blocks|key|1547980|text|NerdDinner在这方面有一些很好的例子。下面是NerdDinner中的SearchController，它有一个名为SearchByLocation的方法，该方法返回一个JsonDinners列表(+NerdDinner的source+code是知识共享)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1547981|namespace+NerdDinner.Controllers+{

++++public+class+JsonDinner+{
++++++++public+int++++++DinnerID++++{+get;+set;+}
++++++++public+string+++Title+++++++{+get;+set;+}
++++++++public+double+++Latitude++++{+get;+set;+}
++++++++public+double+++Longitude+++{+get;+set;+}
++++++++public+string+++Description+{+get;+set;+}
++++++++public+int++++++RSVPCount+++{+get;+set;+}
++++}

++++public+class+SearchController+:+Controller+{

++++++++IDinnerRepository+dinnerRepository;

++++++++//
++++++++//+Dependency+Injection+enabled+constructors

++++++++public+SearchController()
++++++++++++:+this(new+DinnerRepository())+{
++++++++}

++++++++public+SearchController(IDinnerRepository+repository)+{
++++++++++++dinnerRepository+=+repository;
++++++++}

++++++++//
++++++++//+AJAX:+/Search/FindByLocation?longitude=45&latitude=-90

++++++++[AcceptVerbs(HttpVerbs.Post)]
++++++++public+ActionResult+SearchByLocation(float+latitude,+float+longitude)+{

++++++++++++var+dinners+=+dinnerRepository.FindByLocation(latitude,+longitude);

++++++++++++var+jsonDinners+=+from+dinner+in+dinners
++++++++++++++++++++++++++++++select+new+JsonDinner+{
++++++++++++++++++++++++++++++++++DinnerID+=+dinner.DinnerID,
++++++++++++++++++++++++++++++++++Latitude+=+dinner.Latitude,
++++++++++++++++++++++++++++++++++Longitude+=+dinner.Longitude,
++++++++++++++++++++++++++++++++++Title+=+dinner.Title,
++++++++++++++++++++++++++++++++++Description+=+dinner.Description,
++++++++++++++++++++++++++++++++++RSVPCount+=+dinner.RSVPs.Count
++++++++++++++++++++++++++++++};

++++++++++++return+Json(jsonDinners.ToList());
++++++++}
++++}
}|code-block|syntax|javascript|1547982|entityMap|0|LINK|mutability|MUTABLE|url|http://nerddinner.com/|1|http://nerddinner.codeplex.com/^0|0|A|0|36|B|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]|$A|W|B|X|1|Y]]|C|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]]]

<a href="http://nerddinner.com/" rel="nofollow noreferrer">NerdDinner</a> has some pretty good examples of this. Here is the SearchController in NerdDinner, which has a method called SearchByLocation that returns a list of JsonDinners
(<a href="http://nerddinner.codeplex.com/" rel="nofollow noreferrer">source code</a> for NerdDinner is Creative Commons):

<pre><code>namespace NerdDinner.Controllers {

 public class JsonDinner {
 public int DinnerID { get; set; }
 public string Title { get; set; }
 public double Latitude { get; set; }
 public double Longitude { get; set; }
 public string Description { get; set; }
 public int RSVPCount { get; set; }
 }

 public class SearchController : Controller {

 IDinnerRepository dinnerRepository;

 //
 // Dependency Injection enabled constructors

 public SearchController()
 : this(new DinnerRepository()) {
 }

 public SearchController(IDinnerRepository repository) {
 dinnerRepository = repository;
 }

 //
 // AJAX: /Search/FindByLocation?longitude=45&amp;latitude=-90

 [AcceptVerbs(HttpVerbs.Post)]
 public ActionResult SearchByLocation(float latitude, float longitude) {

 var dinners = dinnerRepository.FindByLocation(latitude, longitude);

 var jsonDinners = from dinner in dinners
 select new JsonDinner {
 DinnerID = dinner.DinnerID,
 Latitude = dinner.Latitude,
 Longitude = dinner.Longitude,
 Title = dinner.Title,
 Description = dinner.Description,
 RSVPCount = dinner.RSVPs.Count
 };

 return Json(jsonDinners.ToList());
 }
 }
}
</code></pre>

blocks|key|1332625|text|为什么不只使用静态html“部分”并从json中获取所有动态内容呢？当页面加载或需要时，您应该能够很容易地使用jquery加载html文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332626|JQuery+Ajax上的此链接提供了此示例：|offset|length|1332627|//Alert+out+the+results+from+requesting+test.php+(HTML+or+XML,+depending+on+what+was+returned).
$.get("test.php",+function(data){
++alert("Data+Loaded:+"+%2B+data);
});|code-block|syntax|javascript|1332628|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.jquery.com/Ajax/jQuery.get#urldatacallbacktype^0|0|0|B|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@$D|U|E|V|1|W]]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Why not just have static html "partials" and grab all the dynamic content from the json? You should be able to load the html files with jquery when the page loads or when needed quite easily.

