blocks|key|815451|text|SELECT+TIMEDIFF('2007-12-31+10:02:00','2007-12-30+12:01:01');
--+result:+22:00:59,+the+difference+in+HH:MM:SS+format


SELECT+TIMESTAMPDIFF(SECOND,'2007-12-30+12:01:01','2007-12-31+10:02:00');+
--+result:+79259++the+difference+in+seconds|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|815452|因此，您可以使用TIMESTAMPDIFF来实现您的目的。|unstyled|offset|length|style|CODE|815453|entityMap^0|0|8|D|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>SELECT TIMEDIFF('2007-12-31 10:02:00','2007-12-30 12:01:01');
-- result: 22:00:59, the difference in HH:MM:SS format


SELECT TIMESTAMPDIFF(SECOND,'2007-12-30 12:01:01','2007-12-31 10:02:00'); 
-- result: 79259 the difference in seconds
</code></pre>

So, you can use <code>TIMESTAMPDIFF</code> for your purpose.

blocks|key|815333|text|如果您正在处理日期列(或者可以将它们转换为日期列)，请尝试DATEDIFF()，然后乘以24小时，60分钟，60秒(因为DATEDIFF返回diff+in+days)。来自MySQL：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815334|http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html|offset|length|815335|例如：|815336|mysql>+SELECT+DATEDIFF('2007-12-31+23:59:59','2007-12-30+00:00:00')+*+24*60*60|code-block|syntax|javascript|815337|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|1V|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|U|8|@]|9|@$D|V|E|W|1|X]]|A|$]]|$1|F|3|G|5|6|7|Y|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|Z|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|C]]]]

If you are working with DATE columns (or can cast them as date columns), try DATEDIFF() and then multiply by 24 hours, 60 min, 60 secs (since DATEDIFF returns diff in days). From MySQL:

<a href="http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html" rel="noreferrer">http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html</a>

for example:

<pre><code>mysql&gt; SELECT DATEDIFF('2007-12-31 23:59:59','2007-12-30 00:00:00') * 24*60*60
</code></pre>

blocks|key|815555|text|SELECT+TIMESTAMPDIFF(HOUR,NOW(),'2013-05-15+10:23:23')
+++calculates+difference+in+hour.(for+days-->+you+have+to+define+day+replacing+hour
SELECT+DATEDIFF('2012-2-2','2012-2-1')

SELECT+TO_DAYS+('2012-2-2')-TO_DAYS('2012-2-1')|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|815556|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>SELECT TIMESTAMPDIFF(HOUR,NOW(),'2013-05-15 10:23:23')
 calculates difference in hour.(for days--&gt; you have to define day replacing hour
SELECT DATEDIFF('2012-2-2','2012-2-1')

SELECT TO_DAYS ('2012-2-2')-TO_DAYS('2012-2-1')
</code></pre>

blocks|key|1030299|text|select+
unix_timestamp('2007-12-30+00:00:00')+-+
unix_timestamp('2007-11-30+00:00:00');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1030300|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>select 
unix_timestamp('2007-12-30 00:00:00') - 
unix_timestamp('2007-11-30 00:00:00');
</code></pre>

blocks|key|1030560|text|SELECT+TIMESTAMPDIFF(SECOND,'2018-01-19+14:17:15','2018-01-20+14:17:15');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1030561|第二种方法|unstyled|1030562|SELECT+(+DATEDIFF('1993-02-20','1993-02-19')*(+24*60*60)+)AS+'seccond';|offset|length|style|CODE|1030563|CURRENT_TIME()+--this+will+return+current+Date
DATEDIFF('','')+--this+function+will+return++DAYS+and+in+1+day+there+are+24hh+60mm+60sec|1030564|entityMap^0|0|0|0|1Z|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$B|C]]|$1|O|3|-4|5|F|7|W|8|@]|9|@]|A|$]]]|P|$]]

<pre><code>SELECT TIMESTAMPDIFF(SECOND,'2018-01-19 14:17:15','2018-01-20 14:17:15');
</code></pre>

Second approach 

<code>SELECT ( DATEDIFF('1993-02-20','1993-02-19')*( 24*60*60) )AS 'seccond';</code> 

<pre><code>CURRENT_TIME() --this will return current Date
DATEDIFF('','') --this function will return DAYS and in 1 day there are 24hh 60mm 60sec
</code></pre>

blocks|key|815401|text|或者，您可以使用TIMEDIFF函数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815402|mysql>+SELECT+TIMEDIFF('2000:01:01+00:00:00',+'2000:01:01+00:00:00.000001');
'-00:00:00.000001'
mysql>+SELECT+TIMEDIFF('2008-12-31+23:59:59.000001'+,+'2008-12-30+01:01:01.000002');
+'46:58:57.999999'|code-block|syntax|javascript|815403|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Or, you could use TIMEDIFF function 

