blocks|key|360457|text|您需要一个遵循C99标准或更高版本的C编译器。有一个名为__func__的预定义标识符，它可以执行您所要求的操作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|360458|void+func+(void)
{
++printf("%25s",+__func__);
}|code-block|syntax|javascript|360459|编辑：|360460|作为一个奇怪的参考，C标准6.4.2.2规定上面的代码与您显式编写的代码完全相同：|360461|void+func+(void)
{
++static+const+char+f+[]+=+"func";+//+where+func+is+the+function's+name
++printf("%25s",+f);
}|360462|编辑2：|360463|因此，为了通过函数指针获取名称，您可以构造如下内容：|360464|const+char*+func+(bool+whoami,+...)
{
++const+char*+result;

++if(whoami)
++{
++++result+=+__func__;
++}
++else
++{
++++do_work();
++++result+=+NULL;
++}

++return+result;
}

int+main()
{
++typedef+const+char*(*func_t)(bool+x,+...);+
++func_t+function+[N]+=+...;+//+array+of+func+pointers

++for(int+i=0;+i<N;+i%2B%2B)
++{
++++printf("%25s",+function[i](true,+...);
++}
}|360465|entityMap^0|S|8|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|13|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|15|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|16|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|W|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|X|$]]

You need a C compiler that follows the C99 standard or later. There is a pre-defined identifier called <code>__func__</code> which does what you are asking for.

<pre><code>void func (void)
{
 printf("%s", __func__);
}
</code></pre>

Edit:

As a curious reference, the C standard 6.4.2.2 dictates that the above is exactly the same as if you would have explicitly written:

<pre><code>void func (void)
{
 static const char f [] = "func"; // where func is the function's name
 printf("%s", f);
}
</code></pre>

Edit 2:

So for getting the name through a function pointer, you could construct something like this:

<pre><code>const char* func (bool whoami, ...)
{
 const char* result;

 if(whoami)
 {
 result = __func__;
 }
 else
 {
 do_work();
 result = NULL;
 }

 return result;
}

int main()
{
 typedef const char*(*func_t)(bool x, ...); 
 func_t function [N] = ...; // array of func pointers

 for(int i=0; i&lt;N; i++)
 {
 printf("%s", function[i](true, ...);
 }
}
</code></pre>

blocks|key|360505|text|我不确定这是不是你想要的，但你可以这样做。声明一个结构来保存函数名和地址，以及文件范围内的函数数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|360506|#define+FNUM+3

struct+fnc+{
++++void+*addr;
++++char+name[32];
};

void+(*f[FNUM])();
struct+fnc+fnames[FNUM];|code-block|syntax|javascript|360507|在你的代码中通过函数名手动初始化它们，例如|360508|++++fnames[0]+=+(struct+fnc){foo1,+"foo1"};+//+function+address+%2B+its+name
++++fnames[1]+=+(struct+fnc){foo2,+"foo2"};
++++fnames[2]+=+(struct+fnc){foo3,+"foo3"};|360509|创建一个函数来搜索数组，例如|360510|char+*getfname(void+*p)
{
++++++++for+(int+i+=+0;+i+<+FNUM;+i%2B%2B)+{
++++++++++++++++if+(fnames[i].addr+==+p)
++++++++++++++++++++++++return+fnames[i].name;
++++++++}
++++++++return+NULL;
}|360511|我对此进行了快速测试。我在main中初始化了数组，并调用了foo1()。下面是我的函数和输出：|offset|length|style|CODE|360512|void+foo1(void)
{
++++printf("The+pointer+of+the+current+function+is+%25p\n",+getfnp(__func__));
++++printf("The+name+of+this+function+is+%25s\n",+getfname(getfnp(__func__)));
++++printf("The+name+of+the+function+at+pointer+f[2]+(%25p)+is+'%25s'\n",+f[2],
++++++++getfname(f[2]));++++
}

The+pointer+of+the+current+function+is+0x400715
The+name+of+this+function+is+foo1
The+name+of+the+function+at+pointer+f[2]+(0x40078c)+is+'foo3'|360513|或者，更一般地说：|360514|void+foo2(void)
{
++++for+(int+i+=+0;+i+<+FNUM;+i%2B%2B)+{
++++++++printf("Function+f[%25d]+is+called+'%25s'\n",+i,+getfname(f[i]));
++++}
}

Function+f[0]+is+called+'foo1'
Function+f[1]+is+called+'foo2'
Function+f[2]+is+called+'foo3'|360515|entityMap^0|0|0|0|0|0|0|D|4|T|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|16|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|18|8|@$Q|19|R|1A|S|T]|$Q|1B|R|1C|S|T]]|9|@]|A|$]]|$1|U|3|V|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1E|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|10|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]]|11|$]]

I'm not sure this is what you want, but you could do something like this. Declare a structure to hold a function name and address, and an array of functions at file scope:

<pre><code>#define FNUM 3

struct fnc {
 void *addr;
 char name[32];
};

void (*f[FNUM])();
struct fnc fnames[FNUM];
</code></pre>

Initialise these in your code manually by function name, e.g.

<pre><code> fnames[0] = (struct fnc){foo1, "foo1"}; // function address + its name
 fnames[1] = (struct fnc){foo2, "foo2"};
 fnames[2] = (struct fnc){foo3, "foo3"};
</code></pre>

Make a function to search the array, e.g.

<pre><code>char *getfname(void *p)
{
 for (int i = 0; i &lt; FNUM; i++) {
 if (fnames[i].addr == p)
 return fnames[i].name;
 }
 return NULL;
}
</code></pre>

I ran a quick test of this. I initialised the array in <code>main</code>, and called <code>foo1()</code>. Here's my function, and the output:

<pre><code>void foo1(void)
{
 printf("The pointer of the current function is %p\n", getfnp(__func__));
 printf("The name of this function is %s\n", getfname(getfnp(__func__)));
 printf("The name of the function at pointer f[2] (%p) is '%s'\n", f[2],
 getfname(f[2])); 
}

The pointer of the current function is 0x400715
The name of this function is foo1
The name of the function at pointer f[2] (0x40078c) is 'foo3'
</code></pre>

Or, more generally:

<pre><code>void foo2(void)
{
 for (int i = 0; i &lt; FNUM; i++) {
 printf("Function f[%d] is called '%s'\n", i, getfname(f[i]));
 }
}

Function f[0] is called 'foo1'
Function f[1] is called 'foo2'
Function f[2] is called 'foo3'
</code></pre>

I'd like to display the name of a function I'm calling. Here is my code

<pre><code>void (*tabFtPtr [nbExo])(); // Array of function pointers
int i;
for (i = 0; i &lt; nbExo; ++i)
{
 printf ("%d - %s", i, __function__);
}
</code></pre>

I used <code>__function__</code> as an exemple because it's pretty close from what I'd like but I want to display the name of the function pointed by <code>tabFtPtr [nbExo]</code>.

Thanks for helping me :)

Get called function name as string

编译器

我想要显示我正在调用的函数的名称。以下是我的代码void (*tabFtPtr [nbExo])(); // Array of function pointersint i;for (i = 0; i < nbExo; ++i){ printf ("%d - %s", i, __function__);}我使用_...

问以字符串形式获取被调用的函数名
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