This link on <a href="http://docs.jquery.com/Ajax/jQuery.get#urldatacallbacktype" rel="nofollow noreferrer">JQuery Ajax</a> gives this example:

<pre><code>//Alert out the results from requesting test.php (HTML or XML, depending on what was returned).
$.get("test.php", function(data){
 alert("Data Loaded: " + data);
});
</code></pre>

blocks|key|1332693|text|克雷格|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332694|看看这个。Jeffery+Palermo为ASP.NET+MVC编写了一个SubController，它应该可以完成您想要的功能：|1332695|MvcContrib+-现在支持ASP.NET+MVC的SubController：http://jeffreypalermo.com/blog/mvccontrib-now-with-subcontroller-support/|offset|length|1332696|entityMap|0|LINK|mutability|MUTABLE|url|http://jeffreypalermo.com/blog/mvccontrib-now-with-subcontroller-support/^0|0|0|16|21|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

Craig,

Have a look at this. Jeffery Palermo has written a SubController for ASP.NET MVC that should accomplish what you want:

MvcContrib - now with SubController support for ASP.NET MVC: 
<a href="http://jeffreypalermo.com/blog/mvccontrib-now-with-subcontroller-support/" rel="nofollow noreferrer">http://jeffreypalermo.com/blog/mvccontrib-now-with-subcontroller-support/</a>

blocks|key|1332760|text|这就是答案！与Martin+From's方法相比，这是一个细微的变化，而且似乎是有效的。如果有遗漏的东西，请人们在评论部分贡献任何代码更改。谢谢。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1332761|在你的控制器中，像这样调用它：|1332762|string+HTMLOutput+=+Utils.RenderPartialToString("~/Views/Setting/IndexMain.ascx",+"",+items,+this.ControllerContext.RequestContext);|code-block|syntax|javascript|1332763|将此代码添加到类中|1332764|public+static+string+RenderPartialToString(string+controlName,+object+viewData,+object+model,+System.Web.Routing.RequestContext+viewContext)
{
+++++ViewDataDictionary+vd+=+new+ViewDataDictionary(viewData);
+++++ViewPage+vp+=+new+ViewPage+{+ViewData+=+vd+};

+++++vp.ViewData+=+vd;
+++++vp.ViewData.Model+=+model;
+++++vp.ViewContext+=+new+ViewContext();
+++++vp.Url+=+new+UrlHelper(viewContext);

+++++Control+control+=+vp.LoadControl(controlName);

+++++vp.Controls.Add(control);

+++++StringBuilder+sb+=+new+StringBuilder();

+++++using+(StringWriter+sw+=+new+StringWriter(sb))
+++++using+(HtmlTextWriter+tw+=+new+HtmlTextWriter(sw))
+++++{
+++++++++vp.RenderControl(tw);
+++++}

+++++return+sb.ToString();
}|1332765|entityMap|0|LINK|mutability|MUTABLE|url|http://thriftybliss.spaces.live.com/blog/cns!58DA805F37F31F20!170.entry^0|7|D|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

Here is the answer! It is slight change from <a href="http://thriftybliss.spaces.live.com/blog/cns!58DA805F37F31F20!170.entry" rel="nofollow noreferrer">Martin From's</a> method and it seems to work. If there are things missing please can people contribute any code changes in the comments section. Thanks.

From you controller call it like this:

<pre><code>string HTMLOutput = Utils.RenderPartialToString("~/Views/Setting/IndexMain.ascx", "", items, this.ControllerContext.RequestContext);
</code></pre>

Add this to a class

<pre><code>public static string RenderPartialToString(string controlName, object viewData, object model, System.Web.Routing.RequestContext viewContext)
{
 ViewDataDictionary vd = new ViewDataDictionary(viewData);
 ViewPage vp = new ViewPage { ViewData = vd };

 vp.ViewData = vd;
 vp.ViewData.Model = model;
 vp.ViewContext = new ViewContext();
 vp.Url = new UrlHelper(viewContext);

 Control control = vp.LoadControl(controlName);

 vp.Controls.Add(control);

 StringBuilder sb = new StringBuilder();

 using (StringWriter sw = new StringWriter(sb))
 using (HtmlTextWriter tw = new HtmlTextWriter(sw))
 {
 vp.RenderControl(tw);
 }

 return sb.ToString();
}
</code></pre>

blocks|key|1548179|text|我正在使用本文中的HTML+Helper：Render+partial+view+to+string+in+ASP.NET+MVC。它工作得很完美！|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1548180|entityMap|0|LINK|mutability|MUTABLE|url|http://www.klopfenstein.net/lorenz.aspx/render-partial-view-to-string-in-asp-net-mvc^0|L|18|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

I am using the HTML Helper from this article: <a href="http://www.klopfenstein.net/lorenz.aspx/render-partial-view-to-string-in-asp-net-mvc" rel="nofollow noreferrer">Render partial view to string in ASP.NET MVC</a>. It works perfectly!

blocks|key|1332850|text|这是一个很好的问题解决方案：http://craftycode.wordpress.com/2010/05/15/asp-net-mvc-render-partial-view-to-string/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1332851|entityMap|0|LINK|mutability|MUTABLE|url|http://craftycode.wordpress.com/2010/05/15/asp-net-mvc-render-partial-view-to-string/^0|E|2D|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

