blocks|key|1098910|text|在常见Linux发行版的更高版本上，您可以使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098911|date+-d+@1267619929|code-block|syntax|javascript|1098912|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

On later versions of common Linux distributions you can use:

<pre><code>date -d @1267619929
</code></pre>

blocks|key|1099009|text|date+-r+<number>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1099010|适用于我的Mac和OS/X。|unstyled|1099011|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>date -r &lt;number&gt;
</code></pre>

works for me on Mac&nbsp;OS&nbsp;X.

blocks|key|1098960|text|您可以使用GNU+date，例如，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098961|$+sec=1267619929
$+date+-d+"UTC+1970-01-01+$sec+secs"|code-block|syntax|javascript|1098962|或|1098963|$+date+-ud+@1267619929|1098964|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can use GNU date, for example,

<pre><code>$ sec=1267619929
$ date -d "UTC 1970-01-01 $sec secs"
</code></pre>

or 

<pre><code>$ date -ud @1267619929
</code></pre>

blocks|key|1098837|text|您可以使用这个简单的awk脚本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098838|#!/bin/gawk+-f+++
{+print+strftime("%25c",+$0);+}|code-block|syntax|javascript|1098839|示例用法：|1098840|$+echo+'1098181096'+%7C+./a.awk+
Tue+19+Oct+2004+03:18:16+AM+PDT
$|1098841|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can use this simple awk script:

<pre><code>#!/bin/gawk -f 
{ print strftime("%c", $0); }
</code></pre>

Sample usage:

<pre><code>$ echo '1098181096' | ./a.awk 
Tue 19 Oct 2004 03:18:16 AM PDT
$
</code></pre>

blocks|key|1099566|text|您可以从时间戳中获得格式化日期，如下所示|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099567|date+%2B'%25Y-%25m-%25d+%25H:%25M:%25S'+-d+"@timestamp"|code-block|syntax|javascript|1099568|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can get formatted date from timestamp like this

<pre><code>date +'%Y-%m-%d %H:%M:%S' -d "@timestamp"
</code></pre>

blocks|key|1314697|text|我使用这个跨平台的一行程序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1314698|date+-d+@1267619929+2>/dev/null+%7C%7C+date+-r+1267619929|code-block|syntax|javascript|1314699|它应该可以在macOS和流行的Linux发行版的现代版本中工作。|1314700|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I use this cross-platform one-liner:
<pre><code>date -d @1267619929 2&gt;/dev/null || date -r 1267619929
</code></pre>
It should work both in macOS and modern versions of popular Linux distributions.

blocks|key|1099113|text|在转换日志文件或监视它们时，我使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099114|tail+-f+<log+file>+%7C+gawk+\
'{+printf+strftime("%25c",+$1);+for+(i=2;+i<NF;+i%2B%2B)+printf+$i+"+";+print+$NF+}'|code-block|syntax|javascript|1099115|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use this when converting log files or monitoring them:

<pre><code>tail -f &lt;log file&gt; | gawk \
'{ printf strftime("%c", $1); for (i=2; i&lt;NF; i++) printf $i " "; print $NF }'
</code></pre>

blocks|key|1314454|text|在OSX或BSD中，有一个等效的-r标志，它显然需要一个unix时间戳。下面是一个运行date四次的示例:一次是第一个date，用来显示它是什么；一次是用%25s转换成unix时间戳，最后一次是用-r将%25s提供的内容转换回一个字符串。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1314455|$++date;+date+%2B%25s;+date+-r+`date+%2B%25s`
Tue+Oct+24+16:27:42+CDT+2017
1508880462
Tue+Oct+24+16:27:42+CDT+2017|code-block|syntax|javascript|1314456|至少，看起来在我的机器上是有效的。|1314457|$+uname+-a
Darwin+XXX-XXXXXXXX+16.7.0+Darwin+Kernel+Version+16.7.0:+Thu+Jun+15+17:36:27+PDT+2017;+root:xnu-3789.70.16~2/RELEASE_X86_64+x86_64|1314458|entityMap^0|G|2|25|2|2O|2|2R|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

In OSX, or BSD, there's an equivalent <code>-r</code> flag which apparently takes a unix timestamp. Here's an example that runs date four times: once for the first date, to show what it is; one for the conversion to unix timestamp with <code>%s</code>, and finally, one which, with <code>-r</code>, converts what <code>%s</code> provides back to a string.

