blocks|key|1586039|text|for(int+i=0;i<m;i%2B%2B)
++++for(int+j=0;j<n;j%2B%2B)
++++++++yourList.add(foosArray[i][j]);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1586040|我认为其他技巧是不必要的，因为不管怎样，他们都会使用这个解决方案。|unstyled|1586041|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>for(int i=0;i&lt;m;i++)
 for(int j=0;j&lt;n;j++)
 yourList.add(foosArray[i][j]);
</code></pre>

I think other tricks are unnecessary, because, anyway, they'll use this solution.

blocks|key|1586047|text|将其转换为列表的唯一方法是迭代数组，并在执行过程中构建列表，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1586048|ArrayList<Foo[]>+list+=+new+ArrayList<Foo[]>(foosArray.length);
for(Foo[]+foo:+foosArray){
++++list.add(foo);
}|code-block|syntax|javascript|1586049|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The only way to transform it to a list is to iterate through the array and build the list as you go, like this:

<pre><code>ArrayList&lt;Foo[]&gt; list = new ArrayList&lt;Foo[]&gt;(foosArray.length);
for(Foo[] foo: foosArray){
 list.add(foo);
}
</code></pre>

blocks|key|1800913|text|使用java8+"flatMap“就可以了。一种方法可能是跟随|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800914|List<Foo>+collection+=+Arrays.stream(array).flatMap(Arrays::stream).collect(Collectors.toList());|code-block|syntax|javascript|1800915|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use java8 "flatMap" to play around. One way could be following 

<pre><code>List&lt;Foo&gt; collection = Arrays.stream(array).flatMap(Arrays::stream).collect(Collectors.toList());
</code></pre>

blocks|key|1800909|text|另一种技术。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800910|//converting+2D+array+to+string
String+temp+=+Arrays.deepToString(fooArr).replaceAll("\\[",+"").replaceAll("\\]",+"");
List<String>+fooList+=+new+ArrayList<>(Arrays.asList(","));|code-block|syntax|javascript|1800911|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

another one technique. 

<pre><code>//converting 2D array to string
String temp = Arrays.deepToString(fooArr).replaceAll("\\[", "").replaceAll("\\]", "");
List&lt;String&gt; fooList = new ArrayList&lt;&gt;(Arrays.asList(","));
</code></pre>

blocks|key|1800917|text|ArrayList<Elelement[]>+allElelementList+=+new+ArrayList<>(allElelements.length);
++++allElelementList.addAll(Arrays.asList(allElelements));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1800918|allElelements是二维的|unstyled|1800919|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>ArrayList&lt;Elelement[]&gt; allElelementList = new ArrayList&lt;&gt;(allElelements.length);
 allElelementList.addAll(Arrays.asList(allElelements));
</code></pre>

allElelements is two-dimensional

blocks|key|1586064|text|让我们添加一些原始类型数组处理。但是你可以传递给参数任何对象。方法正确地将int处理为Object|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1586065|+public+<T,+E>+List<E>+twoDArrayToList(T+twoDArray)+{

+++if+(twoDArray+instanceof+int[][])
+++++return+Arrays.stream((int[][])twoDArray)
++++++++++++++++++.flatMapToInt(a->Arrays.stream(a))
++++++++++++++++++.mapToObj(i->(E)Integer.valueOf(i))
++++++++++++++++++.collect(Collectors.toList());

+++//…+processing+arrays+of+other+primitive+types+

+++if+(twoDArray+instanceof+Object[][])
++++++++return+Arrays.stream((E[][])twoDArray)
+++++++++++++++.flatMap(Arrays::stream)
+++++++++++++++.collect(Collectors.toList());

+++return+null;+//+better+to+throw+appropriate+exception+
++++++++++++++++//+if+parameter+is+not+two+dimensional+array
}|code-block|syntax|javascript|1586066|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Let's add some primitive type arrays processing. But you may pass to parameter any object. Method correctly process as int[][] as Object[][]:
<pre><code> public &lt;T, E&gt; List&lt;E&gt; twoDArrayToList(T twoDArray) {

 if (twoDArray instanceof int[][])
 return Arrays.stream((int[][])twoDArray)
 .flatMapToInt(a-&gt;Arrays.stream(a))
 .mapToObj(i-&gt;(E)Integer.valueOf(i))
 .collect(Collectors.toList());

 //… processing arrays of other primitive types 

 if (twoDArray instanceof Object[][])
 return Arrays.stream((E[][])twoDArray)
 .flatMap(Arrays::stream)
 .collect(Collectors.toList());

 return null; // better to throw appropriate exception 
 // if parameter is not two dimensional array
}
</code></pre>

blocks|key|1800930|text|例如。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800931|Integer[][]+a+=+{+{+1,+2,+3+},+{+4,+5,+6+},+{+9,+8,+9+},+};
++++++++
List<List<Integer>>+arr+=+Arrays.stream(a)
++++++++++++++++.map(Arrays::asList)
++++++++++++++++.collect(Collectors.toList());|code-block|syntax|javascript|1800932|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

E.g.
<pre><code>Integer[][] a = { { 1, 2, 3 }, { 4, 5, 6 }, { 9, 8, 9 }, };
 
List&lt;List&lt;Integer&gt;&gt; arr = Arrays.stream(a)
 .map(Arrays::asList)
 .collect(Collectors.toList());
</code></pre>

blocks|key|1586074|text|在Java8中，要从int[][]转换为List<Integer>，可以使用以下代码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1586075|List<Integer>+data+=+Arrays.stream(intervals)
++++++++++++++.flatMapToInt(Arrays::stream)
++++++++++++++.boxed()
++++++++++++++.collect(Collectors.toList());|code-block|syntax|javascript|1586076|entityMap^0|A|7|K|D|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

In Java 8 , to convert from <code>int[][]</code> to <code>List&lt;Integer&gt;</code>, you can use the below code :
<pre><code>List&lt;Integer&gt; data = Arrays.stream(intervals)
 .flatMapToInt(Arrays::stream)
 .boxed()
 .collect(Collectors.toList());
</code></pre>

blocks|key|1800946|text|List<Foo>+list+=++Arrays.stream(fooArray)
++++++.flatMap(e+->+Stream+::+of).collect(Collectors.toList());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1800947|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>List&lt;Foo&gt; list = Arrays.stream(fooArray)
 .flatMap(e -&gt; Stream :: of).collect(Collectors.toList());
</code></pre>

I have a<code>m X n</code> two dimensional array of an Object say <code>Foo</code>. So I have <code>Foo[][] foosArray</code>. What is the best way to convert this into a <code>List&lt;Foo&gt;</code> in Java?

Convert two dimensional array to List in java?

我有一个对象的m X n二维数组，比如Foo。所以我有Foo[][] foosArray。在java语言中，将其转换为List<Foo>的最佳方法是什么？

问在java中将二维数组转换为列表？
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