blocks|key|1364661|text|是。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1364662|"abcdef".ToCharArray();|code-block|syntax|javascript|1364663|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Yes.

<pre><code>"abcdef".ToCharArray();
</code></pre>

blocks|key|1149626|text|所以您需要一个string数组，每个数组有一个char：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1149627|string+s+=+"abcdef";
string[]+a+=+s.Select(c+=>+c.ToString()).ToArray();|code-block|syntax|javascript|1149628|这之所以有效，是因为string实现了IEnumerable<char>。因此，Select(c+=>+c.ToString())将string中的每个char投影到一个表示该char的string，ToArray枚举该投影并将结果转换为一个string数组。|1149629|如果您使用的是旧版本的C#：|1149630|string+s+=+"abcdef";
string[]+a+=+new+string[s.Length];
for(int+i+=+0;+i+<+s.Length;+i%2B%2B)+{
++++a[i]+=+s[i].ToString();
}|1149631|entityMap^0|7|6|N|4|0|0|A|6|J|H|14|P|1U|6|24|4|2G|4|2L|6|2S|7|3D|6|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]|$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1H|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|R|$]]

So you want an array of <code>string</code>, one <code>char</code> each:

<pre><code>string s = "abcdef";
string[] a = s.Select(c =&gt; c.ToString()).ToArray();
</code></pre>

This works because <code>string</code> implements <code>IEnumerable&lt;char&gt;</code>. So <code>Select(c =&gt; c.ToString())</code> projects each <code>char</code> in the <code>string</code> to a <code>string</code> representing that <code>char</code> and <code>ToArray</code> enumerates the projection and converts the result to an array of <code>string</code>.

If you're using an older version of C#:

<pre><code>string s = "abcdef";
string[] a = new string[s.Length];
for(int i = 0; i &lt; s.Length; i++) {
 a[i] = s[i].ToString();
}
</code></pre>

blocks|key|1364747|text|您可以使用linq并执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1364748|string+value+=+"abcdef";
string[]+letters+=+value.Select(c+=>+c.ToString()).ToArray();|code-block|syntax|javascript|1364749|这将得到一个字符串数组，而不是一个字符数组。|1364750|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could use linq and do:

<pre><code>string value = "abcdef";
string[] letters = value.Select(c =&gt; c.ToString()).ToArray();
</code></pre>

This would get you an array of strings instead of an array of chars.

blocks|key|1149705|text|比上面的大一点，但我没有看到任何简单的一个这样的线条。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1149706|List<string>+results+=+new+List<string>;+

foreach(Char+c+in+"abcdef".ToCharArray())
{
+++results.add(c.ToString());
}


results.ToArray();++<--+done|code-block|syntax|javascript|1149707|String.split怎么了？|1149708|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Bit more bulk than those above but i don't see any simple one liner for this.

<pre><code>List&lt;string&gt; results = new List&lt;string&gt;; 

foreach(Char c in "abcdef".ToCharArray())
{
 results.add(c.ToString());
}


results.ToArray(); &lt;-- done
</code></pre>

What's wrong with string.split???

blocks|key|1149757|text|你为什么不干脆|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1149758|string+value="abcd";

value.ToCharArray();

textbox1.Text=Convert.toString(value[0]);|code-block|syntax|javascript|1149759|来显示字符串的第一个字母；在本例中是'a‘。|1149760|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Why don't you just 

<pre><code>string value="abcd";

value.ToCharArray();

textbox1.Text=Convert.toString(value[0]);
</code></pre>

to show the first letter of the string; that would be 'a' in this case.

Is there any way to convert a string (<code>"abcdef"</code>) to an array of string containing its character (<code>["a","b","c","d","e","f"]</code>) without using the <code>String.Split</code> function?

Convert string to array in without using Split function

有没有办法在不使用String.Split函数的情况下将字符串("abcdef")转换为包含其字符(["a","b","c","d","e","f"])的字符串数组？

问在不使用拆分函数的情况下将字符串转换为数组
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