“铁锈”一书calls the ref
keyword "legacy"。因为我想遵循隐含的建议来避免ref
,我该如何在下面的玩具示例中做到这一点呢?你也可以在playground上找到代码。
struct OwnBox(i32);
impl OwnBox {
fn ref_mut(&mut self) -> &mut i32 {
match *self {
OwnBox(ref mut i) => i,
}
// This doesn't work. -- Even not, if the signature of the signature of the function is
// adapted to take an explcit lifetime 'a and use it here like `&'a mut i`.
// match *self {
// OwnBox(mut i) => &mut i,
// }
// This doesn't work
// match self {
// &mut OwnBox(mut i) => &mut i,
// }
}
}
https://stackoverflow.com/questions/55130932
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