blocks|key|1704270|text|如果您一开始就给find一个绝对路径，它将打印绝对路径。例如，要查找当前目录中的所有.htaccess文件：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1704271|find+"$(pwd)"+-name+.htaccess|code-block|syntax|javascript|1704272|或者，如果您的shell将$PWD展开到当前目录：|1704273|find+"$PWD"+-name+.htaccess|1704274|find只需将指定给它的路径添加到文件的相对路径之前。|1704275|如果你想解析当前目录中的符号链接，Greg+Hewgill还建议使用pwd+-P。|1704276|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/893/greg-hewgill^0|8|4|0|0|D|4|0|0|0|4|0|Y|6|H|C|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|S|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

If you give <code>find</code> an absolute path to start with, it will print absolute paths. For instance, to find all .htaccess files in the current directory:

<pre><code>find "$(pwd)" -name .htaccess
</code></pre>

or if your shell expands <code>$PWD</code> to the current directory:

<pre><code>find "$PWD" -name .htaccess
</code></pre>

<code>find</code> simply prepends the path it was given to a relative path to the file from that path. 

<a href="https://stackoverflow.com/users/893/greg-hewgill">Greg Hewgill</a> also suggested using <code>pwd -P</code> if you want to resolve symlinks in your current directory.

blocks|key|1489664|text|readlink+-f+filename+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1489665|提供完整的绝对路径。但如果文件是符号链接，您将获得最终的解析名称。|unstyled|1489666|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>readlink -f filename 
</code></pre>

gives the full absolute path. but if the file is a symlink, u'll get the final resolved name.

blocks|key|1704604|text|将此用于目录(在bash中需要**后的/，以将其限制为目录)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1704605|ls+-d+-1+"$PWD/"**/|code-block|syntax|javascript|1704606|这适用于直接位于当前目录下的文件和目录，其名称包含.|1704607|ls+-d+-1+"$PWD/"*.*|1704608|这是适用于一切的：|1704609|ls+-d+-1+"$PWD/"**/*|1704610|取自此处http://www.zsh.org/mla/users/2002/msg00033.html|1704611|在bash中，如果启用shopt+-s+globstar，则**是递归的。|1704612|entityMap|0|LINK|mutability|MUTABLE|url|http://www.zsh.org/mla/users/2002/msg00033.html^0|F|2|J|1|0|0|P|1|0|0|0|0|4|1B|0|0|B|H|U|2|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|19|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1D|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1E|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1F|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1G|8|@]|D|@$9|1H|A|1I|1|1J]]|E|$]]|$1|U|3|V|5|6|7|1K|8|@$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]]|D|@]|E|$]]|$1|W|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]]]

Use this for dirs (the <code>/</code> after <code>**</code> is needed in bash to limit it to directories):

<pre><code>ls -d -1 "$PWD/"**/
</code></pre>

this for files and directories directly under the current directory, whose names contain a <code>.</code>:

<pre><code>ls -d -1 "$PWD/"*.*
</code></pre>

this for everything:

<pre><code>ls -d -1 "$PWD/"**/*
</code></pre>

Taken from here
 <a href="http://www.zsh.org/mla/users/2002/msg00033.html" rel="noreferrer">http://www.zsh.org/mla/users/2002/msg00033.html</a>

In bash, <code>**</code> is recursive if you enable <code>shopt -s globstar</code>.

blocks|key|1489368|text|您可以使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1489369|find+$PWD+|code-block|syntax|javascript|1489370|在狂欢中|1489371|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use 

<pre><code>find $PWD 
</code></pre>

in bash

blocks|key|1489459|text|如果你给find命令一个绝对路径，它会用一个绝对路径输出结果。因此，如果您要键入以下内容，请从Ken目录输入：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1489460|find+/home/ken/foo/+-name+bar+-print++++|code-block|syntax|javascript|1489461|(而不是相对路径find+.+-name+bar+-print)|offset|length|style|CODE|1489462|你应该得到：|1489463|/home/ken/foo/bar|1489464|因此，如果您想要一个ls+-l并让它返回绝对路径，那么只需告诉find命令对它找到的任何内容执行ls+-l即可。|1489465|find+/home/ken/foo+-name+bar+-exec+ls+-l+{}+;\+|1489466|注意：{}和;之间有一个空格|1489467|你会得到类似这样的东西：|1489468|-rw-r--r--+++1+ken+admin+++++++181+Jan+27+15:49+/home/ken/foo/bar|1489469|如果您不确定文件的位置，您可以随时更改搜索位置。只要搜索路径以"/“开头，返回的就是绝对路径。如果你正在搜索一个位置(如/)，你会得到很多权限被拒绝的错误，那么我建议你重定向标准错误，这样你就可以真正看到查找结果：|1489470|find+/+-name+bar+-exec+ls+-l+{}+;\+2>+/dev/null|1489471|(2>是Borne和Bash+shell的语法，但不能与C+shell一起使用。它也可以在其他shell中工作，但我只确定它在Bourne和Bash中有效)。|1489472|entityMap^0|0|0|8|N|0|0|0|A|5|1C|5|0|0|3|2|6|1|0|0|0|0|0|1|2|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1A|8|@$I|1B|J|1C|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|1D|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1F|8|@$I|1G|J|1H|K|L]|$I|1I|J|1J|K|L]]|9|@]|A|$]]|$1|S|3|T|5|D|7|1K|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1L|8|@$I|1M|J|1N|K|L]|$I|1O|J|1P|K|L]]|9|@]|A|$]]|$1|W|3|X|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1R|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1S|8|@]|9|@]|A|$]]|$1|12|3|13|5|D|7|1T|8|@]|9|@]|A|$E|F]]|$1|14|3|15|5|6|7|1U|8|@$I|1V|J|1W|K|L]]|9|@]|A|$]]|$1|16|3|-4|5|6|7|1X|8|@]|9|@]|A|$]]]|17|$]]

