from+this+month
++++++++if+i+<+5+and+day+!=+0:
++++++++++++weekdays+%2B=+1

print+weekdays|code-block|syntax|javascript|2630244|要获取特定日期的工作日数，可以修改上面的代码，以便在到达输入的日期时返回工作日计数。|2630245|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

To get the number of weekdays in a month:

<pre><code>import calendar

weekdays = 0
cal = calendar.Calendar()

for week in cal.monthdayscalendar(2018, 7):
 for i, day in enumerate(week):
 # Check if is a weekday and the day is from this month
 if i &lt; 5 and day != 0:
 weekdays += 1

print weekdays
</code></pre>

To get the weekday number of a specific day, you can modify the above code to return the weekday count when the input day is reached.

blocks|key|2630252|text|以下是计算前一周天数的一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2630253|请注意，year、month、day的类型转换为int。|offset|length|style|CODE|2630254|import+calendar

year+=+int(input('Year:+'))
month+=+int(input('Month:+'))
day+=+int(input('Day:+'))

full_wks+=+day+/+7
extra_days+=+day+%25+7

first_day+=+calendar.weekday(year,+month,+1)
if+first_day+>=+5:++++++++++++++#+if+month+begins+on+a+weekend
++++weekend+=+7+-+first_day+++++#+yields+1+if+Sunday,+2+if+Saturday
++++extra_days+-=+weekend

weekdays+=+full_wks+*+5+%2B+extra_days

ordinal+=+lambda+n:+"{}{}".format(n,+'tsnrhtdd'[n%255*(n%25100%5E15>4>n%2510)::4])

print+"{}/{}+is+the+{}+weekday+in+the+month.".format(month,+day,+ordinal(weekdays))|code-block|syntax|javascript|2630255|输出：|2630256|Year:+2018
Month:+7
Day:+20
7/20+is+the+15th+weekday+in+the+month.|2630257|在Code+Golf上从xsot转换成序数。|2630258|entityMap|0|LINK|mutability|MUTABLE|url|https://codegolf.stackexchange.com/questions/4707/outputting-ordinal-numbers-1st-2nd-3rd^0|0|O|3|0|0|0|0|1|9|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|14|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|15|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|16|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|17|8|@]|9|@$D|18|E|19|1|1A]]|A|$]]|$1|S|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

Here's one way to find the number of previous weekdays:

Note that the type conversions for year, month, day are <code>int</code>.

<pre><code>import calendar

year = int(input('Year: '))
month = int(input('Month: '))
day = int(input('Day: '))

full_wks = day / 7
extra_days = day % 7

first_day = calendar.weekday(year, month, 1)
if first_day &gt;= 5: # if month begins on a weekend
 weekend = 7 - first_day # yields 1 if Sunday, 2 if Saturday
 extra_days -= weekend

weekdays = full_wks * 5 + extra_days

ordinal = lambda n: "{}{}".format(n, 'tsnrhtdd'[n%5*(n%100^15&gt;4&gt;n%10)::4])

print "{}/{} is the {} weekday in the month.".format(month, day, ordinal(weekdays))
</code></pre>

Output:

<pre><code>Year: 2018
Month: 7
Day: 20
7/20 is the 15th weekday in the month.
</code></pre>

Ordinal number conversion from xsot on <a href="https://codegolf.stackexchange.com/questions/4707/outputting-ordinal-numbers-1st-2nd-3rd">Code Golf</a>.

blocks|key|2419806|text|我在大约10分钟内做了一个简单的解决方案。我的方法在很大程度上依赖于列表理解和字符串方法，所以如果你还不熟悉它们，我建议你去查一查。首先将结果拆分成行，标题需要重新居中，其他行需要删除最后一个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2419807|通过使用strip()方法将第一行重新居中，删除该行请求时的空格，然后预先添加两个空格。|2419808|通过使用列表理解只包含每行的前15个字符来利用周末。|2419809|最后的部分是最难的。这个想法是为了计算我的格式化日历中有多少天的数字。首先将包含日期数字的所有行放到一个大行中，然后用空格拆分该行以获得所有日期数字的列表，最后使用该列表的大小。|2419810|import+calendar

year+=+float(input('Year:+'))
month+=+float(input('Month:+'))
input_year+=+[]
input_month+=+[]

if+year+>=+1000+and+year+<=3000:
++++input_year.append(year)
if+month+>=+1+and+month+<=12:
++++input_month.append(month)

cal_format+=+calendar.TextCalendar(calendar.MONDAY)
result_cal+=+cal_format.formatmonth(int(input_year[0]),+int(input_month[0]))

lines+=+result_cal.split("\n")+#+Split+result_cal+into+a+list+of+lines
title_line+=+lines[0]+#+Save+first+line,+we+want+to+edit+this+differently
title_line+=+"++"+%2B+title_line.strip()+#+Change+the+indentation+of+the+title+line


lines+=+lines[1:]+#+Now+select+lines+below+the+first+
lines+=+[line[:3*5]+for+line+in+lines]+#+Only+Keep+first+15+characters+or+each
+++++++++++++++++++++++++++++++++++++++#+line+to+exclude+weekends.+(5+weekdays+*
+++++++++++++++++++++++++++++++++++++++#+3+chars+per+day)

lines+=+[line+for+line+in+lines+if+len(line.strip())]+#+Don't+include+empty+lines
++++++++++++++++++++++++++++++++++++++++++++++++++++++#+happens+if+month+starts
++++++++++++++++++++++++++++++++++++++++++++++++++++++#+on+a+weekend.

