如何在嵌套数组中找到一个值，然后返回该父数组？
如何在嵌套数组中找到一个值，然后返回该父数组？
提问于 2019-04-09 01:44:48
我从Google地图API返回一个嵌套数组。我要做的是在数组中找到一个特定的类型。我使用json_decode将结果从JSON转换为PHP。下面是返回的响应：
Array
(
[results] => Array
(
[0] => Array
(
[address_components] => Array
(
[0] => Array
(
[long_name] => 78210
[short_name] => 78210
[types] => Array
(
[0] => postal_code
)
)
[1] => Array
(
[long_name] => San Antonio
[short_name] => San Antonio
[types] => Array
(
[0] => locality
[1] => political
)
)
[2] => Array
(
[long_name] => Bexar County
[short_name] => Bexar County
[types] => Array
(
[0] => administrative_area_level_2
[1] => political
)
)
[3] => Array
(
[long_name] => Texas
[short_name] => TX
[types] => Array
(
[0] => administrative_area_level_1
[1] => political
)
)
[4] => Array
(
[long_name] => United States
[short_name] => US
[types] => Array
(
[0] => country
[1] => political
)
)
)
[formatted_address] => San Antonio, TX 78210, USA
[geometry] => Array
(
[bounds] => Array
(
[northeast] => Array
(
[lat] => 29.418426
[lng] => -98.422923
)
[southwest] => Array
(
[lat] => 29.374093
[lng] => -98.499778
)
)
[location] => Array
(
[lat] => 29.3979578
[lng] => -98.4677851
)
[location_type] => APPROXIMATE
[viewport] => Array
(
[northeast] => Array
(
[lat] => 29.418426
[lng] => -98.422923
)
[southwest] => Array
(
[lat] => 29.374093
[lng] => -98.499778
)
)
)
[place_id] => ChIJy9U5Yzj2XIYRRhV9xWIghyU
[types] => Array
(
[0] => postal_code
)
)
)
[status] => OK
)我需要做的是找到某个类型并返回该long_name或short_name。我希望这是有意义的。
所以基本上，如果类型= political，那么返回整个数组，这样我就可以访问long_name和short_name。
我尝试使用array_search，但没有得到任何结果。
任何和所有的帮助是感激的！
回答 2
Stack Overflow用户
回答已采纳
发布于 2019-04-09 01:51:10
这将返回找到的第一个数组：
foreach($array['results'][0]['address_components'] as $v) {
if(is_array($v['types']) && in_array('political', $v['types'])) {
$result = $v;
break;
}
}如果您想要多个，则使用$result[] = $v;并删除break。
Stack Overflow用户
发布于 2019-04-09 02:06:29
您可以使用array_map函数完成此操作
$arr = array(
0 => array(
'long_name' => 'Bexar County',
'short_name' => 'Bexar County',
'types' => array(
0 => 'administrative_area_level_2',
1 => 'political'
)
)
);
$findType = 'political';
$result = array_map(function($v) use ($findType){
if(in_array($findType, $v['types']))
return $v;
}, $arr);结果：
Array
(
[0] => Array
(
[long_name] => Bexar County
[short_name] => Bexar County
[types] => Array
(
[0] => administrative_area_level_2
[1] => political
)
)
)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55578981
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