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使用fn:随机数生成器多次生成随机数
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Stack Overflow用户
提问于 2019-04-24 22:41:14
回答 1查看 709关注 0票数 2

我尝试编写一个简单的函数,以便在每次调用它时为我提供一个随机字母,但我很难将我的想法与函数式编程方法的概念结合起来。在此过程中提供一些帮助,我们将不胜感激!我的代码看起来像这样:

代码语言:javascript
复制
<xd:doc>
        <xd:desc>Provides one random letter, if the type is provided it returns a letter of thet type</xd:desc>
        <xd:param name="type">The type of letter to return, one of (A,a,B,b)</xd:param>
    </xd:doc>
    <xsl:function name="gdpr:randomLetter" as="xs:string">
        <xsl:param name="type" as="xs:string"></xsl:param>
        <xsl:choose>
            <xsl:when test="$type = 'A'">
                <xsl:variable name="randomNumber" select="random-number-generator()['next']?permute(1 to 7)[1]"/>
                <xsl:variable name="letters" select="('A','O','U','E','I','Y','Q')"/>
                <xsl:value-of select="$letters[$randomNumber]"/>
            </xsl:when>
            <xsl:when test="$type = 'a'">
                <xsl:variable name="randomNumber" select="random-number-generator()['next']?permute(1 to 7)[1]"/>
                <xsl:variable name="letters" select="('a','o','u','e','i','y','q')"/>
                <xsl:value-of select="$letters[$randomNumber]"/>
            </xsl:when>
            <xsl:when test="$type = 'B'">
                <xsl:variable name="randomNumber" select="random-number-generator()['next']?permute(1 to 19)[1]"/>
                <xsl:variable name="letters" select="('W','R','T','P','S','D','F','G','H','J','K','L','M','N','B','V','C','X','Z')"/>
                <xsl:value-of select="$letters[$randomNumber]"/>
            </xsl:when>
            <xsl:when test="$type = 'b'">
                <xsl:variable name="randomNumber" select="random-number-generator()['next']?permute(1 to 19)[1]"/>
                <xsl:variable name="letters" select="('w','r','t','p','s','d','f','g','h','j','k','l','m','n','b','v','c','x','z')"/>
                <xsl:value-of select="$letters[$randomNumber]"/>
            </xsl:when>
            <xsl:otherwise>
                <xsl:variable name="randomNumber" select="random-number-generator()['next']?permute(1 to 52)[1]"/>
                <xsl:variable name="letters" select="('A','O','U','E','I','Y','Q','a','o','u','e','i','y','q','w','r','t','p','s','d','f','g','h','j','k','l','m','n','b','v','c','x','z','W','R','T','P','S','D','F','G','H','J','K','L','M','N','B','V','C','X','Z')"/>
                <xsl:value-of select="$letters[$randomNumber]"/>
            </xsl:otherwise>
        </xsl:choose>

    </xsl:function>
EN

回答 1

Stack Overflow用户

发布于 2019-04-25 03:37:40

在XSLT3的上下文中,我认为为需要的每个节点都有一个“新的”random-number-generator的一种方法是定义一个累加器:

代码语言:javascript
复制
<xsl:accumulator name="rng" as="map(xs:string, item())" initial-value="random-number-generator(current-dateTime())">
    <xsl:accumulator-rule match="foo[@type]" select="$value?next()"/>
</xsl:accumulator>

因此,您可以将函数实现为

代码语言:javascript
复制
<xsl:function name="gdpr:randomLetter" as="item()*">
    <xsl:param name="type" as="xs:string"/>
    <xsl:param name="rng" as="map(xs:string, item())"/>
    <xsl:choose>
        <xsl:when test="$type = 'A'">
            <xsl:variable name="randomNumber" select="$rng?permute(1 to 7)[1]"/>
            <xsl:variable name="letters" select="('A','O','U','E','I','Y','Q')"/>
            <xsl:sequence select="$letters[$randomNumber]"/>
        </xsl:when>
        <xsl:when test="$type = 'a'">
            <xsl:variable name="randomNumber" select="$rng?permute(1 to 7)[1]"/>
            <xsl:variable name="letters" select="('a','o','u','e','i','y','q')"/>
            <xsl:sequence select="$letters[$randomNumber]"/>
        </xsl:when>
        <xsl:when test="$type = 'B'">
            <xsl:variable name="randomNumber" select="$rng?permute(1 to 19)[1]"/>
            <xsl:variable name="letters" select="('W','R','T','P','S','D','F','G','H','J','K','L','M','N','B','V','C','X','Z')"/>
            <xsl:sequence select="$letters[$randomNumber]"/>
        </xsl:when>
        <xsl:when test="$type = 'b'">
            <xsl:variable name="randomNumber" select="$rng?permute(1 to 19)[1]"/>
            <xsl:variable name="letters" select="('w','r','t','p','s','d','f','g','h','j','k','l','m','n','b','v','c','x','z')"/>
            <xsl:sequence select="$letters[$randomNumber]"/>
        </xsl:when>
        <xsl:otherwise>
            <xsl:variable name="randomNumber" select="$rng?permute(1 to 52)[1]"/>
            <xsl:variable name="letters" select="('A','O','U','E','I','Y','Q','a','o','u','e','i','y','q','w','r','t','p','s','d','f','g','h','j','k','l','m','n','b','v','c','x','z','W','R','T','P','S','D','F','G','H','J','K','L','M','N','B','V','C','X','Z')"/>
            <xsl:sequence select="$letters[$randomNumber]"/>
        </xsl:otherwise>
    </xsl:choose>        
</xsl:function>

然后用例如

代码语言:javascript
复制
<xsl:template match="foo[@type]">
    <xsl:copy>
        <xsl:value-of select="gdpr:randomLetter(@type, accumulator-before('rng'))"/>   
    </xsl:copy>
</xsl:template>

并确保您使用

代码语言:javascript
复制
<xsl:mode on-no-match="shallow-copy" use-accumulators="rng"/>
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/55832760

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