#+prints+out+the+result
print(title_line)
for+line+in+lines:
++++print(line)

#+Next+work+out+how+many+working+days+in+month.
nums+=+"".join(lines[1:]).split("+")+#+Three+parts:+first+lines[1:]+means+this
+++++++++++++++++++++++++++++++++++++#+only+looks+at+the+portion+of+the+calendar
+++++++++++++++++++++++++++++++++++++#+with+numbers+written+on+then.+2nd+"".join()
+++++++++++++++++++++++++++++++++++++#+joins+the+lines+into+a+single+string+on+1+line
+++++++++++++++++++++++++++++++++++++#+3rd+the+.split("+")+splits+the+string+based+on+spaces
+++++++++++++++++++++++++++++++++++++#+unfortunatly+2+consecutive+spaces+result+in+an+empty
+++++++++++++++++++++++++++++++++++++#+string.

nums+=+[num+for+num+in+nums+if+len(num)]+#+Filters+the+empty+string.
print(f"There+are+{len(nums)}+working+days+in+the+month+you+selected")+#+Prints+result
#(uses+f-string,+you+may+want+to+look+them+up,+I+find+them+to+be+very+useful)|code-block|syntax|javascript|2419811|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Q|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I made a simple solution in around 10 minutes. My approach relies heavily on list comprehensions and string methods such as join and split, so I recommend you look those up if your not familiar with them already. First split the result into lines, the tittle needs to be recentred, and the other lines needed the last characters removing.

Recenter the first line by using the strip() method to removing the whitespace at the begging of the line, then adding two space beforehand.

Take of the weekends by only including the first 15 characters of each line using list comprehensions.

The last part was the hardest. The idea was to count how many day numbers there were in my formatted calendar. First put all the lines with day numbers into one big line, then split the line by spaces to get a list of all day numbers, and finally use the size of the list.

<pre><code>import calendar

year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []

if year &gt;= 1000 and year &lt;=3000:
 input_year.append(year)
if month &gt;= 1 and month &lt;=12:
 input_month.append(month)

cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))

lines = result_cal.split("\n") # Split result_cal into a list of lines
title_line = lines[0] # Save first line, we want to edit this differently
title_line = " " + title_line.strip() # Change the indentation of the title line


lines = lines[1:] # Now select lines below the first 
lines = [line[:3*5] for line in lines] # Only Keep first 15 characters or each
 # line to exclude weekends. (5 weekdays *
 # 3 chars per day)

lines = [line for line in lines if len(line.strip())] # Don't include empty lines
 # happens if month starts
 # on a weekend.

# prints out the result
print(title_line)
for line in lines:
 print(line)

# Next work out how many working days in month.
nums = "".join(lines[1:]).split(" ") # Three parts: first lines[1:] means this
 # only looks at the portion of the calendar
 # with numbers written on then. 2nd "".join()
 # joins the lines into a single string on 1 line
 # 3rd the .split(" ") splits the string based on spaces
 # unfortunatly 2 consecutive spaces result in an empty
 # string.

nums = [num for num in nums if len(num)] # Filters the empty string.
print(f"There are {len(nums)} working days in the month you selected") # Prints result
#(uses f-string, you may want to look them up, I find them to be very useful)
</code></pre>

I was hoping that someone could give me some examples of ways in which I can return calendar data that does the following. 

<hr>

<ol>
<li>Returns the number of days in any given month (past/present/future),
but after excluding Saturdays and Sundays. </li>
</ol>

Example: 

input('Year: ') — 2018

input('Month: ') — 7

End Result: The number of weekdays in (July) of (2018) is (22).

<hr>

<ol start="2">
<li>Assign an iterator to each weekday after excluding Sat. and Sun.</li>
</ol>

Example: 

input('Year: ') — 2018

input('Month: ') — 7

input('date: ') — 20

End Result: The (20) is a (Friday) and is the (15) weekday of (July), (2018).

This is the code that I've been able to create so far...

<pre><code>import calendar

year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []

if year &gt;= 1000 and year &lt;=3000:
 input_year.append(year)
if month &gt;= 1 and month &lt;=12:
 input_month.append(month)

cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))
print(result_cal)

THE END RESULT IS...

Year: 1978
Month: 3
 March 1978
Mo Tu We Th Fr Sa Su
 1 2 3 4 5
 6 7 8 9 10 11 12
13 14 15 16 17 18 19
20 21 22 23 24 25 26
27 28 29 30 31
</code></pre>

This only prints out a Text Calendar with Sat. and Sun at the end of each week, so I can at least visually exclude them. But I would really like to be able to programmatically exclude them and be able to input the above variables to calculate weekdays in a month, and which weekday each day is within that month.

Python - How to exclude Sat. and Sun. from weeks

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我希望有人能给我一些返回日历数据的方法的例子，这些日历数据可以做以下事情。返回任何给定月份的天数(过去/现在/未来)，但不包括周六和周日。示例：输入(‘：') -2018年输入input('Month：') - 7最终结果：2018年7月的工作日数为(22)。在排除Sat之后的每个工作日都会分配一个迭代器。和Sun.示...

问Python -如何排除Sat。还有Sun。从几周开始
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问Python -如何排除Sat。还有Sun。从几周开始
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