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社区首页 >问答首页 >在WordPress插件功能下加载.php文件

在WordPress插件功能下加载.php文件
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Stack Overflow用户
提问于 2013-01-20 23:19:47
回答 2查看 273关注 0票数 2

我有一个WordPress插件脚本

代码语言:javascript
复制
<?php
/*
Plugin Name: Saswat Routroy
Plugin URI: http://www.maheshchari.com/
Description: Description of my plugin
Author URI: http://www.maheshchari.com/
*/
class new_menu {

    function new_menu()
    {
        add_action('admin_menu', array(&$this, 'my_admin_menu'));
    }

    function my_admin_menu()
    {   //create a main admin panel
        //create a sub admin panel link above
        add_menu_page('CMS', 'CMS', 'administrator', 8, array(&$this,'overview'));
        add_submenu_page(8, 'View CMS Page', 'View CMS Page', 'administrator', 1, array(&$this,'view_page'));
        add_submenu_page(8, 'Add CMS Page', 'Add CMS Page', 'administrator', 2, array(&$this,'add_page'));
        //These functions adds sub menu for different kinds of admin panel on back end
        add_options_page('Pages Options', 'Saswat  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_options'));
        add_posts_page('Pages posts', 'Saswat  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_posts'));
        add_media_page('Pages media', 'Saswat  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_media'));
        add_pages_page('Pages pages', 'Saswat  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_pages'));
        add_users_page('Pages users', 'Saswat  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_users'));
        add_management_page('maheshchari', 'Mahesh  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_tools'));
        add_theme_page('maheshchari', 'Mahesh  Plugin', 'administrator', basename(__file__),array(&$this, 'my_plugin_themes'));

    }


    function overview()
    {
        echo '<h2>My Wordpress Plugin Overview</h2>';
    }

    function view_page()
    {
        echo '<h2>My Wordpress Plugin Settings</h2>';
    }

    function add_page()
    {
        //echo '<h2>My Wordpress Plugin Generel</h2>';
        echo "<form method='POST' action=''>
    <ul>
        <li><label for='fname'>Family Name (Sir Name)<span> *</span>: </label>
        <input id='fname' maxlength='45' size='10' name='fname' value='' /></li>    

        <li><label for='lname'>Last Name<span> *</span>: </label>
        <input id='lname' maxlength='45' size='10' name='lname' value='' /></li>
        <li><label for='lname'>Last Name<span> *</span>: </label>
        <input type='submit' maxlength='45' size='10' name='lname' value='' /></li>
    </ul>
</form>";
    }
    function my_plugin_options()
    {
        echo '<h2>My Wordpress Plugin Options</h2>';

    }
    function my_plugin_posts()
    {
        echo '<h2>My Wordpress Plugin posts</h2>';
    }
    function my_plugin_media()
    {
        echo '<h2>My Wordpress Plugin media</h2>';
    }
    function my_plugin_pages()
    {
        echo '<h2>My Wordpress Plugin pages</h2>';
    }
    function my_plugin_users()
    {
        echo '<h2>My Wordpress Plugin users</h2>';
    }

    function my_plugin_tools()
    {
        echo '<h2>My Wordpress Plugin tools</h2>';
    }

    function my_plugin_themes()
    {
        echo '<h2>My Wordpress Plugin themes</h2>';
    }


}


$mybackuper = &new new_menu();//instance of the plugin class

?>

该文件保存在\wp-content\plugins\admin-menu\new_menu.php下

现在,在函数add_page()中,我回显了html。我不想这样做,有没有办法在不回显脚本的情况下加载函数下的.php页面。

说这样的话:

代码语言:javascript
复制
<?php get_template_part( 'content-home' );?>
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2013-01-21 12:53:04

我知道答案了

代码语言:javascript
复制
include('content-home.php');
票数 0
EN

Stack Overflow用户

发布于 2013-01-21 01:20:22

我不太明白你的意思。下面是一种不使用回显来存储输出的方法:

代码语言:javascript
复制
public $contents_add_page = '';

function add_page()
{
    ob_start();

    //echo '<h2>My Wordpress Plugin Generel</h2>';
    echo "<form method='POST' action=''>
<ul>
<li><label for='fname'>Family Name (Sir Name)<span> *</span>: </label>
<input id='fname' maxlength='45' size='10' name='fname' value='' /></li>    
<li><label for='lname'>Last Name<span> *</span>: </label>
<input id='lname' maxlength='45' size='10' name='lname' value='' /></li>
<li><label for='lname'>Last Name<span> *</span>: </label>
<input type='submit' maxlength='45' size='10' name='lname' value='' /></li>
</ul>
</form>";

    $this->contents_add_page = ob_get_contents();
    ob_end_clean();
}

您也可以包含一个文件并将其输出存储在var中:

代码语言:javascript
复制
ob_start();
include DIR . '/content-home.php';
$contents            = ob_get_contents();
ob_end_clean();

实际上,我在WP中使用这些技术通过AJAX输出HTML。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/14425974

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