If you give the find command an absolute path, it will spit the results out with an absolute path. So, from the Ken directory if you were to type:

<pre><code>find /home/ken/foo/ -name bar -print 
</code></pre>

(instead of the relative path <code>find . -name bar -print</code>)

You should get:

<pre><code>/home/ken/foo/bar
</code></pre>

Therefore, if you want an <code>ls -l</code> and have it return the absolute path, you can just tell the find command to execute an <code>ls -l</code> on whatever it finds.

<pre><code>find /home/ken/foo -name bar -exec ls -l {} ;\ 
</code></pre>

NOTE: There is a space between <code>{}</code> and <code>;</code>

You'll get something like this:

<pre><code>-rw-r--r-- 1 ken admin 181 Jan 27 15:49 /home/ken/foo/bar
</code></pre>

If you aren't sure where the file is, you can always change the search location. As long as the search path starts with "/", you will get an absolute path in return. If you are searching a location (like /) where you are going to get a lot of permission denied errors, then I would recommend redirecting standard error so you can actually see the find results:

<pre><code>find / -name bar -exec ls -l {} ;\ 2&gt; /dev/null
</code></pre>

(<code>2&gt;</code> is the syntax for the Borne and Bash shells, but will not work with the C shell. It may work in other shells too, but I only know for sure that it works in Bourne and Bash).

blocks|key|1489778|text|上面的$PWD是Matthew的一个不错的选择。如果您想要查找只打印文件，那么您还可以添加-type+f选项来只搜索普通文件。其他选项是"d“，仅用于目录等。因此，在您的情况下，它将是(如果我只想搜索带有.c+ext的文件)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1489779|find+$PWD+-type+f+-name+"*.c"+|code-block|syntax|javascript|1489780|或者，如果您想要所有文件：|1489781|find+$PWD+-type+f|1489782|注意:您不能为上面的命令创建别名，因为当$PWD设置别名时，bash会自动完成您的主目录。|1489783|entityMap^0|3|4|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

The <code>$PWD</code> is a good option by Matthew above. If you want find to only print files then you can also add the -type f option to search only normal files. Other options are "d" for directories only etc. So in your case it would be (if i want to search only for files with .c ext):

<pre><code>find $PWD -type f -name "*.c" 
</code></pre>

or if you want all files:

<pre><code>find $PWD -type f
</code></pre>

Note: You can't make an alias for the above command, because $PWD gets auto-completed to your home directory when the alias is being set by bash.

blocks|key|1705429|text|你可以做到|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705430|ls+-1+%7Cxargs+realpath|code-block|syntax|javascript|1705431|如果需要指定绝对路径或相对路径，也可以这样做|1705432|+ls+-1+$FILEPATH+%7Cxargs+realpath|1705433|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can do
<pre><code>ls -1 |xargs realpath
</code></pre>
If you need to specify an absolute path or relative path You can do that as well
<pre><code> ls -1 $FILEPATH |xargs realpath
</code></pre>

blocks|key|1705007|text|只是一个替代方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705008|ls+-d+"$PWD/"*+|code-block|syntax|javascript|1705009|为了确定*是外壳扩展，所以|offset|length|style|CODE|1705010|echo+"$PWD/"*|1705011|也会做同样的事情(缺点是你不能用-1来用换行符分隔，而不是用空格分隔)。|1705012|entityMap^0|0|0|4|1|0|0|G|2|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

Just an alternative to 

<pre><code>ls -d "$PWD/"* 
</code></pre>

to pinpoint that <code>*</code> is shell expansion, so 

<pre><code>echo "$PWD/"*
</code></pre>

would do the same (the drawback you cannot use <code>-1</code> to separate by new lines, not spaces).

