blocks|key|1894749|text|只需使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1894750|date("m/d/Y",+strtotime("last+week+monday"));
date("m/d/Y",+strtotime("last+week+sunday"));|code-block|syntax|javascript|1894751|它将给出上周的星期一和星期日的日期。|1894752|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Simply use 

<pre><code>date("m/d/Y", strtotime("last week monday"));
date("m/d/Y", strtotime("last week sunday"));
</code></pre>

It will give the date of Last week's Monday and Sunday.

blocks|key|1894651|text|为此，您需要使用strtotime函数|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1894652|<center>
<?php
+function+get_last_week_dates()
+{
++++++++//+how+can+i+get+the+date+range+last+week+?
++++++++//+ex:+today+is+2014-2-8
++++++++//+the+week+date+range+of+last+week+should+be+'2014-1-26+~+2014-2-1'

++++++++$startdate+=+"last+monday";
++++++++if+(date('N')+!==+'1')
++++++++{+
++++++++++++//+it's+not+Monday+today
++++++++++++$startdate+.=+"+last+week";
++++++++}
++++++++echo+"<br+/>";
++++++++$day+=+strtotime($startdate);
++++++++echo+date('r',+$day);+++
++++++++echo+"<br+/>";
++++++++$sunday+=+strtotime('next+monday',+$day)+-+1;
++++++++echo+date('r',+$sunday);
++++}
++++get_last_week_dates();
?>
</center>|code-block|syntax|javascript|1894653|entityMap^0|8|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

you need you use <code>strtotime</code> function for this

<pre><code>&lt;center&gt;
&lt;?php
 function get_last_week_dates()
 {
 // how can i get the date range last week ?
 // ex: today is 2014-2-8
 // the week date range of last week should be '2014-1-26 ~ 2014-2-1'

 $startdate = "last monday";
 if (date('N') !== '1')
 { 
 // it's not Monday today
 $startdate .= " last week";
 }
 echo "&lt;br /&gt;";
 $day = strtotime($startdate);
 echo date('r', $day); 
 echo "&lt;br /&gt;";
 $sunday = strtotime('next monday', $day) - 1;
 echo date('r', $sunday);
 }
 get_last_week_dates();
?&gt;
&lt;/center&gt;
</code></pre>

blocks|key|1680937|text|只是为了解决这个问题的乐趣：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1680938|date_default_timezone_set('UTC');
$firstDayOfLastWeek+=+mktime(0,0,0,date("m"),date("d")-date("w")-7);
$lastDayOfLastWeek+=+mktime(0,0,0,date("m"),date("d")-date("w")-1);
echo("Last+week+began+on:+".date("d.m.Y",$firstDayOfLastWeek));
echo(" ");
echo("Last+week+ended+on:+".date("d.m.Y",$lastDayOfLastWeek));|code-block|syntax|javascript|1680939|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Well just for the fun of trying to solve this:

<pre><code>date_default_timezone_set('UTC');
$firstDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-7);
$lastDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-1);
echo("Last week began on: ".date("d.m.Y",$firstDayOfLastWeek));
echo("&lt;br&gt;");
echo("Last week ended on: ".date("d.m.Y",$lastDayOfLastWeek));
</code></pre>

blocks|key|1894737|text|这应该能起到作用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1894738|$startWeek+=+date('Y-m-d',strtotime("Sunday+Last+Week"));
$endWeek+=+date('Y-m-d',strtotime("Sunday+This+Week"));|code-block|syntax|javascript|1894739|如果在星期一运行，这将不起作用。从上个星期天(前一天)到下个星期天。所以在上面使用Abhik+Chakraborty的方法：|1894740|$startTime+=+strtotime("last+sunday+midnight",$previous_week);
$endTime+=+strtotime("next+sunday+midnight",$startTime);
$startDate+=+date('Y-m-d+00:00:00',$startTime);
$endDate+=+date('Y-m-d+23:59:59',$endTime);|1894741|这将会给出|1894742|start+=++2014-08-10+00:00:00
endDate+=+2014-08-17+23:59:59|1894743|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

This should do the trick 

<pre><code>$startWeek = date('Y-m-d',strtotime("Sunday Last Week"));
$endWeek = date('Y-m-d',strtotime("Sunday This Week"));
</code></pre>

this would not work if ran on a Monday. It would get last Sunday (the day before) to the next Sunday. So using Abhik Chakraborty's method with the above:

<pre><code>$startTime = strtotime("last sunday midnight",$previous_week);
$endTime = strtotime("next sunday midnight",$startTime);
$startDate = date('Y-m-d 00:00:00',$startTime);
$endDate = date('Y-m-d 23:59:59',$endTime);
</code></pre>