<pre><code>$ date; date +%s; date -r `date +%s`
Tue Oct 24 16:27:42 CDT 2017
1508880462
Tue Oct 24 16:27:42 CDT 2017
</code></pre>

At least, seems to work on my machine.

<pre><code>$ uname -a
Darwin XXX-XXXXXXXX 16.7.0 Darwin Kernel Version 16.7.0: Thu Jun 15 17:36:27 PDT 2017; root:xnu-3789.70.16~2/RELEASE_X86_64 x86_64
</code></pre>

blocks|key|1313684|text|我自己写了一个脚本来做这件事：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1313685|#!/bin/bash
LANG=C
if+[+-z+"$1"+];+then
++++if+[++"$(tty)"+=+"not+a+tty"+];+then
++++++++++++p=`cat`;
++++else
++++++++++++echo+"No+timestamp+given."
++++++++++++exit
++++fi
else
++++p=$1
fi
echo+$p+%7C+gawk+'{+print+strftime("%25c",+$0);+}'|code-block|syntax|javascript|1313686|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I have written a script that does this myself:

<pre><code>#!/bin/bash
LANG=C
if [ -z "$1" ]; then
 if [ "$(tty)" = "not a tty" ]; then
 p=`cat`;
 else
 echo "No timestamp given."
 exit
 fi
else
 p=$1
fi
echo $p | gawk '{ print strftime("%c", $0); }'
</code></pre>

blocks|key|1314314|text|在这个答案中，我复制了Dennis+Williamson的答案，并对其进行了略微修改，以便在通过管道将包含多个时间戳的列传送到脚本时大大提高速度。例如，在我的机器上使用xargs+-n1将1000个时间戳通过管道传输到原始脚本需要6.929秒，而使用这个修改后的版本需要0.027秒：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1314315|#!/bin/bash
LANG=C
if+[[+-z+"$1"+]]
then
++++if+[[+-p+/dev/stdin+]]++++#+input+from+a+pipe
++++then
++++++++cat+-+%7C+gawk+'{+print+strftime("%25c",+$1);+}'
++++else
++++++++echo+"No+timestamp+given."+>&2
++++++++exit
++++fi
else
++++date+-d+@$1+%2B%25c
fi|code-block|syntax|javascript|1314316|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In this answer I copy Dennis Williamson's answer and modify it slightly to allow a vast speed increase when piping a column of many timestamps to the script. For example, piping 1000 timestamps to the original script with xargs -n1 on my machine took 6.929s as opposed to 0.027s with this modified version:

<pre><code>#!/bin/bash
LANG=C
if [[ -z "$1" ]]
then
 if [[ -p /dev/stdin ]] # input from a pipe
 then
 cat - | gawk '{ print strftime("%c", $1); }'
 else
 echo "No timestamp given." &gt;&amp;2
 exit
 fi
else
 date -d @$1 +%c
fi
</code></pre>

blocks|key|1314633|text|虽然不是纯bash，但以下脚本将使用perl将字符串中长度为13的时间戳转换为本地时区中的等效日期|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1314634|timestamp_to_date.sh|1314635|#!/usr/bin/env+bash
IT=$(cat+/dev/stdin)
re='(.*)([0-9]{13})(.*)'
while+[[+$IT+=~+$re+]];+do
++TIMESTAMP=${BASH_REMATCH[2]}
++AS_DATE=$(echo+"$TIMESTAMP"+%7C+perl+-pe+'s/([\d]{10})([\d]{3})/localtime+$1/eg;')
++IT="${IT/$TIMESTAMP/$AS_DATE}"++++
done
echo+"$IT"|code-block|syntax|javascript|1314636|输入|1314637|{"timestamp":"1573121629939","level":"DEBUG","thread":"http-nio-15372-exec-3","logger":"org.springframework.web.servlet.mvc.method.annotation.RequestResponseBodyMethodProcessor"}|1314638|输出|1314639|$+cat+input+%7C+timestamp_to_date.sh

