blocks|key|1428235|text|import+random
random.shuffle(array)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1428236|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import random
random.shuffle(array)
</code></pre>

blocks|key|1428240|text|import+random
random.shuffle(array)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1428241|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|1428533|text|另一种方法是使用sklearn|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1428534|from+sklearn.utils+import+shuffle
X=[1,2,3]
y+=+['one',+'two',+'three']
X,+y+=+shuffle(X,+y,+random_state=0)
print(X)
print(y)|code-block|syntax|javascript|1428535|输出：|1428536|[2,+1,+3]
['two',+'one',+'three']|1428537|优点:您可以同时随机多个数组，而不会中断映射。'random_state‘可以控制可重现行为的混洗。|1428538|entityMap|0|LINK|mutability|MUTABLE|url|http://scikit-learn.org/stable/modules/generated/sklearn.utils.shuffle.html^0|8|7|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|C|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

Alternative way to do this using <a href="http://scikit-learn.org/stable/modules/generated/sklearn.utils.shuffle.html" rel="noreferrer">sklearn</a>

<pre><code>from sklearn.utils import shuffle
X=[1,2,3]
y = ['one', 'two', 'three']
X, y = shuffle(X, y, random_state=0)
print(X)
print(y)
</code></pre>

Output:

<pre><code>[2, 1, 3]
['two', 'one', 'three']
</code></pre>

Advantage: You can random multiple arrays simultaneously without disrupting the mapping. And 'random_state' can control the shuffling for reproducible behavior.

blocks|key|1643160|text|其他答案是最简单的，但是random.shuffle方法实际上并没有返回任何东西，这有点麻烦-它只是对给定的列表进行排序。如果你想链式调用，或者只想在一行中声明一个随机数组，你可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1643161|++++import+random
++++def+my_shuffle(array):
++++++++random.shuffle(array)
++++++++return+array|code-block|syntax|javascript|1643162|然后你就可以像这样做了：|1643163|++++for+suit+in+my_shuffle(['hearts',+'spades',+'clubs',+'diamonds']):|1643164|entityMap^0|C|E|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

The other answers are the easiest, however it's a bit annoying that the <code>random.shuffle</code> method doesn't actually return anything - it just sorts the given list. If you want to chain calls or just be able to declare a shuffled array in one line you can do:

<pre><code> import random
 def my_shuffle(array):
 random.shuffle(array)
 return array
</code></pre>

Then you can do lines like:

<pre><code> for suit in my_shuffle(['hearts', 'spades', 'clubs', 'diamonds']):
</code></pre>

blocks|key|1428463|text|如果您需要一个新的数组，可以使用sample|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1428464|import+random
new_array+=+random.sample(+array,+len(array)+)|code-block|syntax|javascript|1428465|entityMap^0|G|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Just in case you want a new array you can use <code>sample</code>:

<pre><code>import random
new_array = random.sample( array, len(array) )
</code></pre>

blocks|key|1428333|text|在处理常规Python列表时，random.shuffle()将按照前面的答案执行此工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1428334|但当涉及到ndarray(numpy.array)时，random.shuffle似乎打破了最初的ndarray。下面是一个示例：|1428335|import+random
import+numpy+as+np
import+numpy.random

a+=+np.array([1,2,3,4,5,6])
a.shape+=+(3,2)
print+a
random.shuffle(a)+#+a+will+definitely+be+destroyed
print+a|code-block|syntax|javascript|1428336|只需使用：np.random.shuffle(a)|1428337|与random.shuffle一样，np.random.shuffle也就地打乱了数组。|1428338|entityMap^0|F|G|0|5|7|D|B|R|E|1D|7|0|0|5|K|0|1|E|I|H|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|R|$]]

When dealing with regular Python lists, <code>random.shuffle()</code> will do the job just as the previous answers show.

But when it come to <code>ndarray</code>(<code>numpy.array</code>), <code>random.shuffle</code> seems to break the original <code>ndarray</code>. Here is an example:

<pre><code>import random
import numpy as np
import numpy.random

a = np.array([1,2,3,4,5,6])
a.shape = (3,2)
print a
random.shuffle(a) # a will definitely be destroyed
print a
</code></pre>

Just use: <code>np.random.shuffle(a)</code>

Like <code>random.shuffle</code>, <code>np.random.shuffle</code> shuffles the array in-place.

blocks|key|1643465|text|您可以使用随机键对数组进行排序|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1643466|sorted(array,+key+=+lambda+x:+random.random())|code-block|syntax|javascript|1643467|键只被读取一次，因此在排序期间比较项仍然有效。|1643468|但是看起来random.shuffle(array)会更快，因为它是用C语言编写的|offset|length|style|CODE|1643469|这是O(log(N))+btw|1643470|entityMap^0|0|0|0|5|L|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@$K|W|L|X|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

You can sort your array with random key
<pre><code>sorted(array, key = lambda x: random.random())
</code></pre>
key only be read once so comparing item during sort still efficient.
but look like <code>random.shuffle(array)</code> will be faster since it written in C
this is O(log(N)) btw

blocks|key|1643246|text|除了前面的回答之外，我还想介绍另一个函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1643247|numpy.random.shuffle和random.shuffle执行就地混洗。但是，如果您希望返回一个随机数组，则可以使用numpy.random.permutation函数。|offset|length|style|CODE|1643248|entityMap^0|0|0|K|L|E|1S|O|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]|$D|N|E|O|F|G]|$D|P|E|Q|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|I|$]]

In addition to the previous replies, I would like to introduce another function.

