问在PHP中如何将从一个函数的表中获取数据传递给另一个函数？

function gettabledata()

{

    $data = array();

    $query = mysql_query("SELECT * FROM tab2");

    $row = mysql_fetch_assoc($query);

     //Here I am unable to get that how can I pass the fetched data in row 

    //  variable to anywhere this function called.

 //  After update:

     return $row;

}

if(isset($_POST['action']))

{

       $gettab = createtable();//calling the function gettabledata

       //Here I want to get the all data from that table

     // After doing Update:

      foreach($gettab as $row){

        echo $row['name'];

        echo $row['phone'];

     }

}

Warning: Illegal string offset 'name' in E:\xampp\htdocs\practive\csvtest.php on line 29

Notice: Uninitialized string offset: 0 in E:\xampp\htdocs\practive\csvtest.php on line 29

Warning: Illegal string offset 'phone' in E:\xampp\htdocs\practive\csvtest.php on line 30

Notice: Uninitialized string offset: 0 in E:\xampp\htdocs\practive\csvtest.php on line 30

Warning: Illegal string offset 'name' in E:\xampp\htdocs\practive\csvtest.php on line 29

0

Warning: Illegal string offset 'phone' in E:\xampp\htdocs\practive\csvtest.php on line 30 `

Array ( [name] => [phone] => 0 )