<pre><code>mysql&gt; SELECT TIMEDIFF('2000:01:01 00:00:00', '2000:01:01 00:00:00.000001');
'-00:00:00.000001'
mysql&gt; SELECT TIMEDIFF('2008-12-31 23:59:59.000001' , '2008-12-30 01:01:01.000002');
 '46:58:57.999999'
</code></pre>

blocks|key|815543|text|此函数获取两个日期之间的差值，并以日期格式yyyy-mm-dd显示。您需要做的就是执行下面的代码，然后使用函数。执行之后，您可以像这样使用它|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815544|SELECT+datedifference(date1,+date2)
FROM+....
.
.
.
.


DELIMITER+$$

CREATE+FUNCTION+datedifference(date1+DATE,+date2+DATE)+RETURNS+DATE
NO+SQL

BEGIN
++++DECLARE+dif+DATE;
++++IF+DATEDIFF(date1,+DATE(CONCAT(YEAR(date1),'-',+MONTH(date1),+'-',+DAY(date2))))+<+0++++THEN
++++++++++++++++SET+dif=DATE_FORMAT(
++++++++++++++++++++++++++++++++++++++++CONCAT(
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))DIV+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))%25+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++DATEDIFF(date1,+DATE(CONCAT(YEAR(date1),'-',+MONTH(DATE_SUB(date1,+INTERVAL+1+MONTH)),+'-',+DAY(date2))))),
++++++++++++++++++++++++++++++++++++++++'%25Y-%25m-%25d');
++++ELSEIF+DATEDIFF(date1,+DATE(CONCAT(YEAR(date1),'-',+MONTH(date1),+'-',+DAY(date2))))+<+DAY(LAST_DAY(DATE_SUB(date1,+INTERVAL+1+MONTH)))+THEN
++++++++++++++++SET+dif=DATE_FORMAT(
++++++++++++++++++++++++++++++++++++++++CONCAT(
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))DIV+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))%25+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++DATEDIFF(date1,+DATE(CONCAT(YEAR(date1),'-',+MONTH(date1),+'-',+DAY(date2))))),
++++++++++++++++++++++++++++++++++++++++'%25Y-%25m-%25d');
++++ELSE
++++++++++++++++SET+dif=DATE_FORMAT(
++++++++++++++++++++++++++++++++++++++++CONCAT(
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))DIV+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++PERIOD_DIFF(date_format(date1,+'%25y%25m'),date_format(date2,+'%25y%25m'))%25+12+,+
++++++++++++++++++++++++++++++++++++++++++++'-',
++++++++++++++++++++++++++++++++++++++++++++DATEDIFF(date1,+DATE(CONCAT(YEAR(date1),'-',+MONTH(date1),+'-',+DAY(date2))))),
++++++++++++++++++++++++++++++++++++++++'%25Y-%25m-%25d');
++++END+IF;

RETURN+dif;
END+$$
DELIMITER;|code-block|syntax|javascript|815545|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This function takes the difference between two dates and shows it in a date format yyyy-mm-dd. All you need is to execute the code below and then use the function. After executing you can use it like this 

<pre><code>SELECT datedifference(date1, date2)
FROM ....
.
.
.
.


DELIMITER $$

CREATE FUNCTION datedifference(date1 DATE, date2 DATE) RETURNS DATE
NO SQL

BEGIN
 DECLARE dif DATE;
 IF DATEDIFF(date1, DATE(CONCAT(YEAR(date1),'-', MONTH(date1), '-', DAY(date2)))) &lt; 0 THEN
 SET dif=DATE_FORMAT(
 CONCAT(
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))DIV 12 , 
 '-',
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))% 12 , 
 '-',
 DATEDIFF(date1, DATE(CONCAT(YEAR(date1),'-', MONTH(DATE_SUB(date1, INTERVAL 1 MONTH)), '-', DAY(date2))))),
 '%Y-%m-%d');
 ELSEIF DATEDIFF(date1, DATE(CONCAT(YEAR(date1),'-', MONTH(date1), '-', DAY(date2)))) &lt; DAY(LAST_DAY(DATE_SUB(date1, INTERVAL 1 MONTH))) THEN
 SET dif=DATE_FORMAT(
 CONCAT(
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))DIV 12 , 
 '-',
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))% 12 , 
 '-',
 DATEDIFF(date1, DATE(CONCAT(YEAR(date1),'-', MONTH(date1), '-', DAY(date2))))),
 '%Y-%m-%d');
 ELSE
 SET dif=DATE_FORMAT(
 CONCAT(
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))DIV 12 , 
 '-',
 PERIOD_DIFF(date_format(date1, '%y%m'),date_format(date2, '%y%m'))% 12 , 
 '-',
 DATEDIFF(date1, DATE(CONCAT(YEAR(date1),'-', MONTH(date1), '-', DAY(date2))))),
 '%Y-%m-%d');
 END IF;