<code>numpy.random.shuffle</code> as well as <code>random.shuffle</code> perform in-place shuffling. However, if you want to return a shuffled array <code>numpy.random.permutation</code> is the function to use.

blocks|key|1643288|text|我不知道我用过random.shuffle()，但它给我返回了'None‘，所以我写了这篇文章，可能对某些人有帮助|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1643289|def+shuffle(arr):
++++for+n+in+range(len(arr)+-+1):
++++++++rnd+=+random.randint(0,+(len(arr)+-+1))
++++++++val1+=+arr[rnd]
++++++++val2+=+arr[rnd+-+1]

++++++++arr[rnd+-+1]+=+val1
++++++++arr[rnd]+=+val2

++++return+arr|code-block|syntax|javascript|1643290|entityMap^0|7|G|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I don't know I used <code>random.shuffle()</code> but it return 'None' to me, so I wrote this, might helpful to someone

<pre><code>def shuffle(arr):
 for n in range(len(arr) - 1):
 rnd = random.randint(0, (len(arr) - 1))
 val1 = arr[rnd]
 val2 = arr[rnd - 1]

 arr[rnd - 1] = val1
 arr[rnd] = val2

 return arr
</code></pre>

blocks|key|1428597|text|#+arr+=+numpy+array+to+shuffle

def+shuffle(arr):
++++a+=+numpy.arange(len(arr))
++++b+=+numpy.empty(1)
++++for+i+in+range(len(arr)):
++++++++sel+=+numpy.random.random_integers(0,+high=len(a)-1,+size=1)
++++++++b+=+numpy.append(b,+a[sel])
++++++++a+=+numpy.delete(a,+sel)
++++b+=+b[1:].astype(int)
++++return+arr[b]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1428598|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code># arr = numpy array to shuffle

def shuffle(arr):
 a = numpy.arange(len(arr))
 b = numpy.empty(1)
 for i in range(len(arr)):
 sel = numpy.random.random_integers(0, high=len(a)-1, size=1)
 b = numpy.append(b, a[sel])
 a = numpy.delete(a, sel)
 b = b[1:].astype(int)
 return arr[b]
</code></pre>

blocks|key|1643588|text|请注意，不应在多维数组上使用random.shuffle()，因为它会导致重复。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1643589|假设您想要沿数组的第一维对其进行置乱，我们可以创建以下测试示例，|1643590|import+numpy+as+np
x+=+np.zeros((10,+2,+3))

for+i+in+range(10):
+++x[i,+...]+=+i*np.ones((2,3))|code-block|syntax|javascript|1643591|因此，沿着第一个轴，第i个元素对应于一个2x3矩阵，其中所有元素都等于i。|1643592|如果我们对多维数组使用正确的混洗函数，即np.random.shuffle(x)，则数组将根据需要沿着第一个轴进行混洗。但是，使用random.shuffle(x)会导致重复。你可以通过在混洗后运行len(np.unique(x))来检查这一点，在使用np.random.shuffle()时，它会给你10+(正如预期的那样)，但在使用random.shuffle()时，它只会给你5左右。|1643593|entityMap^0|E|G|0|0|0|0|K|K|1T|H|2R|H|3I|J|4O|G|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|R|$]]

Be aware that <code>random.shuffle()</code> should not be used on multi-dimensional arrays as it causes repetitions. 

Imagine you want to shuffle an array along its first dimension, we can create the following test example,

<pre><code>import numpy as np
x = np.zeros((10, 2, 3))

for i in range(10):
 x[i, ...] = i*np.ones((2,3))
</code></pre>

so that along the first axis, the i-th element corresponds to a 2x3 matrix where all the elements are equal to i.

If we use the correct shuffle function for multi-dimensional arrays, i.e. <code>np.random.shuffle(x)</code>, the array will be shuffled along the first axis as desired. However, using <code>random.shuffle(x)</code> will cause repetitions. You can check this by running <code>len(np.unique(x))</code> after shuffling which gives you 10 (as expected) with <code>np.random.shuffle()</code> but only around 5 when using <code>random.shuffle()</code>.

What's the easiest way to shuffle an array with python?

Shuffle an array with python, randomize array item order with python

Python

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