blocks|key|4510262|text|可以使用tick_params+(http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params)将刻度长度设置为0：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4510263|fig+=+plt.figure()
ax+=+fig.add_subplot(111)
ax.plot([1],[1])
ax.tick_params(axis=u'both',+which=u'both',length=0)
plt.show()|code-block|syntax|javascript|4510264|entityMap|0|LINK|mutability|MUTABLE|url|http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params^0|4|B|H|20|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

You can set the tick length to 0 using <code>tick_params</code> (<a href="http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params" rel="noreferrer">http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params</a>):

<pre><code>fig = plt.figure()
ax = fig.add_subplot(111)
ax.plot([1],[1])
ax.tick_params(axis=u'both', which=u'both',length=0)
plt.show()
</code></pre>

blocks|key|2854|text|感谢您的回答@julien-spronck和@cmidi。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2855|需要注意的是，我必须使用这两种方法才能使其工作：|2856|import+numpy+as+np
import+matplotlib.pyplot+as+plt

fig,+(ax1,+ax2,+ax3)+=+plt.subplots(1,+3,+figsize=(11,+3))

data+=+np.random.random((4,+4))

ax1.imshow(data)
ax1.set(title='Bad',+ylabel='$A_y$')
#+plt.setp(ax1.get_xticklabels(),+visible=False)
#+plt.setp(ax1.get_yticklabels(),+visible=False)
ax1.tick_params(axis='both',+which='both',+length=0)

ax2.imshow(data)
ax2.set(title='Somewhat+OK',+ylabel='$B_y$')
plt.setp(ax2.get_xticklabels(),+visible=False)
plt.setp(ax2.get_yticklabels(),+visible=False)
#+ax2.tick_params(axis='both',+which='both',+length=0)

ax3.imshow(data)
ax3.set(title='Nice',+ylabel='$C_y$')
plt.setp(ax3.get_xticklabels(),+visible=False)
plt.setp(ax3.get_yticklabels(),+visible=False)
ax3.tick_params(axis='both',+which='both',+length=0)

plt.show()|code-block|syntax|javascript|2857|​|2858|📷|atomic|offset|length|2859|2860|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/3900c16dd27cb58565a51bd68a3de03a.png|imageAlt^0|0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|10|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|11|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|12|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|13|8|@]|9|@$N|14|O|15|1|16]]|A|$]]|$1|P|3|J|5|6|7|17|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X|Y|-4]]]]

Thanks for your answers @julien-spronck and @cmidi. 
As a note, I had to use both methods to make it work:

<pre><code>import numpy as np
import matplotlib.pyplot as plt

fig, (ax1, ax2, ax3) = plt.subplots(1, 3, figsize=(11, 3))

data = np.random.random((4, 4))

ax1.imshow(data)
ax1.set(title='Bad', ylabel='$A_y$')
# plt.setp(ax1.get_xticklabels(), visible=False)
# plt.setp(ax1.get_yticklabels(), visible=False)
ax1.tick_params(axis='both', which='both', length=0)

ax2.imshow(data)
ax2.set(title='Somewhat OK', ylabel='$B_y$')
plt.setp(ax2.get_xticklabels(), visible=False)
plt.setp(ax2.get_yticklabels(), visible=False)
# ax2.tick_params(axis='both', which='both', length=0)

ax3.imshow(data)
ax3.set(title='Nice', ylabel='$C_y$')
plt.setp(ax3.get_xticklabels(), visible=False)
plt.setp(ax3.get_yticklabels(), visible=False)
ax3.tick_params(axis='both', which='both', length=0)

plt.show()
</code></pre>

<a href="https://i.stack.imgur.com/k3haX.png" rel="noreferrer"><img src="https://i.stack.imgur.com/k3haX.png" alt="Outcome of the code with desired labels"></a>

blocks|key|2983|text|这对我很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2984|plt.tick_params(axis='both',+labelsize=0,+length+=+0)|code-block|syntax|javascript|2985|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This worked for me:

<pre><code>plt.tick_params(axis='both', labelsize=0, length = 0)
</code></pre>

blocks|key|4510415|text|在参加一个关于Python的coursera课程时，这是一个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4510416|下面是给定的解决方案，我认为它更具可读性和直观性。|4510417|ax.tick_params(top=False,+bottom=False,+left=False,+right=False,+labelleft=True,+labelbottom=True)|code-block|syntax|javascript|4510418|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

