问python smtplib 获取debug信息？

想通过PY自动发送邮件，并获取发送成功/失败信息。

不过网上介绍的很多方法都不成功。

下面是尝试过的方法：

方法一：

from_addr = 'sender'

password = 'pass'

to_addr = 'receive_mail '

smtp_server = 'smtp.qq.com'

msg = MIMEText('send by python','plain','utf-8')

msg['From'] = Header(from_addr)

msg['To'] = Header(to_addr)

msg['Subject'] = Header('python test')

try:

server = smtplib.SMTP_SSL(smtp_server)

server.set_debuglevel(1)

smtplib.stderr=open("debug.txt","write") #redirect debug to file

server.connect(smtp_server,465)

server.login(from_addr, password)

server.sendmail(from_addr, to_addr, msg.as_string())

server.quit()

except Exception as e:

方法二：

# Find an available file descriptor

t = tempfile.TemporaryFile()

available_fd = t.fileno()

t.close()

# now make a copy of stderr

os.dup2(2,available_fd)

# Now create a new tempfile and make Python's stderr go to that file

t = tempfile.TemporaryFile()

os.dup2(t.fileno(),2)

from_addr = 'sender'

password = 'pass'

to_addr = 'receive_mail '

smtp_server = 'smtp.qq.com'

msg = MIMEText('send by python','plain','utf-8')

msg['From'] = Header(from_addr)

msg['To'] = Header(to_addr)

msg['Subject'] = Header('python test')

try:

server = smtplib.SMTP_SSL(smtp_server)

server.set_debuglevel(1)

server.connect(smtp_server,465)

server.login(from_addr, password)

server.sendmail(from_addr, to_addr, msg.as_string())

# Grab the stderr from the temp file

sys.stderr.flush()

t.flush()

t.seek(0)

stderr_output = t.read()

t.close()

# Put back stderr

os.dup2(available_fd,2)

os.close(available_fd)

# Finally, demonstrate that we have the output:

print("STDERR:")

count = 0

for line in stderr_output.decode('utf-8').split("\n"):

count += 1

print("{:3} {}".format(count,line))

server.quit()

except Exception as e: