我想要获取自上个午夜以来过期的秒数。Python中最优雅的方式是什么?
发布于 2013-04-12 20:31:42
最好是对返回当前日期/时间的函数进行一次调用:
from datetime import datetime
now = datetime.now()
seconds_since_midnight = (now - now.replace(hour=0, minute=0, second=0, microsecond=0)).total_seconds()
或者确实是
datetime.now() - datetime.now()
为这里的任何人返回零时间增量?
发布于 2013-04-12 20:30:55
import datetime
now = datetime.datetime.now()
midnight = now.replace(hour=0, minute=0, second=0, microsecond=0)
seconds = (now - midnight).seconds
或
import datetime
now = datetime.datetime.now()
midnight = datetime.datetime.combine(now.date(), datetime.time())
seconds = (now - midnight).seconds
选择哪一个是品味问题。
发布于 2013-04-12 20:22:44
我会这样做:
import datetime
import time
today = datetime.date.today()
seconds_since_midnight = time.time() - time.mktime(today.timetuple())
https://stackoverflow.com/questions/15971308
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