blocks|key|919720|text|如果我没记错的话，这个问题需要“包含数字”，而不是“是数字”。所以：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919721|function+hasNumber(myString)+{
++return+/\d/.test(myString);
}|code-block|syntax|javascript|919722|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If I'm not mistaken, the question requires "contains number", not "is number". So:

<pre><code>function hasNumber(myString) {
 return /\d/.test(myString);
}
</code></pre>

blocks|key|703331|text|你可以使用javascript来做这件事。不需要Jquery或Regex|type|unstyled|depth|inlineStyleRanges|entityRanges|data|703332|function+isNumeric(n)+{
++return+!isNaN(parseFloat(n))+&&+isFinite(n);
}|code-block|syntax|javascript|703333|在实现时|703334|var+val+=+$('yourinputelement').val();
if(isNumeric(val))+{+alert('number');+}+
else+{+alert('not+number');+}|703335|更新:要检查字符串中是否包含数字，可以使用正则表达式|703336|var+matches+=+val.match(/\d%2B/g);
if+(matches+!=+null)+{
++++alert('number');
}|703337|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can do this using javascript. No need for Jquery or Regex

<pre><code>function isNumeric(n) {
 return !isNaN(parseFloat(n)) &amp;&amp; isFinite(n);
}
</code></pre>

While implementing

<pre><code>var val = $('yourinputelement').val();
if(isNumeric(val)) { alert('number'); } 
else { alert('not number'); }
</code></pre>

Update: To check if a string has numbers in them, you can use regular expressions to do that

<pre><code>var matches = val.match(/\d+/g);
if (matches != null) {
 alert('number');
}
</code></pre>

blocks|key|703341|text|function+validate(){++++
++++var+re+=+/%5E[A-Za-z]%2B$/;
++++if(re.test(document.getElementById("textboxID").value))
+++++++alert('Valid+Name.');
++++else
+++++++alert('Invalid+Name.');++++++
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|703342|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>function validate(){ 
 var re = /^[A-Za-z]+$/;
 if(re.test(document.getElementById("textboxID").value))
 alert('Valid Name.');
 else
 alert('Invalid Name.'); 
}
</code></pre>

blocks|key|703679|text|这就是你所需要的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|703680|++++++var+hasNumber+=+/\d/;+++
++++++hasNumber.test("ABC33SDF");++//true
++++++hasNumber.test("ABCSDF");++//false+|code-block|syntax|javascript|703681|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is what you need.
<pre><code> var hasNumber = /\d/; 
 hasNumber.test(&quot;ABC33SDF&quot;); //true
 hasNumber.test(&quot;ABCSDF&quot;); //false 
</code></pre>

blocks|key|919774|text|它无论如何都不是防弹的，但它对我的目的是有效的，也许它会帮助一些人。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919775|var+value+=+$('input').val();
+if(parseInt(value))+{
++console.log(value%2B"+is+a+number.");
+}
+else+{
++console.log(value%2B"+is+NaN.");
+}|code-block|syntax|javascript|919776|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It's not bulletproof by any means, but it worked for my purposes and maybe it will help someone.

<pre><code>var value = $('input').val();
 if(parseInt(value)) {
 console.log(value+" is a number.");
 }
 else {
 console.log(value+" is NaN.");
 }
</code></pre>

blocks|key|919885|text|测试是否有任何字符是一个数字，而不过度使用❓，以便根据需要进行调整。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919886|​|919887|const+s+=+"EMA618"

function+hasInt(me){
++let+i+=+1,a+=+me.split(""),b+=+"",c+=+"";
++a.forEach(function(e){
+++if+(!isNaN(e)){
+++++console.log(`CONTAIN+NUMBER+«${e}»+AT+POSITION+${a.indexOf(e)}+=>+TOTAL+COUNT+${i}`)
+++++c+%2B=+e
+++++i%2B%2B
+++}+else+{b+%2B=+e}
++})
++console.log(`STRING+IS+«${b}»,+NUMBER+IS+«${c}»`)
++if+(i+===+0){
++++return+false
++++//+return+b
++}+else+{
++++return+true
++++//+return+%2Bc
++}
}


hasInt(s)|code-block|syntax|javascript|919888|919889|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

To test if any char is a number, without overkill❓, to be adapted as need.
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const s = "EMA618"

function hasInt(me){
 let i = 1,a = me.split(""),b = "",c = "";
 a.forEach(function(e){
 if (!isNaN(e)){
 console.log(`CONTAIN NUMBER «${e}» AT POSITION ${a.indexOf(e)} =&gt; TOTAL COUNT ${i}`)
 c += e
 i++
 } else {b += e}
 })
 console.log(`STRING IS «${b}», NUMBER IS «${c}»`)
 if (i === 0){
 return false
 // return b
 } else {
 return true
 // return +c
 }
}


hasInt(s)</code></pre>
</div>
</div>

blocks|key|703344|text|你可以使用javascript来做这件事。不需要Jquery或Regex|type|unstyled|depth|inlineStyleRanges|entityRanges|data|703345|function+isNumeric(n)+
{
++return+!isNaN(n);
}|code-block|syntax|javascript|703346|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do this using javascript. No need for Jquery or Regex
<pre><code>function isNumeric(n) 
{
 return !isNaN(n);
}
</code></pre>

blocks|key|703465|text|检查它的一种方法是循环遍历字符串，并在输入数字时返回true+(或false，取决于您想要的值)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|703466|function+checkStringForNumbers(input){
++++let+str+=+String(input);
++++for(+let+i+=+0;+i+<+str.length;+i%2B%2B){
++++++++++++++console.log(str.charAt(i));
++++++++if(!isNaN(str.charAt(i))){+++++++++++//if+the+string+is+a+number,+do+the+following
++++++++++++return+true;
++++++++}
++++}
}|code-block|syntax|javascript|703467|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

One way to check it is to loop through the string and return true (or false depending on what you want) when you hit a number.