RETURN dif;
END $$
DELIMITER;
</code></pre>

blocks|key|815628|text|此代码以yyyy+MM+dd格式计算两个日期之间的差异。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815629|declare+@StartDate+datetime+
declare+@EndDate+datetime

declare+@years+int
declare+@months+int+
declare+@days+int

--NOTE:+date+of+birth+must+be+smaller+than+As+on+date,+
--else+it+could+produce+wrong+results
set+@StartDate+=+'2013-12-30'+--birthdate
set+@EndDate++=+Getdate()++++++++++++--current+datetime

--calculate+years
select+@years+=+datediff(year,@StartDate,@EndDate)

--calculate+months+if+it's+value+is+negative+then+it+
--indicates+after+__+months;+__+years+will+be+complete
--To+resolve+this,+we+have+taken+a+flag+@MonthOverflow...
declare+@monthOverflow+int
select+@monthOverflow+=+case+when+datediff(month,@StartDate,@EndDate)+-+
++(+datediff(year,@StartDate,@EndDate)+*+12)+<0+then+-1+else+1+end
--decrease+year+by+1+if+months+are+Overflowed
select+@Years+=+case+when+@monthOverflow+<+0+then+@years-1+else+@years+end
select+@months+=++datediff(month,@StartDate,@EndDate)+-+(@years+*+12)+

--as+we+do+for+month+overflow+criteria+for+days+and+hours+
--&+minutes+logic+will+followed+same+way
declare+@LastdayOfMonth+int
select+@LastdayOfMonth+=++datepart(d,DATEADD
++++(s,-1,DATEADD(mm,+DATEDIFF(m,0,@EndDate)%2B1,0)))

select+@days+=+case+when+@monthOverflow<0+and+
++++DAY(@StartDate)>+DAY(@EndDate)+
then+@LastdayOfMonth+%2B+
++(datepart(d,@EndDate)+-+datepart(d,@StartDate)+)+-+1++
++++++else+datepart(d,@EndDate)+-+datepart(d,@StartDate)+end+


select
+@Months=case+when+@days+<+0+or+DAY(@StartDate)>+DAY(@EndDate)+then+@Months-1+else+@Months+end

Declare+@lastdayAsOnDate+int;
set+@lastdayAsOnDate+=+datepart(d,DATEADD(s,-1,DATEADD(mm,+DATEDIFF(m,0,@EndDate),0)));
Declare+@lastdayBirthdate+int;
set+@lastdayBirthdate+=++datepart(d,DATEADD(s,-1,DATEADD(mm,+DATEDIFF(m,0,@StartDate)%2B1,0)));

if+(@Days+<+0)+
(
++++select+@Days+=+case+when(+@lastdayBirthdate+>+@lastdayAsOnDate)+then
++++++++@lastdayBirthdate+%2B+@Days
++++else
++++++++@lastdayAsOnDate+%2B+@Days
++++end
)
print++convert(varchar,@years)+++%2B+'+year(s),+++'++%2B
+++++++convert(varchar,@months)++%2B+'+month(s),+++'+%2B
+++++++convert(varchar,@days)++++%2B+'+day(s)+++'+++|code-block|syntax|javascript|815630|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This code calculate difference between two dates in yyyy MM dd format.

<pre><code>declare @StartDate datetime 
declare @EndDate datetime

declare @years int
declare @months int 
declare @days int

--NOTE: date of birth must be smaller than As on date, 
--else it could produce wrong results
set @StartDate = '2013-12-30' --birthdate
set @EndDate = Getdate() --current datetime

--calculate years
select @years = datediff(year,@StartDate,@EndDate)

--calculate months if it's value is negative then it 
--indicates after __ months; __ years will be complete
--To resolve this, we have taken a flag @MonthOverflow...
declare @monthOverflow int
select @monthOverflow = case when datediff(month,@StartDate,@EndDate) - 
 ( datediff(year,@StartDate,@EndDate) * 12) &lt;0 then -1 else 1 end
--decrease year by 1 if months are Overflowed
select @Years = case when @monthOverflow &lt; 0 then @years-1 else @years end
select @months = datediff(month,@StartDate,@EndDate) - (@years * 12) 

--as we do for month overflow criteria for days and hours 
--&amp; minutes logic will followed same way
declare @LastdayOfMonth int
select @LastdayOfMonth = datepart(d,DATEADD
 (s,-1,DATEADD(mm, DATEDIFF(m,0,@EndDate)+1,0)))

select @days = case when @monthOverflow&lt;0 and 
 DAY(@StartDate)&gt; DAY(@EndDate) 
then @LastdayOfMonth + 
 (datepart(d,@EndDate) - datepart(d,@StartDate) ) - 1 
 else datepart(d,@EndDate) - datepart(d,@StartDate) end 


select
 @Months=case when @days &lt; 0 or DAY(@StartDate)&gt; DAY(@EndDate) then @Months-1 else @Months end

