最小和最大循环
最小和最大循环
提问于 2017-01-19 13:29:20
我正在为一个赋值编写代码，它希望我编写一个程序，要求用户输入他们想要输入的整数的数量，然后它接受每一个输入，同时测试这个值是最大值还是最小值。我的程序对除1以外的每个整数都运行得很好。当我输入int1时，即使输入的数字在技术上也是最小值，也只记录最大值，这是因为if语句导致循环在找到数字是max还是min时重复，在这种情况下，数字将始终是最大值，因此测试永远不会再次运行。我怎么才能解决这个问题呢？
#include <iostream>
using namespace std;
int main()
{
int input;
int tmp;
int counter = 1;
int max_num=0;
int min_num;
//prompt user for integer amount
cout << "How many integers would you like to enter? " << endl;
cin >> input;
cout<< "Please enter " << input << " integers." << endl;
tmp = input;
//loop for requested amount with a test for each input
while (counter <= tmp){
cin >> input;
//if smaller than previous number it is the minimum
if (input < min_num){
min_num = input;
counter++;
}
// if larger than previous number it becomes max number
else if (input > max_num){
max_num = input;
counter++;
}
//continue loop if number isn't bigger than max or smaller than min
else {
counter++;
}
}
//display the max and min
cout << "min: "<< min_num << endl;
cout << "max: " << max_num<< endl;;
return 0;
}Stack Overflow用户
回答已采纳
发布于 2017-01-19 14:09:25
int max_num = -1;
int min_num = -1
while (counter <= tmp){
cin >> input;
//if smaller than previous number it is the minimum
if (input < min_num || min_num == -1){
min_num = input;
//counter++; => This operation is carried out in every case. Why not just do it once?
}
// if larger than previous number it becomes max number
// Else statement not needed here, What if user inputs only one number. It will be both max and min
if (input > max_num){
max_num = input;
//counter++;
}
//continue loop if number isn't bigger than max or smaller than min
counter++;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/41734407
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