<pre><code>function checkStringForNumbers(input){
 let str = String(input);
 for( let i = 0; i &lt; str.length; i++){
 console.log(str.charAt(i));
 if(!isNaN(str.charAt(i))){ //if the string is a number, do the following
 return true;
 }
 }
}
</code></pre>

blocks|key|920030|text|当字符串以整数的表示形式开头时，parseInt会提供整数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|920031|(parseInt+'1a')++is++1|code-block|syntax|javascript|920032|也许是..so：|920033|isInteger+=+(s)->
++s+is+(parseInt+s).toString()++and++s+isnt+'NaN'

(isInteger+'a')+is+false
(isInteger+'1a')+is+false
(isInteger+'NaN')+is+false
(isInteger+'-42')+is+true|920034|请原谅我的CoffeeScript。|920035|entityMap^0|G|8|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

<code>parseInt</code> provides integers when the string begins with the representation of an integer:

<pre><code>(parseInt '1a') is 1
</code></pre>

..so perhaps:

<pre><code>isInteger = (s)-&gt;
 s is (parseInt s).toString() and s isnt 'NaN'

(isInteger 'a') is false
(isInteger '1a') is false
(isInteger 'NaN') is false
(isInteger '-42') is true
</code></pre>

Pardon my CoffeeScript.

blocks|key|703722|text|下面的代码检查相同的编号、序列号和反向编号序列。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|703723|function+checkNumSequnce(arrayNM2)+{
++++inseqCounter=1;
++++continousSeq+=+1;
++++decsequenceConter+=+1;
++++var+isequence+=+true;
++++for+(i=0;i<arrayNM2.length-1;i%2B%2B)+{
++++++j=i%2B1;
++++++if+(arrayNM2[i]+==+arrayNM2[i%2B1])+{+
++++++++++++++++if(inseqCounter+>+1+%7C%7C+decsequenceConter+>+1){
++++++++++++++++++++isequence+=++false;+break;
++++++++++++++++}++++++++
+++++++++++++++++continousSeq%2B%2B;+
+++++++++++++++++++++++++++++
+++++++++}+++++++++
++++++++else+if+(arrayNM2[j]-+arrayNM2[i]+==+1)+{
++++++++++++if(decsequenceConter+>+1+%7C%7C+continousSeq+>+1){
++++++++++++++++isequence+=++false;+break;++
++++++++++++++}++++++
+++++++++++++inseqCounter%2B%2B;+++++++++++++++
++++++++++++++++++++++++
++++++++}+else+if(arrayNM2[i]-+arrayNM2[j]+==+1){
++++++++++++++if(inseqCounter+>+1+%7C%7C+continousSeq+>+1){
+++++++++++++++++++isequence+=++false;+break;
+++++++++++++++}
++++++++++++++decsequenceConter%2B%2B;
++++++++}else{
++++++++++++++isequence=+false;
++++++++++++++break;
++++++++}
++};

++console.log("isequence:+"%2B+isequence);+

++};|code-block|syntax|javascript|703724|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Below code checks for same number, sequence number and reverse number sequence.
<pre><code>function checkNumSequnce(arrayNM2) {
 inseqCounter=1;
 continousSeq = 1;
 decsequenceConter = 1;
 var isequence = true;
 for (i=0;i&lt;arrayNM2.length-1;i++) {
 j=i+1;
 if (arrayNM2[i] == arrayNM2[i+1]) { 
 if(inseqCounter &gt; 1 || decsequenceConter &gt; 1){
 isequence = false; break;
 } 
 continousSeq++; 
 
 } 
 else if (arrayNM2[j]- arrayNM2[i] == 1) {
 if(decsequenceConter &gt; 1 || continousSeq &gt; 1){
 isequence = false; break; 
 } 
 inseqCounter++; 
 
 } else if(arrayNM2[i]- arrayNM2[j] == 1){
 if(inseqCounter &gt; 1 || continousSeq &gt; 1){
 isequence = false; break;
 }
 decsequenceConter++;
 }else{
 isequence= false;
 break;
 }
 };

 console.log(&quot;isequence: &quot;+ isequence); 

 };
</code></pre>

blocks|key|919936|text|您也可以尝试lodash：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919937|const+isNumeric+=+number+=>+
++_.isFinite(_.parseInt(number))+&&+!_.isNaN(_.parseInt(number))|code-block|syntax|javascript|919938|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can also try lodash:

<pre><code>const isNumeric = number =&gt; 
 _.isFinite(_.parseInt(number)) &amp;&amp; !_.isNaN(_.parseInt(number))
</code></pre>

My end goal is to validate an input field. The input may be either alphabetic or numeric.

Check whether an input string contains a number in javascript

我的最终目标是验证输入字段。输入可以是字母或数字。

问检查输入字符串是否包含javascript中的数字
EN

回答 11

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问检查输入字符串是否包含javascript中的数字EN

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问检查输入字符串是否包含javascript中的数字
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