Declare @lastdayAsOnDate int;
set @lastdayAsOnDate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@EndDate),0)));
Declare @lastdayBirthdate int;
set @lastdayBirthdate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@StartDate)+1,0)));

if (@Days &lt; 0) 
(
 select @Days = case when( @lastdayBirthdate &gt; @lastdayAsOnDate) then
 @lastdayBirthdate + @Days
 else
 @lastdayAsOnDate + @Days
 end
)
print convert(varchar,@years) + ' year(s), ' +
 convert(varchar,@months) + ' month(s), ' +
 convert(varchar,@days) + ' day(s) ' 
</code></pre>

blocks|key|815685|text|如果你有一个日期以字符串的形式存储在文本字段中，你可以实现下面的代码，它将获取过去每周，一个月或一年的天数列表，排序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815686|SELECT+*+FROM+`table`+WHERE+STR_TO_DATE(mydate,+'%25d/%25m/%25Y')+<+CURDATE()+-+INTERVAL+30+DAY+AND+STR_TO_DATE(date,+'%25d/%25m/%25Y')+>+CURDATE()+-+INTERVAL+60+DAY

//This+is+for+a+month

SELECT+*+FROM+`table`+WHERE+STR_TO_DATE(mydate,+'%25d/%25m/%25Y')+<+CURDATE()+-+INTERVAL+7+DAY+AND+STR_TO_DATE(date,+'%25d/%25m/%25Y')+>+CURDATE()+-+INTERVAL+14+DAY

//This+is+for+a+week+|code-block|syntax|javascript|815687|%25d%25m%25Y是您的日期格式|815688|此查询显示您在那里设置的天数之间的记录，如下所示:从最近7天开始，到最近14天开始，因此它将是您最近一周的记录，显示的概念与月份或年份相同。无论您在以下日期中提供的值是什么，例如:7天，因此其他值将是其14天的两倍。我们在这里所说的是获取过去14天的所有记录，以及过去7天的所有记录。这是一周记录，您可以将值更改为一个月或一年的30-60天。|815689|谢谢你，希望它能帮助一些人。|815690|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you've a date stored in text field as string you can implement this code it will fetch the list of past number of days a week, a month or a year sorting:

<pre><code>SELECT * FROM `table` WHERE STR_TO_DATE(mydate, '%d/%m/%Y') &lt; CURDATE() - INTERVAL 30 DAY AND STR_TO_DATE(date, '%d/%m/%Y') &gt; CURDATE() - INTERVAL 60 DAY

//This is for a month

SELECT * FROM `table` WHERE STR_TO_DATE(mydate, '%d/%m/%Y') &lt; CURDATE() - INTERVAL 7 DAY AND STR_TO_DATE(date, '%d/%m/%Y') &gt; CURDATE() - INTERVAL 14 DAY

//This is for a week 
</code></pre>

%d%m%Y is your date format

This query display the record between the days you set there like: Below from last 7 days and Above from last 14 days so it would be your last week record to be display same concept is for month or year. Whatever value you're providing in below date like: below from 7-days so the other value would be its double as 14 days. What we are saying here get all records above from last 14 days and below from last 7 days. This is a week record you can change value to 30-60 days for a month and also for a year.

Thank You Hope it will help someone.

blocks|key|1030394|text|您只需执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1030395|SELECT+(end_time+-+start_time)+FROM+t;+--+return+in+Millisecond
SELECT+(end_time+-+start_time)/1000+FROM+t;+--+return+in+Second|code-block|syntax|javascript|1030396|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You would simply do this:

<pre><code>SELECT (end_time - start_time) FROM t; -- return in Millisecond
SELECT (end_time - start_time)/1000 FROM t; -- return in Second
</code></pre>

blocks|key|815651|text|为什么不干脆|type|unstyled|depth|inlineStyleRanges|entityRanges|data|815652|从表中选择Sum(Date1+-+Date2)|815653|date1和date2是datetime|815654|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

Why not just 

Select Sum(Date1 - Date2) from table 

date1 and date2 are datetime

How to calculate the difference between two dates, in the format <code>YYYY-MM-DD hh: mm: ss</code> and to get the result in seconds or milliseconds?

Difference between two dates in MySQL

MySQL

如何计算两个日期之间的差值，格式为YYYY-MM-DD hh: mm: ss，并以秒或毫秒为单位得到结果？

问MySQL中两个日期之间的差异
EN

回答 11

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问MySQL中两个日期之间的差异
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