问使用Python面向对象的解析几何

EN

from copy import copy

class Point:

    def __init__(self, x=0.0, y=0.0):
        self.x = x
        self.y = y

    def __repr__(self):
        return '({}, {})'.format(self.x, self.y)


class Rectangle:

    def __init__(self, point, width, height):
        self.point = copy(point)
        self.width = abs(width)
        self.height = abs(height)
        if self.width == 0:
            self.width == 1
        if self.height == 0:
            self.height == 1

    def __repr__(self):
        return '[{}, w = {}, h = {}]'.format(self.point, self.width, self.height)

    def surface_area(self):
        return self.width * self.height

    def circunference(self):
        return 2*(self.width + self.height)

    def bottom_right(self):
        return Point(self.point.x + self.width, self.point.y + self.height)

    def overlap(self, r):
        r1, r2 = self, r
        if self.point.x > r.point.x or (self.point.x == r.point.x and self.point.y > r.point.y):
            r1, r2 = r, self
        if r1.bottom_right().x <= r2.point.x or r1.bottom_right().y <= r2.point.y:
            return None
        return Rectangle(r2.point,
            min(r1.bottom_right().x - r2.point.x, r2.width),
            min(r1.bottom_right().y - r2.point.y, r2.height))


r1 = Rectangle(Point(1, 1), 8, 5)
r2 = Rectangle(Point(2, 3), 9, 2)

print(r1, '\n', r1.surface_area(), '\n', r1.circunference(), '\n', r1.bottom_right())
r = r1.overlap(r2)
if r:
    print(r)
else:
    print('No, overlap.')