blocks|key|191466|text|这就是你要的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|191467|​|191468|var+yourString+=+"/installers/";
var+result+=+yourString.substring(1,+yourString.length-1);

console.log(result);|code-block|syntax|javascript|191469|191470|或者，您也可以按照Ankit+Gupta的建议使用.slice|offset|length|style|CODE|191471|191472|var+yourString+=+"/installers/services/";

var+result+=+yourString.slice(1,-1);

console.log(result);|191473|191474|slice和substring的文档。|191475|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/25567247/3063532|1|https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/slice?v=control|2|https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/substring^0|0|0|0|0|P|6|9|B|0|0|0|0|0|0|5|1|6|9|2|0^^$0|@$1|2|3|4|5|6|7|17|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|18|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|19|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|1A|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|1B|8|@$L|1C|M|1D|N|O]]|9|@$L|1E|M|1F|1|1G]]|A|$]]|$1|P|3|C|5|6|7|1H|8|@]|9|@]|A|$]]|$1|Q|3|R|5|F|7|1I|8|@]|9|@]|A|$G|H]]|$1|S|3|C|5|6|7|1J|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1K|8|@]|9|@$L|1L|M|1M|1|1N]|$L|1O|M|1P|1|1Q]]|A|$]]|$1|V|3|-4|5|6|7|1R|8|@]|9|@]|A|$]]]|W|$X|$5|Y|Z|10|A|$11|12]]|13|$5|Y|Z|10|A|$11|14]]|15|$5|Y|Z|10|A|$11|16]]]]

Here you go

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var yourString = "/installers/";
var result = yourString.substring(1, yourString.length-1);

console.log(result);</code></pre>
</div>
</div>


Or you can use <code>.slice</code> as suggested by <a href="https://stackoverflow.com/a/25567247/3063532">Ankit Gupta</a>

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var yourString = "/installers/services/";

var result = yourString.slice(1,-1);

console.log(result);</code></pre>
</div>
</div>


Documentation for the <a href="https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/slice?v=control" rel="noreferrer">slice</a> and <a href="https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/substring" rel="noreferrer">substring</a>.

blocks|key|4697386|text|使用slice可能更好，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4697387|string.slice(1,+-1)|code-block|syntax|javascript|4697388|entityMap^0|2|5|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

It may be nicer one to use <code>slice</code> like :
<pre><code>string.slice(1, -1)
</code></pre>

blocks|key|4697323|text|我不认为jQuery和这件事有任何关系。无论如何，尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4697324|url+=+url.replace(/%5E\/%7C\/$/g,+'');|code-block|syntax|javascript|4697325|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I don't think jQuery has anything to do with this. Anyway, try the following :

<pre><code>url = url.replace(/^\/|\/$/g, '');
</code></pre>

blocks|key|191531|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|191532|"/installers/services/".replace(/%5E\/%2B/g,'').replace(/\/%2B$/g,'')|code-block|syntax|javascript|191533|这种正则表达式是一种常见的方法，可以使许多语言中使用的trim函数具有相同的行为。|offset|length|style|CODE|191534|trim函数的一个可能实现是：|191535|function+trim(string,+char){
++++if(!char)+char+=+'+';+//space+by+default
++++char+=+char.replace(/([()[{*%2B.$%5E\\%7C?])/g,+'\\$1');+//escape+char+parameter+if+needed+for+regex+syntax.
++++var+regex_1+=+new+RegExp("%5E"+%2B+char+%2B+"%2B",+"g");
++++var+regex_2+=+new+RegExp(char+%2B+"%2B$",+"g");
++++return+string.replace(regex_1,+'').replace(regex_2,+'');
}|191536|这将删除字符串开头和结尾的所有/。它处理像///installers/services///这样的情况|191537|您还可以简单地执行以下操作：|191538|"/installers/".substring(1,+string.length-1);|191539|entityMap^0|0|0|R|4|0|0|0|F|1|L|P|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|15|8|@$I|16|J|17|K|L]|$I|18|J|19|K|L]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1A|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|W|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|X|$]]

You can do something like that : 

<pre><code>"/installers/services/".replace(/^\/+/g,'').replace(/\/+$/g,'')
</code></pre>

This regex is a common way to have the same behaviour of the <code>trim</code> function used in many languages.

A possible implementation of trim function is : 

<pre><code>function trim(string, char){
 if(!char) char = ' '; //space by default
 char = char.replace(/([()[{*+.$^\\|?])/g, '\\$1'); //escape char parameter if needed for regex syntax.
 var regex_1 = new RegExp("^" + char + "+", "g");
 var regex_2 = new RegExp(char + "+$", "g");
 return string.replace(regex_1, '').replace(regex_2, '');
}
</code></pre>

Which will delete all <code>/</code> at the beginning and the end of the string. It handles cases like <code>///installers/services///</code>

You can also simply do : 

<pre><code>"/installers/".substring(1, string.length-1);
</code></pre>

blocks|key|4697279|text|您可以使用substring方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4697280|s+=+s.substring(0,+s.length+-+1)+//removes+last+character|code-block|syntax|javascript|4697281|另一种替代方法是slice方法|4697282|entityMap^0|5|9|0|0|8|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

You can use <code>substring</code> method

<pre><code>s = s.substring(0, s.length - 1) //removes last character
</code></pre>

another alternative is <code>slice</code> method

blocks|key|4697299|text|使用.replace(/.*\/(\S%2B)\//img,"$1")|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4697300|"/installers/services/".replace(/.*\/(\S%2B)\//img,"$1");+//-->+services

"/services/".replace(/.*\/(\S%2B)\//img,"$1");+//-->+services|code-block|syntax|javascript|4697301|entityMap^0|2|V|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

use <code>.replace(/.*\/(\S+)\//img,"$1")</code>

<pre><code>"/installers/services/".replace(/.*\/(\S+)\//img,"$1"); //--&gt; services

"/services/".replace(/.*\/(\S+)\//img,"$1"); //--&gt; services
</code></pre>

blocks|key|4697254|text|url=url.substring(1,url.Length-1);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4697255|这样，您就可以使用类似于.../...的目录。等。|unstyled|4697256|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>url=url.substring(1,url.Length-1);
</code></pre>

This way you can use the directories if it is like .../.../.../... etc.

I'm wondering how to remove the first and last character of a string in Javascript.

My url is showing <code>/installers/</code> and I just want <code>installers</code>.

Sometimes it will be <code>/installers/services/</code> and I just need <code>installers/services</code>.

So I can't just simply strip the slashes <code>/</code>.

How to remove the first and the last character of a string

jQuery

我想知道如何在Javascript中删除字符串的第一个和最后一个字符。我的url显示的是/installers/，而我只想要installers。有时它会是/installers/services/，而我只需要installers/services。所以我不能简单地去掉斜杠/。

问如何删除字符串的第一个和最后一个字符
EN

回答 7

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问如何删除字符串的第一个和最后一个字符
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