blocks|key|3942188|text|我猜我们可以使用下面这样的表达式分别捕获两个所需的vars：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3942189|.%2B'(.%2B?)'\s%2B?[%2B\-*]%2B\s%2B([a-z]%2B).%2B|code-block|syntax|javascript|3942190|我们当然可以简化这个表达式，但我不确定我们可能有其他输入。|3942191|Java|3942192|import+java.util.regex.Matcher;
import+java.util.regex.Pattern;

final+String+regex+=+".%2B'(.%2B?)'\\s%2B?[%2B\\-*]%2B\\s%2B([a-z]%2B).%2B";
final+String+string+=+"eval('enterData.style.pixelTop='+%2B+y);\n"
+++++%2B+"eval('enterData.style.pixelTop='+%2B+x);";
final+String+subst+=+"$1$2;";

final+Pattern+pattern+=+Pattern.compile(regex,+Pattern.MULTILINE);
final+Matcher+matcher+=+pattern.matcher(string);

//+The+substituted+value+will+be+contained+in+the+result+variable
final+String+result+=+matcher.replaceAll(subst);

System.out.println(result);|3942193|测试|3942194|​|3942195|const+regex+=+/.%2B'(.%2B?)'\s%2B?[%2B\-*]%2B\s%2B([a-z]%2B).%2B/gm;
const+str+=+`eval('enterData.style.pixelTop='+%2B+y);
eval('enterData.style.pixelTop='+%2B+x);`;
const+subst+=+`$1$2;`;

//+The+substituted+value+will+be+contained+in+the+result+variable
const+result+=+str.replace(regex,+subst);

console.log(result);|3942196|3942197|Demo|3942198|RegEx|3942199|如果这个表达式不需要，可以在regex101.com中修改/更改。|3942200|RegEx电路|3942201|jex.im可视化正则表达式：|3942202|3942203|📷|atomic|3942204|3942205|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/2vSadI/1/|1|2|https://jex.im/regulex/#!flags=&re=%5E(a%7Cb)*?$|3|IMAGE|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/6a3a5adb4854a9e070dd137154716595.png|imageAlt^0|P|4|0|0|0|0|0|0|0|0|0|0|4|0|0|0|E|C|1|0|0|0|6|2|0|0|0|1|3|0|0^^$0|@$1|2|3|4|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1W|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1X|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1Y|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|1Z|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|20|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|21|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|22|8|@]|D|@]|E|$I|J]]|$1|W|3|T|5|6|7|23|8|@]|D|@]|E|$]]|$1|X|3|Y|5|6|7|24|8|@]|D|@$9|25|A|26|1|27]]|E|$]]|$1|Z|3|10|5|6|7|28|8|@]|D|@]|E|$]]|$1|11|3|12|5|6|7|29|8|@]|D|@$9|2A|A|2B|1|2C]]|E|$]]|$1|13|3|14|5|6|7|2D|8|@]|D|@]|E|$]]|$1|15|3|16|5|6|7|2E|8|@]|D|@$9|2F|A|2G|1|2H]]|E|$]]|$1|17|3|T|5|6|7|2I|8|@]|D|@]|E|$]]|$1|18|3|19|5|1A|7|2J|8|@]|D|@$9|2K|A|2L|1|2M]]|E|$]]|$1|1B|3|T|5|6|7|2N|8|@]|D|@]|E|$]]|$1|1C|3|-4|5|6|7|2O|8|@]|D|@]|E|$]]]|1D|$1E|$5|1F|1G|1H|E|$1I|1J]]|1K|$5|1F|1G|1H|E|$1I|1J]]|1L|$5|1F|1G|1H|E|$1I|1M]]|1N|$5|1O|1G|1P|E|$1Q|1R|1S|-4]]]]

<p>I'm guessing that we could capture both desired <code>vars</code> separately with an expression such as: </p>

<pre><code>.+'(.+?)'\s+?[+\-*]+\s+([a-z]+).+
</code></pre>

<p>We can surely simplify this expression, but I was not sure about other inputs that we might have. </p>

<h3>Java</h3>

<pre><code>import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = ".+'(.+?)'\\s+?[+\\-*]+\\s+([a-z]+).+";
final String string = "eval('enterData.style.pixelTop=' + y);\n"
     + "eval('enterData.style.pixelTop=' + x);";
final String subst = "$1$2;";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);

// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);

System.out.println(result);
</code></pre>

<h3>Test</h3>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const regex = /.+'(.+?)'\s+?[+\-*]+\s+([a-z]+).+/gm;
const str = `eval('enterData.style.pixelTop=' + y);
eval('enterData.style.pixelTop=' + x);`;
const subst = `$1$2;`;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

console.log(result);</code></pre>
</div>
</div>
</p>

<h3><a href="https://regex101.com/r/2vSadI/1/" rel="nofollow noreferrer">Demo</a></h3>

<h3>RegEx</h3>

<p>If this expression wasn't desired, it can be modified/changed in <a href="https://regex101.com/r/2vSadI/1/" rel="nofollow noreferrer">regex101.com</a>.</p>

<h3>RegEx Circuit</h3>

<p><a href="https://jex.im/regulex/#!flags=&amp;re=%5E(a%7Cb)*%3F%24" rel="nofollow noreferrer">jex.im</a> visualizes regular expressions:</p>

<p><a href="https://i.stack.imgur.com/eSr5L.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/eSr5L.png" alt="enter image description here"></a></p>


blocks|key|3942263|text|我对Javascript一无所知，但这就是我所看到的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3942264|您需要使用:?对'字符进行转义，并将它们放入不匹配的组中|offset|length|style|CODE|3942265|Regex:+eval$((?:\')(.*)(?:\').*)$
Replace:+$1|code-block|syntax|javascript|3942266|查看用于构建正则表达式原型的regex101。|3942267|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/^0|0|5|2|8|1|0|0|E|8|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]|$D|10|E|11|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@$D|14|E|15|1|16]]|A|$]]|$1|O|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

<p>I know nothing about Javascript, but this is what I see. </p>

<p>You need to escape your <code>'</code> characters and to put them in non-matching groups using <code>:?</code></p>

<pre><code>Regex: eval$((?:\')(.*)(?:\').*)$
Replace: $1
</code></pre>

<p>Check out <a href="https://regex101.com/" rel="nofollow noreferrer">regex101</a> for prototyping regular expressions.</p>


<p>I have tons of html files with expression like this:</p>

<pre><code>eval('enterData.style.pixelTop=' + y);
</code></pre>

<p>and I want to eliminate the eval expression and just execute the code, in other words change it to:</p>

<pre><code>enterData.style.pixelTop =  y;
</code></pre>

<p>Can anybody help me with this. Im breaking my head trying to get a solution but i only know how to eliminate the eval with:</p>

<pre><code>Regex: eval$'(.*)'$
Replace: $1
</code></pre>

<p>Im using java for regex. </p>


RegEx for replacing a JavaScript pattern

Java

我有大量的html文件，它们的表达式是这样的：eval('enterData.style.pixelTop=' + y);我想删除eval表达式，只执行代码，换句话说，将其更改为：enterData.style.pixelTop =  y;有没有人能帮我。我正在试图找到一个解决方案，但我只知道如何用以下方法消除评估：R...

问用于替换JavaScript模式的RegEx
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