如何从async-await返回rejected？
如何从async-await返回rejected？
提问于 2019-04-28 08:43:03
当fetch请求失败时，我想返回rejected。如何拒绝异步等待？
class FetchUrl {
static async getJson(api) {
try {
const response = await fetch(api);
if (response.ok) {
const questions = await response.json();
return questions;
}
} catch (error) {
throw new Error("Request Failed!");
}
}
}
FetchUrl.getJson(this.api).then((resolved) => {
console.log(resolved)
// this sampe of code is executing even fetch is rejected.. what can i do
to avoid it?
}, rejected => {
console.log(rejected)
})
}回答 1
Stack Overflow用户
发布于 2019-04-28 08:54:42
According to jQuery docs您应该使用类似于(这主要取自jQuery文档)的符号：
$.getJSON( this.api)
.done(function( json ) {
console.log( "JSON Data: " + json.users[ 3 ].name );
})
.fail(function( jqxhr, textStatus, error ) {
var err = textStatus + ", " + error;
console.log( "Request Failed: " + err );
});页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55886072
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