blocks|key|909592|text|$_GET不是函数或语言构造-它只是一个变量(数组)。尝试：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|909593|<?php
echo+$_GET['link'];|code-block|syntax|javascript|909594|特别是，它是一个superglobal：一个由PHP填充的内置变量，在所有作用域中都可用(您可以在没有global关键字的函数内部使用它)。|909595|由于变量可能不存在，您可以(也应该)确保您的代码不会触发以下通知：|909596|<?php
if+(isset($_GET['link']))+{
++++echo+$_GET['link'];
}+else+{
++++//+Fallback+behaviour+goes+here
}|909597|或者，如果您想跳过手动索引检查，并可能添加进一步的验证，则可以使用filter扩展：|909598|<?php
echo+filter_input(INPUT_GET,+'link',+FILTER_SANITIZE_URL);|909599|最后但并非最不重要的一点是，您可以使用null+coalescing+operator+(从PHP/7.0开始提供)来处理缺少的参数：|909600|echo+$_GET['link']+??+'Fallback+value';|909601|entityMap|0|LINK|mutability|MUTABLE|url|http://es1.php.net/manual/en/language.variables.superglobals.php|1|http://es1.php.net/manual/en/language.variables.scope.php|2|http://php.net/filter|3|https://www.php.net/manual/en/language.operators.comparison.php#language.operators.comparison.coalesce|4|https://www.php.net/manual/en/migration70.new-features.php^0|0|5|0|0|8|B|0|1F|6|1|0|0|0|X|6|2|0|0|J|O|3|1A|7|4|0|0^^$0|@$1|2|3|4|5|6|7|1E|8|@$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1H|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1I|8|@]|D|@$9|1J|A|1K|1|1L]|$9|1M|A|1N|1|1O]]|E|$]]|$1|M|3|N|5|6|7|1P|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|1Q|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|1R|8|@]|D|@$9|1S|A|1T|1|1U]]|E|$]]|$1|S|3|T|5|H|7|1V|8|@]|D|@]|E|$I|J]]|$1|U|3|V|5|6|7|1W|8|@]|D|@$9|1X|A|1Y|1|1Z]|$9|20|A|21|1|22]]|E|$]]|$1|W|3|X|5|H|7|23|8|@]|D|@]|E|$I|J]]|$1|Y|3|-4|5|6|7|24|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]|16|$5|11|12|13|E|$14|17]]|18|$5|11|12|13|E|$14|19]]|1A|$5|11|12|13|E|$14|1B]]|1C|$5|11|12|13|E|$14|1D]]]]

<code>$_GET</code> is not a function or language construct—it's just a variable (an array). Try:

<pre><code>&lt;?php
echo $_GET['link'];
</code></pre>

In particular, it's a <a href="http://es1.php.net/manual/en/language.variables.superglobals.php" rel="noreferrer">superglobal</a>: a built-in variable that's populated by PHP and is available in all scopes (you can use it from inside a function without the <a href="http://es1.php.net/manual/en/language.variables.scope.php" rel="noreferrer">global</a> keyword).

Since the variable might not exist, you could (and should) ensure your code does not trigger notices with:

<pre><code>&lt;?php
if (isset($_GET['link'])) {
 echo $_GET['link'];
} else {
 // Fallback behaviour goes here
}
</code></pre>

Alternatively, if you want to skip manual index checks and maybe add further validations you can use the <a href="http://php.net/filter" rel="noreferrer">filter</a> extension:

<pre><code>&lt;?php
echo filter_input(INPUT_GET, 'link', FILTER_SANITIZE_URL);
</code></pre>

Last but not least, you can use the <a href="https://www.php.net/manual/en/language.operators.comparison.php#language.operators.comparison.coalesce" rel="noreferrer">null coalescing operator</a> (available since <a href="https://www.php.net/manual/en/migration70.new-features.php" rel="noreferrer">PHP/7.0</a>) to handle missing parameters:

<pre><code>echo $_GET['link'] ?? 'Fallback value';
</code></pre>

blocks|key|909686|text|使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|909687|$parameter+=+$_SERVER['QUERY_STRING'];
echo+$parameter;|code-block|syntax|javascript|909688|或者直接使用：|909689|$parameter+=+$_GET['link'];
echo+$parameter+;|909690|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Use this:

<pre><code>$parameter = $_SERVER['QUERY_STRING'];
echo $parameter;
</code></pre>

Or just use:

<pre><code>$parameter = $_GET['link'];
echo $parameter ;
</code></pre>

blocks|key|909670|text|为了确保您始终是安全的，而不会得到各种不想要的代码插入，请使用过滤器：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|909671|echo+filter_input(INPUT_GET,"link",FILTER_SANITIZE_STRING);|code-block|syntax|javascript|909672|有关php.net+function+filter_input的更多信息，请查看the+description+of+the+different+filters|offset|length|909673|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.filter-input.php|1|http://www.php.net/manual/en/filter.filters.php^0|0|0|2|T|0|14|14|1|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]|$I|10|J|11|1|12]]|A|$]]|$1|K|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]|S|$5|N|O|P|A|$Q|T]]]]