{"timestamp":"Thu+Nov++7+06:13:49+2019","level":"DEBUG","thread":"http-nio-15372-exec-3","logger":"org.springframework.web.servlet.mvc.method.annotation.RequestResponseBodyMethodProcessor"}|1314640|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

While not pure bash, the following script will convert timestamps of length 13 in a string to their equivalent date in your local timezone using perl

<h1>timestamp_to_date.sh</h1>

<pre><code>#!/usr/bin/env bash
IT=$(cat /dev/stdin)
re='(.*)([0-9]{13})(.*)'
while [[ $IT =~ $re ]]; do
 TIMESTAMP=${BASH_REMATCH[2]}
 AS_DATE=$(echo "$TIMESTAMP" | perl -pe 's/([\d]{10})([\d]{3})/localtime $1/eg;')
 IT="${IT/$TIMESTAMP/$AS_DATE}" 
done
echo "$IT"
</code></pre>

<h3>input</h3>

<pre><code>{"timestamp":"1573121629939","level":"DEBUG","thread":"http-nio-15372-exec-3","logger":"org.springframework.web.servlet.mvc.method.annotation.RequestResponseBodyMethodProcessor"}
</code></pre>

<h3>output</h3>

<pre><code>$ cat input | timestamp_to_date.sh

{"timestamp":"Thu Nov 7 06:13:49 2019","level":"DEBUG","thread":"http-nio-15372-exec-3","logger":"org.springframework.web.servlet.mvc.method.annotation.RequestResponseBodyMethodProcessor"}
</code></pre>

blocks|key|1314769|text|我必须在我的bash历史中内联转换时间戳，以便对我有意义。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1314770|也许下面这段来自How+do+I+replace+a+substring+by+the+output+of+a+shell+command+with+sed,+awk+or+such?的回答对其他读者来说也会很有趣。要获得原始sed内联代码的荣誉，请访问@Gabriel。|offset|length|1314771|cat+~/.bash_history+%7C+sed+"s/%5E#$[0-9]\%2B$$/echo+-n+'#';+date+-u+--d+@\1+'\%2B\%25Y-\%25m-\%25d+\%25T'/e"+%7C+less|code-block|syntax|javascript|1314772|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/27823959/how-do-i-replace-a-substring-by-the-output-of-a-shell-command-with-sed-awk-or-s/27823994^0|0|8|2C|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@$D|U|E|V|1|W]]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

I had to convert timestamps inline in my bash history to make sense to me.
Maybe the following coming from an answer to <a href="https://stackoverflow.com/questions/27823959/how-do-i-replace-a-substring-by-the-output-of-a-shell-command-with-sed-awk-or-s/27823994">How do I replace a substring by the output of a shell command with sed, awk or such?</a> could be interesting to other readers too.
Kudos for the original sed inline code go to @Gabriel.
<pre><code>cat ~/.bash_history | sed &quot;s/^#$[0-9]\+$$/echo -n '#'; date -u --d @\1 '\+\%Y-\%m-\%d \%T'/e&quot; | less
</code></pre>

blocks|key|1314847|text|如果您希望一次格式化多个时间戳，我已经编写了一个名为datefmt的C+util，它在文本流中格式化时间戳：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1314848|假设我们有一些包含unix时间戳的日志：|1314849|$+cat+logs.txt

