如何知道.keyup()是否是字符键(jQuery)
如何知道.keyup()是否是字符键(jQuery)
提问于 2010-10-20 20:16:02
如何知道.keyup()是否是字符键(jQuery)
$("input").keyup(function() {
if (key is a character) { //such as a b A b c 5 3 2 $ # ^ ! ^ * # ...etc not enter key or shift or Esc or space ...etc
/* Do stuff */
}
});回答 3
Stack Overflow用户
发布于 2012-09-20 18:50:06
这对我很有帮助：
$("#input").keyup(function(event) {
//use keyup instead keypress because:
//- keypress will not work on backspace and delete
//- keypress is called before the character is added to the textfield (at least in google chrome)
var searchText = $.trim($("#input").val());
var c= String.fromCharCode(event.keyCode);
var isWordCharacter = c.match(/\w/);
var isBackspaceOrDelete = (event.keyCode == 8 || event.keyCode == 46);
// trigger only on word characters, backspace or delete and an entry size of at least 3 characters
if((isWordCharacter || isBackspaceOrDelete) && searchText.length > 2)
{ ...Stack Overflow用户
发布于 2010-10-20 20:31:27
如果您只需要排除enter、escape和spacebar密钥，则可以执行以下操作：
$("#text1").keyup(function(event) {
if (event.keyCode != '13' && event.keyCode != '27' && event.keyCode != '32') {
alert('test');
}
});您可以参考complete list of keycode here进行进一步的修改。
Stack Overflow用户
发布于 2018-10-27 00:15:15
我从来不喜欢关键代码验证。我的方法是查看输入是否包含文本(任何字符)，确认用户输入的是文本而不是其他字符
$('#input').on('keyup', function() {
var words = $(this).val();
// if input is empty, remove the word count data and return
if(!words.length) {
$(this).removeData('wcount');
return true;
}
// if word count data equals the count of the input, return
if(typeof $(this).data('wcount') !== "undefined" && ($(this).data('wcount') == words.length)){
return true;
}
// update or initialize the word count data
$(this).data('wcount', words.length);
console.log('user tiped ' + words);
// do you stuff...
});<html lang="en">
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body>
<input type="text" name="input" id="input">
</body>
</html>
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原文链接：
https://stackoverflow.com/questions/3977642
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