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Hibernate不会自动创建表
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Stack Overflow用户
提问于 2018-06-09 20:04:33
回答 3查看 20.8K关注 0票数 5

我有一个带有Hibernate/Spring/MySQL的Maven项目。我有基本的实体,我想让Hibernate自动创建表,但Hibernate不会创建表。也没有抛出异常,所以我不知道这里出了什么问题。

application.properties:

代码语言:javascript
复制
# ===============================
# = DATA SOURCE
# ===============================
spring.datasource.url = jdbc:mysql://localhost:3306/task
spring.datasource.username = root
spring.datasource.password = 12345678
spring.datasource.testWhileIdle = true
spring.datasource.validationQuery = SELECT 1

# ===============================
# = JPA / HIBERNATE
# ===============================
spring.jpa.show-sql = true
spring.jpa.hibernate.ddl-auto = create
spring.jpa.hibernate.naming-strategy = org.hibernate.cfg.ImprovedNamingStrategy
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQLDialect
spring.datasource.driver-class-name = com.mysql.jdbc.Driver
spring.jpa.properties.hibernate.format_sql = true
spring.jpa.properties.hibernate.id.new_generator_mappings = true
logging.level.org.hibernate.SQL=DEBUG
logging.level.org.hibernate.type.descriptor.sql.BasicBinder=TRACE
spring.datasource.tomcat.max-wait=20000
spring.datasource.tomcat.max-active=50
spring.datasource.tomcat.max-idle=20
spring.datasource.tomcat.min-idle=15
spring.datasource.tomcat.test-while-idle=true
spring.datasource.tomcat.test-on-borrow=true
spring.datasource.tomcat.time-between-eviction-runs-millis=3600000
spring.datasource.tomcat.validation-query=SELECT 1

User.java:

代码语言:javascript
复制
package com.example.model;

import java.util.ArrayList;
import java.util.List;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;

import lombok.Data;

@Entity
@Table(name = "user")
@Data
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "id")
    private int id;

    @Column(name = "telegramId")
    private Integer telegramId;

    @Column(name = "firstName")
    private String firstName;

    @Column(name = "lastName")
    private String lastName;

    @OneToMany(
            mappedBy = "user",
            cascade = CascadeType.ALL,
            orphanRemoval = true
            )
    private List<Message> msg = new ArrayList<>();
}

在User.java中,我也使用lombok。有什么建议吗?谢谢。

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/50774085

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