While attending a coursera course on Python, this was a question.
Below is the given solution, which I think is more readable and intuitive.
<pre><code>ax.tick_params(top=False, bottom=False, left=False, right=False, labelleft=True, labelbottom=True)
</code></pre>

blocks|key|2805|text|matplotlib.pyplot.setp(*args,+**kwargs)用于设置艺术家对象的属性。除了get_xticklabes()之外，您还可以使用它来使其不可见。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2806|关于以下内容的内容|2807|import+matplotlib.pyplot+as+plt
fig+=+plt.figure()
ax+=+fig.add_subplot(2,1,1)
ax.set_xlabel("X-Label",fontsize=10,color='red')
plt.setp(ax.get_xticklabels(),visible=False)|code-block|syntax|javascript|2808|下面是参考页面http://matplotlib.org/api/pyplot_api.html|2809|entityMap|0|LINK|mutability|MUTABLE|url|http://matplotlib.org/api/pyplot_api.html^0|0|13|1I|G|0|0|0|7|15|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

<code>matplotlib.pyplot.setp(*args, **kwargs)</code> is used to set properties of an artist object. You can use this in addition to <code>get_xticklabes()</code> to make it invisible.

something on the lines of the following

<pre><code>import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(2,1,1)
ax.set_xlabel("X-Label",fontsize=10,color='red')
plt.setp(ax.get_xticklabels(),visible=False)
</code></pre>

Below is the reference page
<a href="http://matplotlib.org/api/pyplot_api.html" rel="noreferrer">http://matplotlib.org/api/pyplot_api.html</a>

blocks|key|2895|text|您可以设置yaxis和xaxis+set_ticks_position属性，使它们分别显示在左侧和底部。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2896|ax.yaxis.set_ticks_position('left')
ax.xaxis.set_ticks_position('bottom')|code-block|syntax|javascript|2897|此外，还可以通过将特定脊椎的set_visible属性设置为False来隐藏脊椎。|2898|axes[i].spines['right'].set_visible(False)
axes[i].spines['top'].set_visible(False)|2899|entityMap^0|5|5|B|5|H|I|0|0|E|B|U|5|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|P|$]]

You can set the <code>yaxis</code> and <code>xaxis</code> <code>set_ticks_position</code> properties so they just show on the left and bottom sides, respectively.

<pre><code>ax.yaxis.set_ticks_position('left')
ax.xaxis.set_ticks_position('bottom')
</code></pre>

Furthermore, you can hide the spines as well by setting the <code>set_visible</code> property of the specific spine to <code>False</code>. 

<pre><code>axes[i].spines['right'].set_visible(False)
axes[i].spines['top'].set_visible(False)
</code></pre>

blocks|key|4510501|text|这对我来说效果很好！试试看|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4510502|import+matplotlib.pyplot+as+plt
import+numpy+as+np

plt.figure()

languages+=['Python',+'SQL',+'Java',+'C%2B%2B',+'JavaScript']
pos+=+np.arange(len(languages))
popularity+=+[56,+39,+34,+34,+29]

plt.bar(pos,+popularity,+align='center')
plt.xticks(pos,+languages)
plt.ylabel('%25+Popularity')
plt.title('Top+5+Languages+for+Math+&+Data+\nby+%25+popularity+on+Stack+Overflow',+
alpha=0.8)

#+remove+all+the+ticks+(both+axes),+
plt.tick_params(top='off',+bottom='off',+left='off',+right='off',+labelleft='off',+
labelbottom='on')
plt.show()|code-block|syntax|javascript|4510503|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This Worked out pretty well for me! try it out
<pre><code>import matplotlib.pyplot as plt
import numpy as np

plt.figure()

languages =['Python', 'SQL', 'Java', 'C++', 'JavaScript']
pos = np.arange(len(languages))
popularity = [56, 39, 34, 34, 29]

plt.bar(pos, popularity, align='center')
plt.xticks(pos, languages)
plt.ylabel('% Popularity')
plt.title('Top 5 Languages for Math &amp; Data \nby % popularity on Stack Overflow', 
alpha=0.8)