This will now give 

<pre><code>start = 2014-08-10 00:00:00
endDate = 2014-08-17 23:59:59
</code></pre>

blocks|key|1681019|text|我知道这很古老，但这里有一种更简洁的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1681020|$startDate+=+date("m/d/y",+strtotime(date("w")+?+"2+sundays+ago"+:+"last+sunday"));
$endDate+=+date("m/d/y",+strtotime("last+saturday"));
echo+$startDate+.+"+-+"+.+$endDate|code-block|syntax|javascript|1681021|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I know this is old but here's a much more succinct way of doing it:

<pre><code>$startDate = date("m/d/y", strtotime(date("w") ? "2 sundays ago" : "last sunday"));
$endDate = date("m/d/y", strtotime("last saturday"));
echo $startDate . " - " . $endDate
</code></pre>

blocks|key|1681034|text|这将产生正确的结果，并处理星期一的问题|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1681035|<?php
$monday+=+strtotime("last+monday");
$monday+=+date('W',+$monday)==date('W')+?+$monday-7*86400+:+$monday;

$sunday+=+strtotime(date("Y-m-d",$monday)."+%2B6+days");
$this_week_sd+=+date("Y-m-d",$monday);
$this_week_ed+=+date("Y-m-d",$sunday);

echo+"Last+week+range+from+$this_week_sd+to+$this_week_ed+";
?>|code-block|syntax|javascript|1681036|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This one will produce the proper result and handles the Monday issue

<pre><code>&lt;?php
$monday = strtotime("last monday");
$monday = date('W', $monday)==date('W') ? $monday-7*86400 : $monday;

$sunday = strtotime(date("Y-m-d",$monday)." +6 days");
$this_week_sd = date("Y-m-d",$monday);
$this_week_ed = date("Y-m-d",$sunday);

echo "Last week range from $this_week_sd to $this_week_ed ";
?&gt;
</code></pre>

blocks|key|1680917|text|你可以这样做。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1680918|首先得到当前的时间戳，然后减去你想要的no.of天。|1680919|$curTime+=+time();
echo+date("Y-m-d",$curTime);
echo+"<br+/>";
echo+date("Y-m-d",($curTime-(60*60*24*7)));|code-block|syntax|javascript|1680920|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can do this way.

First get the current timestamp and subtract the no.of days you want.

<pre><code>$curTime = time();
echo date("Y-m-d",$curTime);
echo "&lt;br /&gt;";
echo date("Y-m-d",($curTime-(60*60*24*7)));
</code></pre>

blocks|key|1681007|text|$lastWeekStartTime+=+strtotime("last+sunday",strtotime("-1+week"));
$lastWeekEndTime+=+strtotime("this+sunday",strtotime("-1+week"));
$lastWeekStart+=+date("Y-m-d",$lastWeekStartTime);
$lastWeekEnd+=+date("Y-m-d",$lastWeekEndTime);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1681008|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$lastWeekStartTime = strtotime("last sunday",strtotime("-1 week"));
$lastWeekEndTime = strtotime("this sunday",strtotime("-1 week"));
$lastWeekStart = date("Y-m-d",$lastWeekStartTime);
$lastWeekEnd = date("Y-m-d",$lastWeekEndTime);
</code></pre>

blocks|key|1894811|text|大多数其他提供的解决方案在一天内就失效了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1894812|如果你想在上周从周日到周六，这是一个很好的方法。|1894813|$start+=+date("Y-m-d",strtotime("last+sunday",strtotime("-1+week")));
$end+=+date("Y-m-d",strtotime("saturday",strtotime("-1+week")));

echo+$start.+"+to+".$end;|code-block|syntax|javascript|1894814|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Most of those other solutions offered were off by one day. 
If you want Sunday to Saturday for last week, this is the way to do it.

<pre><code>$start = date("Y-m-d",strtotime("last sunday",strtotime("-1 week")));
$end = date("Y-m-d",strtotime("saturday",strtotime("-1 week")));

echo $start. " to ".$end;
</code></pre>

how can I get last week' date range in php ?

see my codes bellow:

<pre><code>&lt;?php 
 function get_last_week_dates(){
 // how can i get the date range last week ?
 // ex: today is 2014-2-8
 // the week date range of last week should be '2014-1-26 ~ 2014-2-1'
 }
?&gt;
</code></pre>

how can I get last week' date range in php?

如何在php中获取上周的日期范围？下面是我的代码：<?php function get_last_week_dates(){ // how can i get the date range last week ? // ex: today is 2014-2-8 // the week date range of last week should

问如何在php中获取上周的日期范围？
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问如何在php中获取上周的日期范围？
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