blocks|key|1533548|text|是的，struct与class非常相似，除了struct的默认可访问性是public+(而class的默认可访问性是private+)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1533549|entityMap^0|3|6|A|5|M|6|10|6|19|5|1M|7|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|G|$]]

Yes, <code>struct</code> is exactly like <code>class</code> except the default accessibility is <code>public</code> for <code>struct</code> (while it's <code>private</code> for <code>class</code>).

blocks|key|1318407|text|是。默认情况下，继承是公共的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1318408|语法(示例)：|1318409|struct+A+{+};
struct+B+:+A+{+};
struct+C+:+B+{+};|code-block|syntax|javascript|1318410|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Yes. The inheritance is public by default.

Syntax (example):

<pre><code>struct A { };
struct B : A { };
struct C : B { };
</code></pre>

blocks|key|1533665|text|除了亚历克斯和埃文已经说过的以外，我想补充说，C%2B%2B结构与C结构不同。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1533666|在C%2B%2B中，结构可以像C%2B%2B类一样具有方法、继承等。|1533667|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Other than what Alex and Evan have already stated, I would like to add that a C++ struct is not like a C struct.

In C++, a struct can have methods, inheritance, etc. just like a C++ class.

blocks|key|1533693|text|在C%2B%2B中，除了以下区别之外，结构的继承与类相同：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1533694|从类/结构派生结构时，基类/结构的默认访问说明符是public。在派生类时，默认访问说明符是private。|1533695|例如，程序1由于编译错误而失败，而程序2工作正常。|1533696|//+Program+1
#include+<stdio.h>

class+Base+{
++++public:
++++++++int+x;
};

class+Derived+:+Base+{+};+//+Is+equivalent+to+class+Derived+:+private+Base+{}

int+main()
{
++++Derived+d;
++++d.x+=+20;+//+Compiler+error+because+inheritance+is+private
++++getchar();
++++return+0;
}

//+Program+2
#include+<stdio.h>

struct+Base+{
++++public:
++++++++int+x;
};

struct+Derived+:+Base+{+};+//+Is+equivalent+to+struct+Derived+:+public+Base+{}

int+main()
{
++++Derived+d;
++++d.x+=+20;+//+Works+fine+because+inheritance+is+public
++++getchar();
++++return+0;
}|code-block|syntax|javascript|1533697|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

In C++, a structure's inheritance is the same as a class except the following differences:

When deriving a struct from a class/struct, the default access-specifier for a base class/struct is public. And when deriving a class, the default access specifier is private.

For example, program 1 fails with a compilation error and program 2 works fine.

<pre><code>// Program 1
#include &lt;stdio.h&gt;

class Base {
 public:
 int x;
};

class Derived : Base { }; // Is equivalent to class Derived : private Base {}

int main()
{
 Derived d;
 d.x = 20; // Compiler error because inheritance is private
 getchar();
 return 0;
}

// Program 2
#include &lt;stdio.h&gt;

struct Base {
 public:
 int x;
};

struct Derived : Base { }; // Is equivalent to struct Derived : public Base {}

int main()
{
 Derived d;
 d.x = 20; // Works fine because inheritance is public
 getchar();
 return 0;
}
</code></pre>

blocks|key|1318366|text|当然了。在C%2B%2B中，结构和类几乎是相同的(比如缺省为公有而不是私有是细微的区别)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1318367|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Of course. In C++, structs and classes are nearly identical (things like defaulting to public instead of private are among the small differences).

blocks|key|1318510|text|是的，c%2B%2B结构与c%2B%2B类非常相似，不同之处在于一切都是公开继承的(单/多级/分层继承，但不是混合和多重继承)以下是演示代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1318511|#include<bits/stdc%2B%2B.h>
using+namespace+std;

struct+parent
{
++++int+data;
++++parent()+:+data(3){};+++++++++++//+default+constructor
++++parent(int+x)+:+data(x){};++++++//+parameterized+constructor
};
struct+child+:+parent
{
++++int+a+,+b;
++++child():+a(1)+,+b(2){};+++++++++++++//+default+constructor
++++child(int+x,+int+y)+:+a(x)+,+b(y){};//+parameterized+constructor
++++child(int+x,+int+y,int+z)+++++++++++//+parameterized+constructor
++++{
++++++++a+=+x;
++++++++b+=+y;
++++++++data+=+z;
++++}
++++child(const+child+&C)+++++++++++++++//+copy+constructor
++++{
++++++++a+=+C.a;
++++++++b+=+C.b;
++++++++data+=+C.data;
++++}
};
int+main()
{
+++child+c1+,
+++++++++c2(10+,+20),
+++++++++c3(10+,+20,+30),
+++++++++c4(c3);

++++auto+print+=+[](const+child+&c)+{+cout<<c.a<<"\t"<<c.b<<"\t"<<c.data<<endl;+};

++++print(c1);
++++print(c2);
++++print(c3);
++++print(c4);
}
OUTPUT+
1+++++++2+++++++3
10++++++20++++++3
10++++++20++++++30
10++++++20++++++30|code-block|syntax|javascript|1318512|​|1318513|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Yes, c++ struct is very similar to c++ class, except the fact that everything is publicly inherited, ( single / multilevel / hierarchical inheritance, but not hybrid and multiple inheritance )
here is a code for demonstration
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-css lang-css prettyprint-override"><code>#include&lt;bits/stdc++.h&gt;
using namespace std;

struct parent
{
 int data;
 parent() : data(3){}; // default constructor
 parent(int x) : data(x){}; // parameterized constructor
};
struct child : parent
{
 int a , b;
 child(): a(1) , b(2){}; // default constructor
 child(int x, int y) : a(x) , b(y){};// parameterized constructor
 child(int x, int y,int z) // parameterized constructor
 {
 a = x;
 b = y;
 data = z;
 }
 child(const child &amp;C) // copy constructor
 {
 a = C.a;
 b = C.b;
 data = C.data;
 }
};
int main()
{
 child c1 ,
 c2(10 , 20),
 c3(10 , 20, 30),
 c4(c3);

 auto print = [](const child &amp;c) { cout&lt;&lt;c.a&lt;&lt;"\t"&lt;&lt;c.b&lt;&lt;"\t"&lt;&lt;c.data&lt;&lt;endl; };

 print(c1);
 print(c2);
 print(c3);
 print(c4);
}
OUTPUT 
1 2 3
10 20 3
10 20 30
10 20 30</code></pre>
</div>
</div>

Can a <code>struct</code> be inherited in C++?

问C++中的结构继承
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回答 6

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