This is a good solution to the problem:
<a href="http://craftycode.wordpress.com/2010/05/15/asp-net-mvc-render-partial-view-to-string/" rel="nofollow noreferrer">http://craftycode.wordpress.com/2010/05/15/asp-net-mvc-render-partial-view-to-string/</a>

blocks|key|1332909|text|我用Razor找到了一个更新的答案，这可能对http://codepaste.net/8xkoj2很有帮助|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1332910|public+static+string+RenderViewToString(string+viewPath,+object+model,ControllerContext+context)
{++++++++++++
++++var+viewEngineResult+=+ViewEngines.Engines.FindView(context,+viewPath,+null);
++++var+view+=+viewEngineResult.View;


++++context.Controller.ViewData.Model+=+model;

++++string+result+=+String.Empty;
++++using+(var+sw+=+new+StringWriter())
++++{

++++++++var+ctx+=+new+ViewContext(context,+view,+
++++++++++++++++++++++++++++++++++context.Controller.ViewData,+
++++++++++++++++++++++++++++++++++context.Controller.TempData,+
++++++++++++++++++++++++++++++++++sw);
++++++++view.Render(ctx,+sw);

++++++++result+=+sw.ToString();
++++}

++++return+result;
}|code-block|syntax|javascript|1332911|entityMap|0|LINK|mutability|MUTABLE|url|http://codepaste.net/8xkoj2^0|M|R|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

I found a more recent answer using Razor that may be helpful <a href="http://codepaste.net/8xkoj2" rel="nofollow">http://codepaste.net/8xkoj2</a>

<pre><code>public static string RenderViewToString(string viewPath, object model,ControllerContext context)
{ 
 var viewEngineResult = ViewEngines.Engines.FindView(context, viewPath, null);
 var view = viewEngineResult.View;


 context.Controller.ViewData.Model = model;

 string result = String.Empty;
 using (var sw = new StringWriter())
 {

 var ctx = new ViewContext(context, view, 
 context.Controller.ViewData, 
 context.Controller.TempData, 
 sw);
 view.Render(ctx, sw);

 result = sw.ToString();
 }

 return result;
}
</code></pre>

blocks|key|1332966|text|我不知道哪个版本可以做到这一点，但现在你可以用一种非常简单的方式返回JSON：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332967|public+ActionResult+JSONaction()
{
++++return+Json(data,+JsonRequestBehavior);
}|code-block|syntax|javascript|1332968|不需要精心设计的帮手等。|1332969|数据当然是您模型中的数据JsonRequestBehavior指定是否允许来自客户端的HTTP+GET请求。(source)是可选的，DenyGet是默认行为，所以如果主要使用JsonRequestBehavior.AllowGet和here，这就是为什么会出现这种情况|offset|length|style|CODE|1332970|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.web.mvc.jsonrequestbehavior%2528v=vs.108%2529.aspx|1|https://stackoverflow.com/questions/8464677/why-is-jsonrequestbehavior-needed^0|0|0|0|1V|7|2G|S|1J|6|0|39|4|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|11|8|@$K|12|L|13|M|N]|$K|14|L|15|M|N]]|9|@$K|16|L|17|1|18]|$K|19|L|1A|1|1B]]|A|$]]|$1|O|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

I don not know since which version number you can do this, but nowadays you can return JSON in a very simple way:

<pre><code>public ActionResult JSONaction()
{
 return Json(data, JsonRequestBehavior);
}
</code></pre>

no need for elaborate helpers etc.

data is of course your data from your model
JsonRequestBehavior specifies whether HTTP GET requests from the client are allowed. (<a href="http://msdn.microsoft.com/en-us/library/system.web.mvc.jsonrequestbehavior%28v=vs.108%29.aspx" rel="nofollow noreferrer">source</a>), is optional <code>DenyGet</code> is default behaviour, so if used mostly <code>JsonRequestBehavior.AllowGet</code> and <a href="https://stackoverflow.com/questions/8464677/why-is-jsonrequestbehavior-needed">here</a> is why this is in there

I have a MVC app with quite a few Controller Actions that are called using Ajax (jQuery) and return partial views content which updates a part of the screen. But what I would rather do is return JSON something like this.

<pre><code>return Json(new { 
 Result = true, 
 Message = "Item has been saved", 
 Content = View("Partial") 
});
</code></pre>

Where the HTML is just a property of the Json. What this means is I need to retrieve the HTML that is rendered by the View method. Is there any easy way to do this, a few examples I have seen are quite convoluted.

Edit: This question was originally for ASP.NET MVC 1, but if version 2 makes it easier I would like to hear the answer.

ASP MVC View Content as JSON

jQuery

JSON

我有一个MVC应用程序，有相当多的控制器操作，使用Ajax (jQuery)调用，并返回部分视图内容，更新屏幕的一部分。但我更愿意做的是返回类似这样的JSON。return Json(new {     Result = true,     Message = "Item has been saved",     Co...

问ASP MVC以JSON格式查看内容
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