blocks|key|602568|text|尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|602569|grep+-n+"text+to+find"+file.ext+%7C+cut+-f1+-d:|code-block|syntax|javascript|602570|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try:

<pre><code>grep -n "text to find" file.ext | cut -f1 -d:
</code></pre>

blocks|key|602605|text|如果您对使用AWK持开放态度：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|602606|awk+'/textstring/+{print+FNR}'+textfile|code-block|syntax|javascript|602607|在本例中，FNR是行号。当您正在查看grep%7Ccut时，或者在任何时候需要获取grep输出并对其进行操作时，AWK都是一个很好的工具。|602608|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you're open to using AWK:

<pre><code>awk '/textstring/ {print FNR}' textfile
</code></pre>

In this case, FNR is the line number. AWK is a great tool when you're looking at grep|cut, or any time you're looking to take grep output and manipulate it.

blocks|key|817848|text|您将需要冒号之后的第二个字段，而不是第一个字段。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|817849|grep+-n+"text+to+find"+file.txt+%7C+cut+-f2+-d:|offset|length|style|CODE|817850|entityMap^0|0|0|19|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

You're going to want the second field after the colon, not the first.

<code>grep -n "text to find" file.txt | cut -f2 -d:</code>

blocks|key|602702|text|所有这些答案都需要grep生成整个匹配的行，然后通过管道将其传递给另一个程序。如果您的行很长，那么使用sed输出行号可能会更有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|602703|sed+-n+'/pattern/='+filename|code-block|syntax|javascript|602704|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

All of these answers require grep to generate the entire matching lines, then pipe it to another program. If your lines are very long, it might be more efficient to use just sed to output the line numbers:

<pre><code>sed -n '/pattern/=' filename
</code></pre>

blocks|key|602729|text|Bash版本|type|unstyled|depth|inlineStyleRanges|entityRanges|data|602730|++++lineno=$(grep+-n+"pattern"+filename)
++++lineno=${lineno%25%25:*}|code-block|syntax|javascript|602731|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Bash version

<pre><code> lineno=$(grep -n "pattern" filename)
 lineno=${lineno%%:*}
</code></pre>

blocks|key|817995|text|要计算匹配模式的行数，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|817996|grep+-n+"Pattern"+in_file.ext+%7C+wc+-l+|code-block|syntax|javascript|817997|提取匹配的模式|817998|sed+-n+'/pattern/p'+file.est|817999|显示匹配模式的行号|818000|grep+-n+"pattern"+file.ext+%7C+cut+-f1+-d:|818001|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

To count the number of lines matched the pattern:

<pre><code>grep -n "Pattern" in_file.ext | wc -l 
</code></pre>

To extract matched pattern

<pre><code>sed -n '/pattern/p' file.est
</code></pre>

To display line numbers on which pattern was matched

<pre><code>grep -n "pattern" file.ext | cut -f1 -d:
</code></pre>

blocks|key|602870|text|我建议使用sed和awk来获取行号，而不是使用grep获取整个匹配行，然后使用cut或其他工具将其从输出中删除。为了完整性，您还可以使用Perl：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|602871|perl+-nE+'/pattern/+&&+say+$.'+filename|code-block|syntax|javascript|602872|或者Ruby：|602873|ruby+-ne+'puts+$.+if+/pattern/'+filename|602874|entityMap^0|5|3|9|3|N|4|13|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

I recommend the answers with <code>sed</code> and <code>awk</code> for just getting the line number, rather than using <code>grep</code> to get the entire matching line and then removing that from the output with <code>cut</code> or another tool. For completeness, you can also use Perl:

<pre><code>perl -nE '/pattern/ &amp;&amp; say $.' filename
</code></pre>

or Ruby:

<pre><code>ruby -ne 'puts $. if /pattern/' filename
</code></pre>

I have a file that possibly contains bad formatting (in this case, the occurrence of the pattern <code>\\backslash</code>). I would like to use <code>grep</code> to return only the line numbers where this occurs (as in, the match was here, go to line # x and fix it).

However, there doesn't seem to be a way to print the line number (<code>grep -n</code>) and not the match or line itself.

I can use another regex to extract the line numbers, but I want to make sure grep cannot do it by itself. <code>grep -no</code> comes closest, I think, but still displays the match.

Use grep to report back only line numbers

Perl

我有一个可能包含错误格式的文件(在本例中，出现了模式\\backslash)。我想使用grep来只返回出现这种情况的行号(如在这里，匹配在这里，转到第#x行并修复它)。但是，似乎没有一种方法可以打印行号(grep -n)，而不是打印匹配或行本身。我可以使用另一个正则表达式来提取行号，但我希望确保grep不能自己完成。我...

问使用grep仅报告行号
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