使用JsonBuilder的toPrettyString时的StackOverflowError
使用JsonBuilder的toPrettyString时的StackOverflowError
提问于 2019-07-02 20:04:38
我有以下代码。它接收Jenkins工作区中本地可用的文件名，读取文件，并尝试将其内容发送到端点。
对于service-configuration.json，这是可行的。然而，对于剩余的文件，它会失败，并显示一个StackOverflowError...
// Update Service configuration.
serviceJson = readJSON file: "service-configuration.json"
response = httpRequest validResponseCodes: "100:504", acceptType: "APPLICATION_JSON", contentType: "APPLICATION_JSON", customHeaders: [[name: 'Authorization', value: iamToken]], httpMode: "PUT", requestBody: new JsonBuilder(serviceJson).toPrettyString(), url: GlobalCatalog.service
if (response.status != 200) {
println "Failure: ${response.status} ${response.content}"
currentBuild.result = 'FAILURE'
error "Failed uploading Global Catalog entry."
}
// Update Plans and their Deployments configurations.
GlobalCatalog.plans.each { plan ->
planJson = readJSON file: "${plan.planName}-plan-configuration.json"
response = httpRequest validResponseCodes: "100:504", acceptType: "APPLICATION_JSON", contentType: "APPLICATION_JSON", customHeaders: [[name: 'Authorization', value: iamToken]], httpMode: "PUT", requestBody: new JsonBuilder(planJson).toPrettyString(), url: plan.url
if (response.status != 200) {
println "Failure: ${response.status} ${response.content}"
currentBuild.result = 'FAILURE'
error "Failed uploading Global Catalog entry."
} else {
plan.deployments.each { deployment ->
deploymentJson = readJSON file: "${plan.planName}-${deployment.region}-deployment-configuration.json"
response = httpRequest validResponseCodes: "100:504", acceptType: "APPLICATION_JSON", contentType: "APPLICATION_JSON", customHeaders: [[name: 'Authorization', value: iamToken]], httpMode: "PUT", requestBody: new JsonBuilder(deploymentJson).toPrettyString(), url: deployment.url
if (response.status != 200) {
println "Failure: ${response.status} ${response.content}"
currentBuild.result = 'FAILURE'
error "Failed uploading Global Catalog entry."
}
}
}
}StackOverflowError：
java.lang.StackOverflowError
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)
at groovy.json.JsonOutput.writeObject(JsonOutput.java:321)
at groovy.json.JsonOutput.writeMap(JsonOutput.java:458)编辑:如果我使用toString()，它可以工作--但是文件中各种语言字符串的编码不会被保留……
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-07-04 15:14:27
正如评论中所建议的那样，使用JsonOutput.prettyPrint(myProp)比使用new JsonBuilder(myProp).toPrettyString()要好得多，尽管我不确定为什么……
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原文链接：
https://stackoverflow.com/questions/56852072
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