blocks|key|1533176|text|您可以使用strtol|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1533177|char+string[]+=+"1101110100110100100000";
char+*+end;
long+int+value+=+strtol+(string,&end,2);|code-block|syntax|javascript|1533178|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use strtol

<pre><code>char string[] = "1101110100110100100000";
char * end;
long int value = strtol (string,&amp;end,2);
</code></pre>

blocks|key|1748186|text|#include+<stdio.h>
#include+<stdlib.h>

int+main(void)+{
++++char+*+ptr;
++++long+parsed+=+strtol("11110111",+&+ptr,+2);
++++printf("%25lX\n",+parsed);
++++return+EXIT_SUCCESS;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1748187|对于更大的数字，有一个long+long版本，strtoll。|unstyled|offset|length|style|CODE|1748188|entityMap^0|0|B|9|N|7|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>#include &lt;stdio.h&gt;
#include &lt;stdlib.h&gt;

int main(void) {
 char * ptr;
 long parsed = strtol("11110111", &amp; ptr, 2);
 printf("%lX\n", parsed);
 return EXIT_SUCCESS;
}
</code></pre>

For larger numbers, there as a <code>long long</code> version, <code>strtoll</code>.

blocks|key|1748232|text|可以使用std::bitset+(如果在编译时知道位的长度)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1748233|不过，在某些程序中，您可以将其分成块并合并。|1748234|#include+<bitset>
#include+<iostream>

int+main()
{
++++std::bitset<5>++x(std::string("01011"));

++++std::cout+<<+x+<<+":"+<<+x.to_ulong()+<<+std::endl;
}|code-block|syntax|javascript|1748235|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use std::bitset (if then length of your bits is known at compile time) 
Though with some program you could break it up into chunks and combine.

<pre><code>#include &lt;bitset&gt;
#include &lt;iostream&gt;

int main()
{
 std::bitset&lt;5&gt; x(std::string("01011"));

 std::cout &lt;&lt; x &lt;&lt; ":" &lt;&lt; x.to_ulong() &lt;&lt; std::endl;
}
</code></pre>

blocks|key|1533295|text|您可以使用Boost+Dynamic+Bitset：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1533296|boost::dynamic_bitset<>++x(std::string("01011"));
std::cout+<<+x+<<+":"+<<+x.to_ulong()+<<+std::endl;|code-block|syntax|javascript|1533297|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use Boost Dynamic Bitset:

<pre><code>boost::dynamic_bitset&lt;&gt; x(std::string("01011"));
std::cout &lt;&lt; x &lt;&lt; ":" &lt;&lt; x.to_ulong() &lt;&lt; std::endl;
</code></pre>

blocks|key|1748280|text|#include+<iostream>
#include+<stdio.h>
#include+<string>

using+namespace+std;

string+getBinaryString(int+value,+unsigned+int+length,+bool+reverse)+{
++++string+output+=+string(length,+'0');
++++if+(!reverse)+{
++++++++for+(unsigned+int+i+=+0;+i+<+length;+i%2B%2B)+{
++++++++++++if+((value+&+(1+<<+i))+!=+0)+{
++++++++++++++++output[i]+=+'1';
++++++++++++}
++++++++}
++++}
++++else+{
++++++++for+(unsigned+int+i+=+0;+i+<+length;+i%2B%2B)+{
++++++++++++if+((value+&+(1+<<+(length+-+i+-+1)))+!=+0)+{
++++++++++++++++output[i]+=+'1';
++++++++++++}
++++++++}
++++}
++++return+output;
}

unsigned+long+getInteger(const+string&+input,+size_t+lsbindex,+size_t+msbindex)+{
++++unsigned+long+val+=+0;
++++unsigned+int+offset+=+0;
++++if+(lsbindex+>+msbindex)+{
++++++++size_t+length+=+lsbindex+-+msbindex;
++++++++for+(size_t+i+=+msbindex;+i+<=+lsbindex;+i%2B%2B,+offset%2B%2B)+{
++++++++++++if+(input[i]+==+'1')+{
++++++++++++++++val+%7C=+(1+<<+(length+-+offset));
++++++++++++}
++++++++}
++++}
++++else+{+//lsbindex+<+msbindex
++++++++for+(size_t+i+=+lsbindex;+i+<=+msbindex;+i%2B%2B,+offset%2B%2B)+{
++++++++++++if+(input[i]+==+'1')+{
++++++++++++++++val+%7C=+(1+<<+offset);
++++++++++++}
++++++++}
++++}
++++return+val;
}

int+main()+{
++++int+value+=+23;
++++cout+<<+value+<<+":+"+<<+getBinaryString(value,+5,+false)+<<+endl;
++++string+str+=+"01011";
++++cout+<<+str+<<+":+"+<<+getInteger(str,+1,+3)+<<+endl;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1748281|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#include &lt;iostream&gt;
#include &lt;stdio.h&gt;
#include &lt;string&gt;

using namespace std;

string getBinaryString(int value, unsigned int length, bool reverse) {
 string output = string(length, '0');
 if (!reverse) {
 for (unsigned int i = 0; i &lt; length; i++) {
 if ((value &amp; (1 &lt;&lt; i)) != 0) {
 output[i] = '1';
 }
 }
 }
 else {
 for (unsigned int i = 0; i &lt; length; i++) {
 if ((value &amp; (1 &lt;&lt; (length - i - 1))) != 0) {
 output[i] = '1';
 }
 }
 }
 return output;
}

unsigned long getInteger(const string&amp; input, size_t lsbindex, size_t msbindex) {
 unsigned long val = 0;
 unsigned int offset = 0;
 if (lsbindex &gt; msbindex) {
 size_t length = lsbindex - msbindex;
 for (size_t i = msbindex; i &lt;= lsbindex; i++, offset++) {
 if (input[i] == '1') {
 val |= (1 &lt;&lt; (length - offset));
 }
 }
 }
 else { //lsbindex &lt; msbindex
 for (size_t i = lsbindex; i &lt;= msbindex; i++, offset++) {
 if (input[i] == '1') {
 val |= (1 &lt;&lt; offset);
 }
 }
 }
 return val;
}

int main() {
 int value = 23;
 cout &lt;&lt; value &lt;&lt; &quot;: &quot; &lt;&lt; getBinaryString(value, 5, false) &lt;&lt; endl;
 string str = &quot;01011&quot;;
 cout &lt;&lt; str &lt;&lt; &quot;: &quot; &lt;&lt; getInteger(str, 1, 3) &lt;&lt; endl;
}
</code></pre>

I'm trying to convert an incoming sting of 1s and 0s from stdin into their respective binary values (where a string such as "11110111" would be converted to 0xF7). This seems pretty trivial but I don't want to reinvent the wheel so I'm wondering if there's anything in the C/C++ standard libs that can already perform such an operation?

Converting string of 1s and 0s into binary value

我正在尝试将传入的字符串1和0从标准输入转换为它们各自的二进制值(其中"11110111“这样的字符串将被转换为0xF7)。这看起来很微不足道，但我不想重复发明轮子，所以我想知道在C/C++标准库中是否有什么已经可以执行这样的操作？

问将1和0组成的字符串转换为二进制值
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