blocks|key|975683|text|"cat".toCharArray()|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|975684|但是如果你需要字符串|unstyled|975685|"cat".split("")|975686|Edit:这将返回一个空的第一个值。|975687|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>"cat".toCharArray()
</code></pre>

But if you need strings

<pre><code>"cat".split("")
</code></pre>

Edit: which will return an empty first value.

blocks|key|975628|text|String+str+=+"cat";
char[]+cArray+=+str.toCharArray();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|975629|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String str = "cat";
char[] cArray = str.toCharArray();
</code></pre>

blocks|key|975762|text|如果输入中需要Basic+Multilingual+Plane以外的字符(一些CJK字符、新表情符号...)，则不能使用诸如"ab".split("(?!%5E)")之类的方法，因为它们会将这些字符(结果转换为array+["a",+"?",+"?",+"b"])断开，并且必须使用更安全的方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|975763|"ab".codePoints()
++++.mapToObj(cp+->+new+String(Character.toChars(cp)))
++++.toArray(size+->+new+String[size]);|code-block|syntax|javascript|975764|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/Plane_(Unicode)^0|1Q|J|2V|Q|7|O|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

If characters beyond <a href="https://en.wikipedia.org/wiki/Plane_(Unicode)" rel="noreferrer">Basic Multilingual Plane</a> are expected on input (some CJK characters, new emoji...), approaches such as <code>"ab".split("(?!^)")</code> cannot be used, because they break such characters (results into <code>array ["a", "?", "?", "b"]</code>) and something safer has to be used:

<pre><code>"ab".codePoints()
 .mapToObj(cp -&gt; new String(Character.toChars(cp)))
 .toArray(size -&gt; new String[size]);
</code></pre>

blocks|key|975895|text|如果字符串包含代理项对，则split("(?!%5E)")无法正常工作。您应该使用split("(?<=.)")。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|975896|String[]+splitted+=+"花ab".split("(?<=.)");
System.out.println(Arrays.toString(splitted));|code-block|syntax|javascript|975897|输出：|975898|[花,+a,+b,+,+,+]|975899|entityMap^0|D|E|13|F|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

<code>split(&quot;(?!^)&quot;)</code> does not work correctly if the string contains surrogate pairs. You should use <code>split(&quot;(?&lt;=.)&quot;)</code>.
<pre><code>String[] splitted = &quot;花ab&quot;.split(&quot;(?&lt;=.)&quot;);
System.out.println(Arrays.toString(splitted));
</code></pre>
output:
<pre><code>[花, a, b, , , ]
</code></pre>

blocks|key|975815|text|总结一下其他的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|975816|这适用于所有Java版本：|975817|"cat".split("(?!%5E)")|code-block|syntax|javascript|975818|这只适用于Java+8及更高版本：|975819|"cat".split("")|975820|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

To sum up the other answers...

This works on all Java versions:

<pre><code>"cat".split("(?!^)")
</code></pre>

This only works on Java 8 and up:

<pre><code>"cat".split("")
</code></pre>

blocks|key|975689|text|for(int+i=0;i<str.length();i%2B%2B)
{
System.out.println(str.charAt(i));
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|975690|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for(int i=0;i&lt;str.length();i++)
{
System.out.println(str.charAt(i));
}
</code></pre>

blocks|key|760037|text|也许您可以使用一个for循环来遍历字符串内容，并使用charAt方法逐个提取字符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|760038|例如，与ArrayList<String>相结合，您可以获得单个字符的数组。|760039|entityMap^0|Q|6|0|4|H|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

Maybe you can use a for loop that goes through the String content and extract characters by characters using the <code>charAt</code> method.

Combined with an <code>ArrayList&lt;String&gt;</code> for example you can get your array of individual characters.

blocks|key|975865|text|如果原始字符串包含supplementary+Unicode+characters，则split()将不起作用，因为它将这些字符拆分成代理项对。要正确处理这些特殊字符，可以使用下面这样的代码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|975866|String[]+chars+=+new+String[stringToSplit.codePointCount(0,+stringToSplit.length())];
for+(int+i+=+0,+j+=+0;+i+<+stringToSplit.length();+j%2B%2B)+{
++++int+cp+=+stringToSplit.codePointAt(i);
++++char+c[]+=+Character.toChars(cp);
++++chars[j]+=+new+String(c);
++++i+%2B=+Character.charCount(cp);
}|code-block|syntax|javascript|975867|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/tutorial/i18n/text/supplementaryChars.html^0|17|7|9|W|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

If the original string contains <a href="https://docs.oracle.com/javase/tutorial/i18n/text/supplementaryChars.html" rel="nofollow noreferrer">supplementary Unicode characters</a>, then <code>split()</code> would not work, as it splits these characters into surrogate pairs. To correctly handle these special characters, a code like this works:

<pre><code>String[] chars = new String[stringToSplit.codePointCount(0, stringToSplit.length())];
for (int i = 0, j = 0; i &lt; stringToSplit.length(); j++) {
 int cp = stringToSplit.codePointAt(i);
 char c[] = Character.toChars(cp);
 chars[j] = new String(c);
 i += Character.charCount(cp);
}
</code></pre>

I need to split a String into an array of single character Strings.

Eg, splitting "cat" would give the array "c", "a", "t"

Split string into array of character strings

Java

我需要将一个字符串拆分成一个单字符字符串数组。例如，拆分"cat“将得到数组"c"，"a"，"t”

问将字符串拆分为字符串数组
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回答 8

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