blocks|key|1331796|text|var+numbers+=+sNumbers.Split(',').Select(Int32.Parse).ToList();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1331797|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var numbers = sNumbers.Split(',').Select(Int32.Parse).ToList();
</code></pre>

blocks|key|1547168|text|您也可以在不需要Linq的情况下这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1547169|List<int>+numbers+=+new+List<int>(+Array.ConvertAll(sNumbers.Split(','),+int.Parse)+);

//+Uses+Linq
var+numbers+=+Array.ConvertAll(sNumbers.Split(','),+int.Parse).ToList();|code-block|syntax|javascript|1547170|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can also do it this way without the need of Linq:

<pre><code>List&lt;int&gt; numbers = new List&lt;int&gt;( Array.ConvertAll(sNumbers.Split(','), int.Parse) );

// Uses Linq
var numbers = Array.ConvertAll(sNumbers.Split(','), int.Parse).ToList();
</code></pre>

blocks|key|1547462|text|最好使用int.TryParse来避免异常；|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1547463|var+numbers+=+sNumbers
++++++++++++.Split(',')
++++++++++++.Where(x+=>+int.TryParse(x,+out+_))
++++++++++++.Select(int.Parse)
++++++++++++.ToList();|code-block|syntax|javascript|1547464|entityMap^0|4|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Better use <code>int.TryParse</code> to avoid exceptions;

<pre><code>var numbers = sNumbers
 .Split(',')
 .Where(x =&gt; int.TryParse(x, out _))
 .Select(int.Parse)
 .ToList();
</code></pre>

blocks|key|1331886|text|Joze的方式也需要LINQ，ToList()在System.Linq命名空间中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1331887|通过将数组传递给列表构造函数，可以将Array转换为不带Linq的List：|1331888|List<int>+numbers+=+new+List<int>(+Array.ConvertAll(sNumbers.Split(','),+int.Parse)+);|code-block|syntax|javascript|1331889|entityMap^0|F|8|O|B|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|U|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Joze's way also need LINQ, <code>ToList()</code> is in <code>System.Linq</code> namespace.

You can convert Array to List without Linq by passing the array to List constructor:

<pre class="lang-cs prettyprint-override"><code>List&lt;int&gt; numbers = new List&lt;int&gt;( Array.ConvertAll(sNumbers.Split(','), int.Parse) );
</code></pre>

blocks|key|1332099|text|也可以使用int数组来直接赋值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332100|像这样|1332101|int[]+numbers+=+sNumbers.Split(',').Select(Int32.Parse).ToArray();|code-block|syntax|javascript|1332102|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

It is also possible to int array to direct assign value.

like this

<pre><code>int[] numbers = sNumbers.Split(',').Select(Int32.Parse).ToArray();
</code></pre>

blocks|key|1547302|text|您还可以使用此扩展方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1547303|public+static+List<int>+SplitToIntList(this+string+list,+char+separator+=+',')
{
++++return+list.Split(separator).Select(Int32.Parse).ToList();
}|code-block|syntax|javascript|1547304|用法：|1547305|var+numberListString+=+"1,+2,+3,+4";
List<int>+numberList+=+numberListString.SplitToIntList(',');|1547306|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

also you can use this Extension method

<pre><code>public static List&lt;int&gt; SplitToIntList(this string list, char separator = ',')
{
 return list.Split(separator).Select(Int32.Parse).ToList();
}
</code></pre>

usage: 

<pre><code>var numberListString = "1, 2, 3, 4";
List&lt;int&gt; numberList = numberListString.SplitToIntList(',');
</code></pre>

blocks|key|1331978|text|在Unity3d上，int.Parse不能很好地工作。所以我用了像bellow。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1331979|List<int>+intList+=+new+List<int>(+Array.ConvertAll(sNumbers.Split(','),
+new+Converter<string,+int>((s)=>{return+Convert.ToInt32(s);})+)+);|code-block|syntax|javascript|1331980|希望这对Unity3d用户有帮助。|1331981|entityMap^0|A|9|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

On Unity3d, <code>int.Parse</code> doesn't work well. So I use like bellow.

