我有一个带有删除标志的简单表(应该更新此列中的记录,而不是删除):
create table PSEUDODELETETABLE
(
ID NUMBER(8) not null, -- PKEY
NAME VARCHAR2(50) not null,
ISDELETED NUMBER(1) default 0 not null
)
在插入新记录时,我必须检查是否已经存在与主键匹配但ISDELETED = 1的记录。在这种情况下,我必须将ISDELETED更改为0并更新其他列。因此,我使用下面的Merge语句:
merge into ET.PSEUDODELETETABLE TARGET
using (select 1 as ID, 'Horst' as NAME from sys.dual) SOURCE
on (TARGET.ISDELETED = 1 and SOURCE.ID = TARGET.ID)
when matched then
update set ISDELETED = 0, NAME = SOURCE.NAME
when not matched then
insert values (SOURCE.ID, SOURCE.NAME, 0);
在Sql-Server上,它工作得很好,但Oracle说:
ORA-38104: Columns referenced in the ON Clause cannot be updated: TARGET.ISDELETED
如果存在IDELETED = 0的匹配记录,我希望主键冲突成为异常,这就是为什么我不能将"TARGET.ISDELETED = 1“从on-子句移动到update-语句。
发布于 2011-11-29 06:24:23
与接受的响应相反,实际上有一种方法可以做到这一点:将有问题的部分移出ON子句,放入update语句的WHERE子句中:
merge into ET.PSEUDODELETETABLE TARGET
using (select 1 as ID, 'Horst' as NAME from sys.dual) SOURCE
on (SOURCE.ID = TARGET.ID)
when matched then
update
set ISDELETED = 0,
NAME = SOURCE.NAME
where TARGET.ISDELETED = 1 -- Magic!
when not matched then
insert
values (SOURCE.ID, SOURCE.NAME, 0);
发布于 2016-03-05 09:08:36
我们还需要考虑下面的场景,
如果有一个与IDELETED = 0
匹配的记录,我希望主键冲突是一个异常,这就是为什么我不能将"TARGET.ISDELETED = 1“从on-子句移动到update-语句。
所以确切的解决方案如下所示,
begin
update ET.PSEUDODELETETABLE set ISDELETED = 0, NAME = 'Horst'
where ISDELETED = 1 and ID = 1;
if (sql%rowcount = 0) then
insert into ET.PSEUDODELETETABLE values (1, 'Horst', 0);
end if;
end;
发布于 2019-01-02 23:14:56
这不就行了吗?
merge into (select * from ET.PSEUDODELETETABLE where ISDELETED = 1) TARGET
using (select 1 as ID, 'Horst' as NAME from sys.dual) SOURCE
on (SOURCE.ID = TARGET.ID)
when matched then
update set ISDELETED = 0, NAME = SOURCE.NAME
when not matched then
insert values (SOURCE.ID, SOURCE.NAME, 0);
https://stackoverflow.com/questions/5900912
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