blocks|key|1490078|text|如果您需要当前目录和子目录中所有文件列表|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1490079|find+$PWD+-type+f|code-block|syntax|javascript|1490080|如果您只需要当前目录中所有文件列表|1490081|find+$PWD+-maxdepth+1+-type+f|1490082|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you need list of all files in current as well as sub-directories

<pre><code>find $PWD -type f
</code></pre>

If you need list of all files only in current directory

<pre><code>find $PWD -maxdepth 1 -type f
</code></pre>

blocks|key|1704692|text|lspwd()+{+for+i+in+$@;+do+ls+-d+-1+$PWD/$i;+done+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1704693|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>lspwd() { for i in $@; do ls -d -1 $PWD/$i; done }
</code></pre>

blocks|key|1704855|text|下面是一个示例，它打印出一个不带额外句点的列表，还演示了如何搜索文件匹配。希望这能有所帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1704856|find+.+-type+f+-name+"extr*"+-exec+echo+`pwd`/{}+\;+%7C+sed+"s%7C\./%7C%7C"|code-block|syntax|javascript|1704857|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's an example that prints out a list without an extra period and that also demonstrates how to search for a file match. Hope this helps:

<pre><code>find . -type f -name "extr*" -exec echo `pwd`/{} \; | sed "s|\./||"
</code></pre>

blocks|key|1489886|text|这对我很有效。但它没有按字母顺序列出。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1489887|find+"$(pwd)"+-maxdepth+1|code-block|syntax|javascript|1489888|此命令按字母顺序列出，也列出隐藏文件。|1489889|ls+-d+-1+"$PWD/".*;+ls+-d+-1+"$PWD/"*;|1489890|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This worked for me. But it didn't list in alphabetical order.

<pre><code>find "$(pwd)" -maxdepth 1
</code></pre>

This command lists alphabetically as well as lists hidden files too.

<pre><code>ls -d -1 "$PWD/".*; ls -d -1 "$PWD/"*;
</code></pre>

blocks|key|1704964|text|stat|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1704965|单个文件的绝对路径：|1704966|stat+-c+%25n+"$PWD"/foo/bar|code-block|syntax|javascript|1704967|entityMap^0|0|4|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

<h3><code>stat</code></h3>

Absolute path of a single file:

<pre><code>stat -c %n "$PWD"/foo/bar
</code></pre>

blocks|key|1705053|text|你可能想试试这个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705054|for+name+in+/home/ken/foo/bar/*
do
++++echo+$name
done|code-block|syntax|javascript|1705055|您可以使用for循环和echo获得abs路径，而无需使用find。|offset|length|style|CODE|1705056|entityMap^0|0|0|5|3|B|4|S|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

You might want to try this.

<pre class="lang-sh prettyprint-override"><code>for name in /home/ken/foo/bar/*
do
 echo $name
done
</code></pre>

You can get abs path using <code>for</code> loop and <code>echo</code> simply without <code>find</code>.

blocks|key|1490195|text|如果路径中包含空格，那么大多数建议的方法都会产生不能直接在其他终端命令中使用的路径。理想情况下，结果会预先加上斜杠。这对我在macOS上很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1490196|find+/+-iname+"*SEARCH+TERM+spaces+are+okay*"+-print+2>&1++%7C+grep+-v+denied+%7Cgrep+-v+permitted+%7Csed+-E+'s/\+/\\+/g'|code-block|syntax|javascript|1490197|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Most if not all of the suggested methods result in paths that cannot be used directly in some other terminal command if the path contains spaces. Ideally the results will have slashes prepended.
This works for me on macOS:

<pre><code>find / -iname "*SEARCH TERM spaces are okay*" -print 2&gt;&amp;1 | grep -v denied |grep -v permitted |sed -E 's/\ /\\ /g'
</code></pre>

blocks|key|1705466|text|递归查找jar文件并打印绝对路径|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705467|`ls+-R+%7Cgrep+"\.jar$"+%7C+xargs+readlink+-f`+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++|code-block|syntax|javascript|1705468|/opt/tool/dev/maven_repo/com/oracle/ojdbc/ojdbc8-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/ons-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/oraclepki-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/osdt_cert-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/osdt_core-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/simplefan-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/ucp-19.3.0.0.jar|1705469|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|D|7|M|8|@]|9|@]|A|$E|F]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

find jar file recursely and print absolute path
<pre><code>`ls -R |grep &quot;\.jar$&quot; | xargs readlink -f` 
</code></pre>
<pre class="lang-sh prettyprint-override"><code>/opt/tool/dev/maven_repo/com/oracle/ojdbc/ojdbc8-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/ons-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/oraclepki-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/osdt_cert-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/osdt_core-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/simplefan-19.3.0.0.jar
/opt/tool/dev/maven_repo/com/oracle/ojdbc/ucp-19.3.0.0.jar

