如何使用java使两个json对象相对于json路径相等或不相等
如何使用java使两个json对象相对于json路径相等或不相等
提问于 2018-09-20 23:59:14
我想比较两个json对象，在json路径的帮助下，它们在结构上是否相同。我不考虑值，只是提前structure.Thank你有任何帮助例如下面两个json文件json-1和json-2，两者在结构上是相同的，但你可以看到值是不同的。
json-1
{
"squadName": "Super hero squad",
"homeTown": "Metro City",
"formed": 2016,
"secretBase": "Super tower",
"active": true,
"members": [
{
"name": "man1",
"age": 50,
"secretIdentity": "Dan",
"powers": [
"Radiation resistance",
"Turning tiny",
"Radiation blast"
]
},
{
"name": "Madame Uppercut",
"age": 39,
"secretIdentity": "Jane Wilson",
"powers": [
"Million tonne punch",
"Damage resistance",
"Superhuman reflexes"
]
}
]
}json-2
{
"squadName": "Super hero1",
"homeTown": "Metro City",
"formed": 2016,
"secretBase": "Super tower",
"active": true,
"members": [
{
"name": "Man2",
"age": 33,
"secretIdentity": "Jukes",
"powers": [
"Radiation resistance",
"Turning tiny",
"Radiation blast"
]
},
{
"name": "Madame Uppercut1111",
"age": 30,
"secretIdentity": "ran",
"powers": [
"Million tonne punch",
"Damage resistance",
"Superhuman reflexes"
]
}
]
}下面两个json具有不同的结构：
{
"squadName": "Super hero1",
"homeTown": "Metro City",
"formed": 2016,
"secretBase": "Super tower",
"active": true,
"members": [
{
"name": "Man2",
"age": 33,
"secretIdentity": "Jukes",
"powers": [
"Radiation resistance",
"Turning tiny",
"Radiation blast"
]
},
{
"name": "Madame Uppercut1111",
"age": 30,
"secretIdentity": "ran",
"powers": [
"Million tonne punch",
"Damage resistance",
"Superhuman reflexes"
]
}
]
}
and
{
"Name": "Super hero1",
"Town": "Metro City",
"year": 2016,
"base": "Super tower",
"IsActive": true,
"associates": [
{
"name1": "Man2",
"age1": 33,
"secretIdentity1": "Jukes",
"powers1": [
"Radiation resistance",
"Turning tiny",
"Radiation blast"
]
},
{
"name1": "Madame Uppercut1111",
"age1": 30,
"secretIdentity1": "ran",
"powers1": [
"Million tonne punch",
"Damage resistance",
"Superhuman reflexes"
]
}
]我已经编写了前面提到的来自两个json对象的below.Getting键的代码，并通过比较both.Wanted来验证我的逻辑是否正确。
List<String>list4 =printJsonObject(obj);
List<String>list5 =printJsonObject(obj1);
if(list5.containsAll(list4)){
boolean res=true;
System.out.println("res"+res);
}
public static List printJsonObject(JSONObject jsonObj) throws
JSONException {
Iterator keys = jsonObj.keys();
List<String> jsonKeys=new ArrayList<String>();
while(keys.hasNext()){
//based on you key types
Object keyObj = (String)keys.next();
Object keyvalue = jsonObj.get(keyObj.toString());
jsonKeys.add(keyObj.toString());
//for nested objects iteration if required
if (keyvalue instanceof JSONObject)
printJsonObject((JSONObject)keyvalue);
}
return jsonKeys;
}回答 1
Stack Overflow用户
发布于 2018-09-21 00:12:51
如果结构是一致的，您可以做的一件事是尝试通过将这些JSON对象映射到类来转换它们。如果它发现任何其他键不存在，它将引发异常，并通过捕获它，您知道它们具有不同的结构。这在默认情况下是启用的，可以使用注释@JsonIgnoreProperties(ignoreUnknown = true)禁用它，并尝试使用它。
这样做的一个好方法是添加Jackson库this is a good link tutorial并执行以下操作：
class Foo {
@JsonProperty("squadName") String name;
// (other props...)
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52429024
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