blocks|key|1549170|text|完全不同的是，您不会在静态函数中获得$this。如果你尝试使用$this，你会得到一个Fatal+error:+Using+$this+when+not+in+object+context。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1549171|好的，还有一个不同之处:您的第一个示例生成了一个E_STRICT警告。|1549172|entityMap^0|I|5|V|5|17|1F|0|O|8|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

Entire difference is, you don't get <code>$this</code> supplied inside the static function. If you try to use <code>$this</code>, you'll get a <code>Fatal error: Using $this when not in object context</code>.

Well, okay, one other difference: an <code>E_STRICT</code> warning is generated by your first example.

blocks|key|1549212|text|简而言之，在第二种情况下，您没有将对象作为$this，因为静态方法是类的函数/方法，而不是对象实例。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1549213|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

In a nutshell, you don't have the object as $this in the second case, as 
the static method is a function/method of the class not the object instance.

blocks|key|1333864|text|在第一个类中，sayHi()实际上是一个实例方法，您将其作为静态方法调用，但由于sayHi()从未引用过$this，因此您可以轻松地使用它。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1333865|静态函数与类相关联，而不是类的实例。因此，$this不能从静态上下文中获得($this没有指向任何对象)。|1333866|entityMap^0|7|7|14|7|1G|5|0|L|5|12|5|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|I|$]]

In the first class, <code>sayHi()</code> is actually an instance method which you are calling as a static method and you get away with it because <code>sayHi()</code> never refers to <code>$this</code>.

Static functions are associated with the class, not an instance of the class. As such, <code>$this</code> is not available from a static context (<code>$this</code> isn't pointing to any object).

blocks|key|1549345|text|在尝试了示例(PHP5.3.5)之后，我发现在定义函数的两种情况下，都不能使用$this运算符来处理类函数。所以我还找不到它们之间的区别。:(|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1549346|entityMap^0|13|5|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

After trying examples (PHP 5.3.5), I found that in both cases of defining functions you can't use <code>$this</code> operator to work on class functions. So I couldn't find a difference in them yet. :(

blocks|key|1549413|text|简单地说，静态函数的功能独立于它们所属的类。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1549414|$this表示，这是这个类的一个对象。它不适用于静态函数。|1549415|class+test+{
++++public+function+sayHi($hi+=+"Hi")+{
++++++++$this->hi+=+$hi;
++++++++return+$this->hi;
++++}
}
class+test1+{
++++public+static+function+sayHi($hi)+{
++++++++$hi+=+"Hi";
++++++++return+$hi;
++++}
}

//++Test
$mytest+=+new+test();
print+$mytest->sayHi('hello');++//+returns+'hello'
print+test1::sayHi('hello');++++//++returns+'Hi'|code-block|syntax|javascript|1549416|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Simply, static functions function independently of the class where they belong.

$this means, this is an object of this class. It does not apply to static functions.

<pre><code>class test {
 public function sayHi($hi = "Hi") {
 $this-&gt;hi = $hi;
 return $this-&gt;hi;
 }
}
class test1 {
 public static function sayHi($hi) {
 $hi = "Hi";
 return $hi;
 }
}

// Test
$mytest = new test();
print $mytest-&gt;sayHi('hello'); // returns 'hello'
print test1::sayHi('hello'); // returns 'Hi'
</code></pre>

blocks|key|1549461|text|静态调用非静态方法会生成E_STRICT级别的警告。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1549462|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Calling non-static methods statically generates an E_STRICT level warning.

I have a question regarding static function in php.

let's assume that I have a class

<pre><code>class test {
 public function sayHi() {
 echo 'hi';
 }
}
</code></pre>

if I do <code>test::sayHi();</code> it works without a problem.

<pre><code>class test {
 public static function sayHi() {
 echo 'hi';
 }
}
</code></pre>

<code>test::sayHi();</code> works as well.

What are the differences between first class and second class?

What is special about a static function?

php static function

我有一个关于php中静态函数的问题。假设我有一个类class test {    public function sayHi() {        echo 'hi';    }}如果我使用test::sayHi();，它可以正常工作，没有问题。class test {    public static functio...

问php静态函数
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问php静态函数EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问php静态函数
EN