</code></pre>

blocks|key|1705159|text|这将给出规范路径(将解析符号链接)：realpath+FILENAME|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1705160|如果您想要指向符号链接本身的规范路径，那么：realpath+-s+FILENAME|1705161|entityMap^0|I|H|0|M|K|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

This will give the canonical path (will resolve symlinks): <code>realpath FILENAME</code>

If you want canonical path to the symlink itself, then: <code>realpath -s FILENAME</code>

blocks|key|1705317|text|在Linux中，可以通过多种方式列出递归文件。在这里，我分享了一个线性脚本，用于清除/var/log/目录中所有文件(仅文件)的日志，第二个检查最近哪个日志文件已经输入。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1705318|首先：|1705319|find+/var/log/+-type+f++#listing+file+recursively+|code-block|syntax|javascript|1705320|第二：|1705321|for+i+in+$(find+$PWD+-type+f)+;+do+cat+/dev/null+>+"$i"+;+done+#empty+files+recursively+|1705322|第三种用途：|1705323|ls+-ltr+$(find+/var/log/+-type+f+)+#+listing+file+used+in+recent|1705324|注意:对于目录位置，您也可以传递$PWD而不是/var/log。|1705325|entityMap^0|16|9|0|0|0|0|0|0|0|G|4|N|8|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|15|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|W|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|X|$]]

Recursive files can be listed by many ways in Linux. Here I am sharing one liner script to clear all logs of files(only files) from <code>/var/log/</code> directory and second check recently which logs file has made an entry.
First:
<pre><code>find /var/log/ -type f #listing file recursively 
</code></pre>
Second:
<pre><code>for i in $(find $PWD -type f) ; do cat /dev/null &gt; &quot;$i&quot; ; done #empty files recursively 
</code></pre>
Third use:
<pre><code>ls -ltr $(find /var/log/ -type f ) # listing file used in recent
</code></pre>
Note: for directory location you can also pass <code>$PWD</code> instead of <code>/var/log</code>.

blocks|key|1705380|text|如果没有符号链接，可以尝试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705381|tree+-iFL+1+[DIR]|code-block|syntax|javascript|1705382|-i使树状打印文件名在每一行，而不是树状结构。|offset|length|style|CODE|1705383|-f让树打印出每个文件的完整路径。|1705384|-L+1避免了树的递归。|1705385|entityMap^0|0|0|0|2|0|0|2|0|0|4|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@$I|Y|J|Z|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

If you don't have symbolic links, you could try
<pre class="lang-sh prettyprint-override"><code>tree -iFL 1 [DIR]
</code></pre>
<code>-i</code> makes tree print filenames in each line, without the tree structure.
<code>-f</code> makes tree print the full path of each file.
<code>-L 1</code> avoids tree from recursion.

blocks|key|1705528|text|如果您想要在函数中运行良好的动态解决方案，则此方法效果最好|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1705529|lfp+()
{
++ls+-1+$1+%7C+xargs+-I{}+echo+$(realpath+$1)/{}
}|code-block|syntax|javascript|1705530|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works best if you want a dynamic solution that works well in a function
<pre><code>lfp ()
{
 ls -1 $1 | xargs -I{} echo $(realpath $1)/{}
}

</code></pre>

blocks|key|1704334|text|find+/+-print将执行此操作|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1704335|entityMap^0|0|D|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>find / -print</code> will do this

blocks|key|1489491|text|ls+-1+%7C+awk++-vpath=$PWD/+'{print+path$1}'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1489492|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>ls -1 | awk -vpath=$PWD/ '{print path$1}'
</code></pre>

I am writing a shell script that takes file paths as input.

For this reason, I need to generate recursive file listings with full paths. For example, the file <code>bar</code> has the path:

<pre><code>/home/ken/foo/bar
</code></pre>

but, as far as I can see, both <code>ls</code> and <code>find</code> only give relative path listings:

<pre><code>./foo/bar (from the folder ken)
</code></pre>

It seems like an obvious requirement, but I can't see anything in the <code>find</code> or <code>ls</code> man pages.

How can I generate a list of files in the shell including their absolute paths?

How can I generate a list of files with their absolute path in Linux?

日志文件

Linux

我正在编写一个将文件路径作为输入的shell脚本。出于这个原因，我需要生成带有完整路径的递归文件清单。例如，文件bar的路径为：/home/ken/foo/bar但是，据我所知，ls和find都只给出了相对路径列表：./foo/bar   (from the folder ken)这似乎是一个显而易见的要求，但我在find或ls手册页中看不到任何东西。如何在shell中生成包含绝对路径的文件列表？

问如何在Linux中使用文件的绝对路径生成文件列表？
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