<pre><code>List&lt;int&gt; intList = new List&lt;int&gt;( Array.ConvertAll(sNumbers.Split(','),
 new Converter&lt;string, int&gt;((s)=&gt;{return Convert.ToInt32(s);}) ) );
</code></pre>

Hope this help for Unity3d Users.

blocks|key|1332074|text|我的问题类似，但有时字符串包含字母(有时是空的)，这带来了不便。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332075|string+sNumbers+=+"1,2,hh,3,4,x,5";|code-block|syntax|javascript|1332076|正在尝试遵循Pcode+Xonos扩展方法：|1332077|public+static+List<int>+SplitToIntList(this+string+list,+char+separator+=+',')
{
++++++int+result+=+0;
++++++return+(from+s+in+list.Split(',')
++++++++++++++let+isint+=+int.TryParse(s,+out+result)
++++++++++++++let+val+=+result
++++++++++++++where+isint
++++++++++++++select+val).ToList();+
}|1332078|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

My problem was similar but with the inconvenience that sometimes the string contains letters (sometimes empty). 

<pre><code>string sNumbers = "1,2,hh,3,4,x,5";
</code></pre>

Trying to follow Pcode Xonos Extension Method:

<pre><code>public static List&lt;int&gt; SplitToIntList(this string list, char separator = ',')
{
 int result = 0;
 return (from s in list.Split(',')
 let isint = int.TryParse(s, out result)
 let val = result
 where isint
 select val).ToList(); 
}
</code></pre>

blocks|key|1332166|text|当我们有泛型的时候，为什么只使用int呢？像这样的扩展方法怎么样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1332167|++++public+static+List<T>+Split<T>(this+string+@this,+char+separator,+out+bool+AllConverted)
++++{
++++++++List<T>+returnVals+=+new+List<T>();
++++++++AllConverted+=+true;
++++++++var+itens+=+@this.Split(separator);
++++++++foreach+(var+item+in+itens)
++++++++{
++++++++++++try
++++++++++++{
++++++++++++++++returnVals.Add((T)Convert.ChangeType(item,+typeof(T)));
++++++++++++}
++++++++++++catch+{+AllConverted+=+false;+}
++++++++}
++++++++return+returnVals;
++++}|code-block|syntax|javascript|1332168|然后|1332169|+string+testString+=+"1,+2,+3,+XP,+*,+6";
+List<int>+splited+=+testString.Split<int>(',',+out+_);|1332170|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Why stick with just int when we have generics?
What about an extension method like :
<pre><code> public static List&lt;T&gt; Split&lt;T&gt;(this string @this, char separator, out bool AllConverted)
 {
 List&lt;T&gt; returnVals = new List&lt;T&gt;();
 AllConverted = true;
 var itens = @this.Split(separator);
 foreach (var item in itens)
 {
 try
 {
 returnVals.Add((T)Convert.ChangeType(item, typeof(T)));
 }
 catch { AllConverted = false; }
 }
 return returnVals;
 }
</code></pre>
and then
<pre><code> string testString = &quot;1, 2, 3, XP, *, 6&quot;;
 List&lt;int&gt; splited = testString.Split&lt;int&gt;(',', out _);
</code></pre>

blocks|key|1547408|text|您可以使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1547409|List<Int32>+sNumberslst+=+sNumbers.Split(',').ConvertIntoIntList();|code-block|syntax|javascript|1547410|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this: 

<pre><code>List&lt;Int32&gt; sNumberslst = sNumbers.Split(',').ConvertIntoIntList();
</code></pre>

I have a string that has numbers

<pre><code>string sNumbers = "1,2,3,4,5";
</code></pre>

I can split it then convert it to <code>List&lt;int&gt;</code>

<pre><code>sNumbers.Split( new[] { ',' } ).ToList&lt;int&gt;();
</code></pre>

How can I convert string array to integer list?
So that I'll be able to convert <code>string[]</code> to <code>IEnumerable</code>

Split string, convert ToList<int>() in one line

我有一个包含数字的字符串string sNumbers = "1,2,3,4,5";我可以拆分它，然后将它转换为List<int>sNumbers.Split( new[] { ',' } ).ToList<int>();如何将字符串数组转换为整数列表？这样我就可以将string[]转换为IEnumerable

问拆分字符串，将ToList<int>()转换为一行
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