# remove all the ticks (both axes), 
plt.tick_params(top='off', bottom='off', left='off', right='off', labelleft='off', 
labelbottom='on')
plt.show()
</code></pre>

blocks|key|3035|text|目前遇到了同样的问题，在3.3.3版本中解决如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3036|#+My+matplotlib+ver:+3.3.3

ax.tick_params(tick1On=False)+#+"for+left+and+bottom+ticks"
ax.tick_params(tick2On=False)+#+"for+right+and+top+ticks,+which+are+off+by+default"|code-block|syntax|javascript|3037|示例：|3038|fig,+ax+=+plt.subplots()
ax.plot([1,+2,+3,+4,+5],+[1,+2,+3,+4,+5])
ax.tick_params(tick1On=False)
plt.show()|3039|输出：|3040|📷|atomic|offset|length|3041|​|3042|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/6af6e2ab8d918de29e409918c9cdfe7a.png|imageAlt^0|0|0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|16|8|@]|9|@]|A|$]]|$1|M|3|N|5|O|7|17|8|@]|9|@$P|18|Q|19|1|1A]]|A|$]]|$1|R|3|S|5|6|7|1B|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|U|$V|$5|W|X|Y|A|$Z|10|11|-4]]]]

Currently came across the same issue, solved as follows on version 3.3.3:
<pre><code># My matplotlib ver: 3.3.3

ax.tick_params(tick1On=False) # &quot;for left and bottom ticks&quot;
ax.tick_params(tick2On=False) # &quot;for right and top ticks, which are off by default&quot;
</code></pre>
Example:
<pre><code>fig, ax = plt.subplots()
ax.plot([1, 2, 3, 4, 5], [1, 2, 3, 4, 5])
ax.tick_params(tick1On=False)
plt.show()
</code></pre>
Output:
<a href="https://i.stack.imgur.com/IjgcZ.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/IjgcZ.png" alt="output" /></a>

blocks|key|4510476|text|假设要移除Y轴上的一些刻度，而只显示与值大于0的刻度相对应的yticks，则可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4510477|from+import+matplotlib.pyplot+as+plt

fig,+ax+=+plt.subplots()

#+yticks+and+yticks+labels
yTicks+=+list(range(26))
yTicks+=+[yTick+if+yTick+%25+5+==+0+else+0+for+yTick+in+yTicks]
yTickLabels+=+[str(yTick)+if+yTick+%25+5+==+0+else+''+for+yTick+in+yTicks]|code-block|syntax|javascript|4510478|然后设置轴对象的Y轴，如下所示：|4510479|ax.yaxis.grid(True)
ax.set_yticks(yTicks)
ax.set_yticklabels(yTickLabels,+fontsize=6)
fig.savefig('temp.png')
plt.close()|4510480|你会得到一个像这样的图：|4510481|​|4510482|📷|atomic|4510483|4510484|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/16f0bac42498181a63dddf10719a3ea4.png|imageAlt^0|5|1|U|6|0|0|8|1|0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1F|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1G|8|@]|D|@]|E|$]]|$1|S|3|T|5|U|7|1H|8|@]|D|@$9|1I|A|1J|1|1K]]|E|$]]|$1|V|3|R|5|6|7|1L|8|@]|D|@]|E|$]]|$1|W|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13|14|-4]]]]

Assuming that you want to remove some ticks on the <code>Y</code> axes and only show the <code>yticks</code> that correspond to the ticks that have values higher than 0 you can do the following:

<pre><code>from import matplotlib.pyplot as plt

fig, ax = plt.subplots()

# yticks and yticks labels
yTicks = list(range(26))
yTicks = [yTick if yTick % 5 == 0 else 0 for yTick in yTicks]
yTickLabels = [str(yTick) if yTick % 5 == 0 else '' for yTick in yTicks]
</code></pre>

Then you set up your axis object's <code>Y</code> axes as follow:

<pre><code>ax.yaxis.grid(True)
ax.set_yticks(yTicks)
ax.set_yticklabels(yTickLabels, fontsize=6)
fig.savefig('temp.png')
plt.close()
</code></pre>

And you'll get a plot like this:

<a href="https://i.stack.imgur.com/P1v91.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/P1v91.png" alt="enter image description here"></a>

I can remove the ticks with

<pre><code>ax.set_xticks([]) 
ax.set_yticks([]) 
</code></pre>

but this removes the labels as well. Any way I can plot the tick labels but not the ticks and the spine

Python hide ticks but show tick labels

Python

Java

我可以用下面的命令去掉扁虫ax.set_xticks([]) ax.set_yticks([]) 但这也删除了标签。无论如何，我可以绘制刻度标签，但不能绘制刻度和脊椎

问Python隐藏刻度，但显示刻度标签
EN

回答 9

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问Python隐藏刻度，但显示刻度标签EN

回答 9

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问Python隐藏刻度，但显示刻度标签
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