这里,_also
是可选的,如何拆分字符串使_also
成为可选的?
>>> aa="may_be_this.is_the_string"
>>> aa.split('this.')[1]
'is_the_string'
>>>
>>> aa="may_be_this_also.is_the_string"
>>> aa.split('this[_also]*.')[1] # something like this, to make _also as optional substring.
https://stackoverflow.com/questions/56549634
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