To make sure you're always on the safe side, without getting all kinds of unwanted code insertion use FILTERS:

<pre><code>echo filter_input(INPUT_GET,"link",FILTER_SANITIZE_STRING);
</code></pre>

More reading on <a href="http://php.net/manual/en/function.filter-input.php" rel="noreferrer">php.net function filter_input</a>, or check out <a href="http://www.php.net/manual/en/filter.filters.php" rel="noreferrer">the description of the different filters</a>

blocks|key|693738|text|公认的答案是好的。但是如果你有这样的场景：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|693739|http://www.mydomain.me/index.php?state=California.php#Berkeley|code-block|syntax|javascript|693740|您可以将命名锚点视为查询字符串，如下所示：|693741|http://www.mydomain.me/index.php?state=California.php&city=Berkeley|693742|然后，像这样访问它：|693743|$Url+=+$_GET['state']."#".$_GET['city'];|693744|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The accepted answer is good. But if you have a scenario like this:

<pre><code>http://www.mydomain.me/index.php?state=California.php#Berkeley
</code></pre>

You can treat the named anchor as a query string like this:

<pre><code>http://www.mydomain.me/index.php?state=California.php&amp;city=Berkeley
</code></pre>

Then, access it like this:

<pre><code>$Url = $_GET['state']."#".$_GET['city'];
</code></pre>

blocks|key|693784|text|正如Alvaro所说，$_GET不是一个函数，而是一个包含参数的数组，因此您可以使用以下命令从该数组中检索一个元素|type|unstyled|depth|inlineStyleRanges|entityRanges|data|693785|<?php
$link+=+$_GET['link'];
echo+$link;
?>|code-block|syntax|javascript|693786|预期的操作：|693787|www.google.com|693788|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

As Alvaro said, $_GET is not a function but an array containing the parameters
So you can retrieve one element from that array using 

<pre><code>&lt;?php
$link = $_GET['link'];
echo $link;
?&gt;
</code></pre>

Expected OP:

<pre><code>www.google.com
</code></pre>

blocks|key|693841|text|这就是我解决这个问题的方法，我更进一步，使用该参数来设置cookie，然后重定向到一个干净的URL。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|693842|if+(isset+($_GET['referrer']))+{
++++$referrer+=+$_GET['referrer'];

//++++check+db+if+refer+exists
++++$shareLinkTrue+=+(new+queries)->checkNewReferralExists($conn,+$referrer);
//++++if+exists,+set+cookie
++++if+($shareLinkTrue+==+1)+{
++++++++setcookie('_referrer_link',+$referrer,+1,
++++++++++++isset($params['path']),
++++++++++++isset($params['domain']),
++++++++++++isset($params['secure']),
++++++++++++isset($params['httponly']));

++++++++header('Location:+register.php');

++++}

}|code-block|syntax|javascript|693843|完美的作品|693844|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This is what I done with the problem, and I went a step further and used that parameter to set a cookie, and then redirect to a clean URL.
<pre><code>if (isset ($_GET['referrer'])) {
 $referrer = $_GET['referrer'];

// check db if refer exists
 $shareLinkTrue = (new queries)-&gt;checkNewReferralExists($conn, $referrer);
// if exists, set cookie
 if ($shareLinkTrue == 1) {
 setcookie('_referrer_link', $referrer, 1,
 isset($params['path']),
 isset($params['domain']),
 isset($params['secure']),
 isset($params['httponly']));

 header('Location: register.php');

 }

}
</code></pre>
Works perfect

blocks|key|693530|text|如果没有得到任何结果，我认为他只需要将结果放在html标签中，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|693531|如下所示：|693532|<html>
<head></head>
<body>
<?php
echo+$_GET['link'];
?>
<body>
</html>|code-block|syntax|javascript|693533|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Whomever gets nothing back, I think he just has to enclose the result in html tags, 

Like this:

<pre><code>&lt;html&gt;
&lt;head&gt;&lt;/head&gt;
&lt;body&gt;
&lt;?php
echo $_GET['link'];
?&gt;
&lt;body&gt;
&lt;/html&gt;
</code></pre>

I'm trying to pass a URL as a url parameter in php but when I try to get this parameter I get nothing 

I'm using the following url form:

<pre><code>http://localhost/dispatch.php?link=www.google.com
</code></pre>

I'm trying to get it through:

<pre><code>$_GET['link'];
</code></pre>

But nothing returned. What is the problem?

GET URL parameter in PHP

我试图在php中传递一个URL作为url参数，但是当我尝试获取这个参数时，我什么也得不到。我使用下面的url格式：http://localhost/dispatch.php?link=www.google.com我在试着让它通过：$_GET['link'];但是什么也没有返回。有什么问题吗？

问获取PHP中的URL参数
EN

回答 7

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问获取PHP中的URL参数EN

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