使用LastFM应用程序接口获取数据时,我无法显示搜索到的艺术家的顶级曲目。该api返回一个对象toptracks。我想从api数据中获取每个顶级曲目的详细信息。
我不确定我是否在正确的轨道上。如果我做错了什么,能不能有人看一下,让我知道?
来自api的示例数据:
{
"toptracks": {
"track": [{
"name": "Best I Ever Had",
"playcount": "3723918",
"listeners": "1086968",
"mbid": "00bde944-7562-446f-ad0f-3d4bdc86b69f",
"url": "https://www.last.fm/music/Drake/_/Best+I+Ever+Had",
"streamable": "0",
"artist": {
"name": "Drake",
"mbid": "b49b81cc-d5b7-4bdd-aadb-385df8de69a6",
},
"@attr": {
"rank": "1"
}
},
{
"name": "Forever",
"playcount": "1713492",
"listeners": "668998",
"url": "https://www.last.fm/music/Drake/_/Forever",
"streamable": "0",
"artist": {
"name": "Drake",
"mbid": "b49b81cc-d5b7-4bdd-aadb-385df8de69a6",
},
"@attr": {
"rank": "2"
}
}
}
function renderTracks(trackArray) {
function createHTML(track){
return `<h1>${track.name}</h1>
<h2>${track.artist[0]}</h2>
<h3>${toptracks[1].rank}</h3>
<h3>${track.playcount}</h3>`;
};
trackHTML = trackArray.map(createHTML);
return trackHTML.join("");
};
var searchString = $(".search-bar").val().toLowerCase();
var urlEncodedSearchString = encodeURIComponent(searchString);
const url = "lastFMwebsite"
axios.get(url + urlEncodedSearchString).then(function(response) {
// createHTML.push(response.data.track);
// $(".tracks-container").innerHTML = renderTracks(response.data.track);
// comented out old code above
createHTML.push(response.toptracks.track);
$(".tracks-container").innerHTML = renderTracks(response.toptracks.track);
})
https://stackoverflow.com/questions/56782175
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