EVENTS++1638499687+++blahblah+log1
EVENTS++1638499717+++blahblah+log2|code-block|syntax|javascript|1314850|我们可以将此日志通过管道传输到datefmt中，以将这些时间戳转换为人类可读的日期：|1314851|$+<logs.txt+datefmt

EVENTS++2021-12-02+18:48+++blahblah+log1
EVENTS++2021-12-02+18:48+++blahblah+log2|1314852|当然，您也可以自定义格式：|1314853|$+<logs.txt+datefmt+"DATE:'%25m-%25d+%25R'"

EVENTS++DATE:'12-02+18:48'+++blahblah+log1
EVENTS++DATE:'12-02+18:48'+++blahblah+log2|1314854|我已经用NixOS打包了这个包，希望它很快就能在其他发行版中使用，但现在您需要下载tarball并使用make构建它|style|CODE|1314855|entityMap|0|LINK|mutability|MUTABLE|url|https://jb55.com/datefmt^0|Q|7|0|0|0|0|0|0|0|0|1F|4|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@$A|15|B|16|1|17]]|C|$]]|$1|D|3|E|5|6|7|18|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|19|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|1A|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|1B|8|@]|9|@]|C|$I|J]]|$1|O|3|P|5|6|7|1C|8|@]|9|@]|C|$]]|$1|Q|3|R|5|H|7|1D|8|@]|9|@]|C|$I|J]]|$1|S|3|T|5|6|7|1E|8|@$A|1F|B|1G|U|V]]|9|@]|C|$]]|$1|W|3|-4|5|6|7|1H|8|@]|9|@]|C|$]]]|X|$Y|$5|Z|10|11|C|$12|13]]]]

If you're looking to format many timestamps all at once, I've written a C util called <a href="https://jb55.com/datefmt" rel="nofollow noreferrer">datefmt</a> that formats timestamps in a text stream:
Let’s say we have some logs that contain unix timestamps:
<pre><code>$ cat logs.txt

EVENTS 1638499687 blahblah log1
EVENTS 1638499717 blahblah log2
</code></pre>
We can pipe this log into datefmt to convert these timestamps into human-readable dates:
<pre><code>$ &lt;logs.txt datefmt

EVENTS 2021-12-02 18:48 blahblah log1
EVENTS 2021-12-02 18:48 blahblah log2
</code></pre>
Of course you can customize the format as well:
<pre><code>$ &lt;logs.txt datefmt &quot;DATE:'%m-%d %R'&quot;

EVENTS DATE:'12-02 18:48' blahblah log1
EVENTS DATE:'12-02 18:48' blahblah log2
</code></pre>
I've packaged this in NixOS, hopefully it will trickle out to other distros soon, but for now you will need to download the tarball and build it with <code>make</code>

blocks|key|1313705|text|在PHP中|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1313706|$unix_time+=+1256571985;

echo+date("Y-m-d+H:i:s",$unix_time)|code-block|syntax|javascript|1313707|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In PHP

<pre><code>$unix_time = 1256571985;

echo date("Y-m-d H:i:s",$unix_time)
</code></pre>

I need a shell command or script that converts a Unix timestamp to a date. The input can come either from the first parameter or from stdin, allowing for the following usage patterns:

<pre><code>ts2date 1267619929
</code></pre>

and

<pre><code>echo 1267619929 | ts2date
</code></pre>

Both commands should output "Wed Mar 3 13:38:49 2010".

How to convert timestamps to dates in Bash?

日志文件

Kernel

Linux

Unix

我需要一个shell命令或脚本来将Unix时间戳转换为日期。输入可以来自第一个参数，也可以来自stdin，允许以下使用模式：ts2date 1267619929和echo 1267619929 | ts2date两个命令都应该输出"Wed Mar 3 13:38:49 2010“。

问如何在Bash中将时间戳转换为日期？
EN

回答 14

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问如何在Bash中将时间戳转换为日期？EN

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问如何在Bash中将时间戳转换为日期？
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