假设connectionDetails
是一个Python字典,那么像这样重构代码的最好、最优雅、最“Python”的方式是什么?
if "host" in connectionDetails:
host = connectionDetails["host"]
else:
host = someDefaultValue
发布于 2012-02-20 17:44:06
如下所示:
host = connectionDetails.get('host', someDefaultValue)
发布于 2014-05-29 20:50:13
您也可以像这样使用defaultdict
:
from collections import defaultdict
a = defaultdict(lambda: "default", key="some_value")
a["blabla"] => "default"
a["key"] => "some_value"
您可以传递任何普通函数,而不是lambda:
from collections import defaultdict
def a():
return 4
b = defaultdict(a, key="some_value")
b['absent'] => 4
b['key'] => "some_value"
发布于 2013-07-06 17:17:36
虽然.get()
是一个很好的习惯用法,但它比if/else
慢(如果在大多数情况下可以预料到字典中存在键,那么它比try/except
还慢):
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="try:\n a=d[1]\nexcept KeyError:\n a=10")
0.07691968797894333
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="try:\n a=d[2]\nexcept KeyError:\n a=10")
0.4583777282275605
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="a=d.get(1, 10)")
0.17784020746671558
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="a=d.get(2, 10)")
0.17952161730158878
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="if 1 in d:\n a=d[1]\nelse:\n a=10")
0.10071221458065338
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="if 2 in d:\n a=d[2]\nelse:\n a=10")
0.06966537335119938
https://stackoverflow.com/questions/9358983
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