在[:http_payload.index("\r\n\r\n")+2]
中":“和"+2”是什么意思?在.split("/")[1]
中"("/")“和"1”是什么意思
def get_http_headers(http_payload):
try:
# split the headers off if it is HTTP traffic
headers_raw = http_payload[:http_payload.index("\r\n\r\n")+2]
# break out the headers
headers = dict(re.findall(r"(?P<name>.*?): (? P<value>.*?)\r\n", headers_raw))
except:
return None
return headers
def extract_image(headers, http_payload):
image = None
image_type = None
try:
if "image" in headers["Content-Type"]:
# grab the image type and image body
image_type = headers["Content-Type"].split("/")[1]
image = http_payload[http_payload.index("\r\n\r\n")+4:]
except:
pass
except:
return None, None
return image, image_type
发布于 2019-04-01 02:36:01
http_payload[:http_payload.index("\r\n\r\n")+2]
slices字符串http_payload
,以便只保留字符串的头部,直到第一次出现"\r\n\r\n“和第一个"\r\n”。字符串的.index()
方法将返回该模式在字符串中首次出现的索引。
示例:
test = "abcdefg"
# slicing:
print(test[1:3]) # will output 'bc'
# index:
print(test.index('bc')) # will output 1 (index of start of substring 'bc')
# either start or end (or both) of the slice can be left out, so the following is equivalent:
print(test[:2] == test[0:2]) # will output True
.split("/")[1]
将以"/“字符拆分一个字符串,并返回一个列表,从中可以访问索引为1的项。有关示例,请参阅以下代码:
test = "/this/is/a/path"
print(test.split("/")) # will output ["this", "is", "a", "path"]
print(test.split("/")[0]) # will output "is" since element of index 1 of the resulting list is accessed.
https://stackoverflow.com/questions/55442464
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