blocks|key|708633|text|您的问题是forloop.counter是一个整数，并且您使用的是add模板过滤器，如果您传递给它的是全部字符串或全部整数，而不是混合传递，则该过滤器将正常工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|708634|解决此问题的一种方法是：|708635|{%25+for+x+in+some_list+%25}
++++{%25+with+y=forloop.counter%7Cstringformat:"s"+%25}
++++{%25+with+template="mod"%7Cadd:y%7Cadd:".html"+%25}
++++++++{{+template+}}
++++{%25+endwith+%25}
++++{%25+endwith+%25}
{%25+endfor+%25}|code-block|syntax|javascript|708636|这会导致：|708637|mod1.html
mod2.html
mod3.html
mod4.html
mod5.html
mod6.html
...|708638|第二个with标签是必需的，因为stringformat标签是用一个自动预置的%25实现的。要解决此问题，可以创建自定义筛选器。我使用类似这样的东西：|708639|http://djangosnippets.org/snippets/393/|708640|将截图另存为some_app/templatetags/some_name.py|708641|from+django+import+template

register+=+template.Library()

def+format(value,+arg):
++++"""
++++Alters+default+filter+"stringformat"+to+not+add+the+%25+at+the+front,
++++so+the+variable+can+be+placed+anywhere+in+the+string.
++++"""
++++try:
++++++++if+value:
++++++++++++return+(unicode(arg))+%25+value
++++++++else:
++++++++++++return+u''
++++except+(ValueError,+TypeError):
++++++++return+u''
register.filter('format',+format)|708642|在模板中：|708643|{%25+load+some_name.py+%25}

{%25+for+x+in+some_list+%25}
++++{%25+with+template=forloop.counter%7Cformat:"mod%25s.html"+%25}
++++++++{{+template+}}
++++{%25+endwith+%25}
{%25+endfor+%25}|708644|entityMap|0|LINK|mutability|MUTABLE|url^0|X|3|0|0|0|0|0|13|1|0|0|13|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1C|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1D|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1E|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|S|3|T|5|6|7|1J|8|@]|D|@$9|1K|A|1L|1|1M]]|E|$]]|$1|U|3|V|5|6|7|1N|8|@]|D|@]|E|$]]|$1|W|3|X|5|J|7|1O|8|@]|D|@]|E|$K|L]]|$1|Y|3|Z|5|6|7|1P|8|@]|D|@]|E|$]]|$1|10|3|11|5|J|7|1Q|8|@]|D|@]|E|$K|L]]|$1|12|3|-4|5|6|7|1R|8|@]|D|@]|E|$]]]|13|$14|$5|15|16|17|E|$18|T]]]]

Your problem is that the forloop.counter is an integer and you are using the <code>add</code> template filter which will behave properly if you pass it all strings or all integers, but not a mix.

One way to work around this is:

<pre><code>{% for x in some_list %}
 {% with y=forloop.counter|stringformat:"s" %}
 {% with template="mod"|add:y|add:".html" %}
 &lt;p&gt;{{ template }}&lt;/p&gt;
 {% endwith %}
 {% endwith %}
{% endfor %}
</code></pre>

which results in:

<pre><code>&lt;p&gt;mod1.html&lt;/p&gt;
&lt;p&gt;mod2.html&lt;/p&gt;
&lt;p&gt;mod3.html&lt;/p&gt;
&lt;p&gt;mod4.html&lt;/p&gt;
&lt;p&gt;mod5.html&lt;/p&gt;
&lt;p&gt;mod6.html&lt;/p&gt;
...
</code></pre>

The second with tag is required because stringformat tag is implemented with an automatically prepended <code>%</code>. To get around this you can create a custom filter. I use something similar to this:

<a href="http://djangosnippets.org/snippets/393/" rel="noreferrer">http://djangosnippets.org/snippets/393/</a>

save the snipped as some_app/templatetags/some_name.py

<pre><code>from django import template

register = template.Library()

def format(value, arg):
 """
 Alters default filter "stringformat" to not add the % at the front,
 so the variable can be placed anywhere in the string.
 """
 try:
 if value:
 return (unicode(arg)) % value
 else:
 return u''
 except (ValueError, TypeError):
 return u''
register.filter('format', format)
</code></pre>

in template:

<pre><code>{% load some_name.py %}

{% for x in some_list %}
 {% with template=forloop.counter|format:"mod%s.html" %}
 &lt;p&gt;{{ template }}&lt;/p&gt;
 {% endwith %}
{% endfor %}
</code></pre>

blocks|key|925042|text|您可能不想在模板中这样做，这看起来更像是一个视图作业：(在for循环中使用if+)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|925043|chosen_templates=[]
for+choice+in+choice_dict:
++if+choice+=='2':
++++{%25+with+"mod"%7Cadd:forloop.counter%7Cadd:".html"+as+template+%25}
++++template_name+=+"mod%25i.html"+%25index
++++chosen_templates.append(template_name)|code-block|syntax|javascript|925044|然后将chosen_templates传递给您的模板，在该模板中您将只拥有|offset|length|style|CODE|925045|{%25+for+template+in+chosen_templates+%25}
++{%25+load+template+%25}
{%25+endfor+%25}|925046|另外，我也不太明白为什么你要用字典来选择一个字典里没有的数字模板。for+key,value+in+dict.items()可能就是你要找的东西。|925047|entityMap^0|0|0|3|G|0|0|X|T|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

You probably don't want to do this in your templates, this seems more like a views job: (use of if within a for loop).

<pre><code>chosen_templates=[]
for choice in choice_dict:
 if choice =='2':
 {% with "mod"|add:forloop.counter|add:".html" as template %}
 template_name = "mod%i.html" %index
 chosen_templates.append(template_name)
</code></pre>

Then pass <code>chosen_templates</code> to your template where you will have only

<pre><code>{% for template in chosen_templates %}
 {% load template %}
{% endfor %}
</code></pre>

Also, I don't quite understand why you are using a dict to select the template with a number that is not in the dictionnary. <code>for key,value in dict.items()</code> may be what you are looking for.

I am already trying to concatenate like this:

<pre><code>{% for choice in choice_dict %}
 {% if choice =='2' %}
 {% with "mod"|add:forloop.counter|add:".html" as template %}
 {% include template %}
 {% endwith %} 
 {% endif %}
{% endfor %} 
</code></pre>

but for some reason I am only getting "mod.html" and not the forloop.counter number. Does anyone have any idea what is going on and what I can do to fix this issue? Thanks alot!

How can I concatenate forloop.counter to a string in my django template

我已经尝试像这样连接：{% for choice in choice_dict %}    {% if choice =='2' %}        {% with "mod"|add:forloop.counter|add:".html" as template %}            {% include te...

问如何将forloop.counter连接到django模板中的字符串
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