blocks|key|1249561|text|您还可以替换所有出现的空格，从而避免foreach循环：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1249562|string+email+=+"a@a.com,+b@b.com,+c@c.com";++++
string[]+emails+=+email.Replace("+",+"").Split(',');|code-block|syntax|javascript|1249563|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could also replace all occurrences of spaces, and so avoid the foreach loop:

<pre><code>string email = "a@a.com, b@b.com, c@c.com"; 
string[] emails = email.Replace(" ", "").Split(',');
</code></pre>

blocks|key|1249805|text|emails.Split(',').Select(email+=>+email.Trim()).ToArray()|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1249806|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>emails.Split(',').Select(email =&gt; email.Trim()).ToArray()
</code></pre>

blocks|key|1464614|text|以下任何一种方法都可以工作。我推荐使用第一种方法，因为它更准确地表达了连接字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1464615|string[]+emails+=+email.Split(new+string[]+{+",+"+},+StringSplitOptions.None);
string[]+emails+=+email.Split(new+char[]+{+'+',+','+},+StringSplitOptions.RemoveEmptyEntries);|code-block|syntax|javascript|1464616|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Either one of the following would work. I'd recommend the first since it more accurately expresses the joining string.

<pre><code>string[] emails = email.Split(new string[] { ", " }, StringSplitOptions.None);
string[] emails = email.Split(new char[] { ' ', ',' }, StringSplitOptions.RemoveEmptyEntries);
</code></pre>

blocks|key|1249383|text|您可以使用Trim()：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1249384|string+email+=+"a@a.com,+b@b.com,+c@c.com";
string[]+emails+=+email.Split(',');
emails+=+(from+e+in+emails
++++++++++select+e.Trim()).ToArray();|code-block|syntax|javascript|1249385|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use Trim():

<pre><code>string email = "a@a.com, b@b.com, c@c.com";
string[] emails = email.Split(',');
emails = (from e in emails
 select e.Trim()).ToArray();
</code></pre>

blocks|key|1464419|text|使用Regex.Split避免修剪|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1464420|var+emails+=+Regex.Split(email,+@",\s*");|code-block|syntax|javascript|1464421|entityMap^0|2|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use <code>Regex.Split</code> to avoid trimming

<pre><code>var emails = Regex.Split(email, @",\s*");
</code></pre>

blocks|key|1249848|text|您可以使用这样的单行解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1249849|string[]+emails+=+text.Split(',',+StringSplitOptions.RemoveEmptyEntries);
Array.ForEach<string>(emails,+x+=>+emails[Array.IndexOf<string>(emails,+x)]+=+x.Trim());|code-block|syntax|javascript|1249850|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use a one line solution like this:

<pre><code>string[] emails = text.Split(',', StringSplitOptions.RemoveEmptyEntries);
Array.ForEach&lt;string&gt;(emails, x =&gt; emails[Array.IndexOf&lt;string&gt;(emails, x)] = x.Trim());
</code></pre>

blocks|key|1249990|text|如果您只需要操作条目，而不返回数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1249991|string[]+emails+=+text.Split(',');
Array.ForEach(emails,+e+=>+e.Trim());|code-block|syntax|javascript|1249992|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you just need to manipulate the entries, without returning the array: 

<pre><code>string[] emails = text.Split(',');
Array.ForEach(emails, e =&gt; e.Trim());
</code></pre>

blocks|key|1464331|text|或者，也可以使用以下形式的正则表达式进行拆分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1464332|\s*,\s*|code-block|syntax|javascript|1464333|即|1464334|string[]+emails+=+Regex.Split(email,+@"\s*,\s*");|1464335|它会直接消耗周围的空间。|1464336|正则表达式通常会影响性能，但是您给出的示例表明，对于短数组，这是您计划在代码中执行一次的操作。|1464337|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Alternatively, you can split using a regular expression of the form:

<pre><code>\s*,\s*
</code></pre>

i.e.

<pre><code>string[] emails = Regex.Split(email, @"\s*,\s*");
</code></pre>

It will consume the surrounding spaces directly.

Regular expressions are usually a performance hit, but the example you gave indicates that this is something you plan to do once in your code for a short array.

blocks|key|1250039|text|.NET+5已经问世，随之而来的是对这个问题的现代解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1250040|string[]+emails+=+email.Split(',',+StringSplitOptions.TrimEntries);|code-block|syntax|javascript|1250041|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

.NET 5 has arrived and with it, a modern solution to this problem:
<pre><code>string[] emails = email.Split(',', StringSplitOptions.TrimEntries);
</code></pre>

blocks|key|1464760|text|布莱恩·瓦茨的回答是优雅而简单的。他隐式地引用了Split()创建的字符串数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1464761|如果您正在读取文件，并且希望在构建数组时处理数据，请注意它的可扩展性。|1464762|string+sFileA+=+@"C:\Documents+and+Settings\FileA.txt";
string+sFileB+=+@"C:\Documents+and+Settings\FileB.txt";

//+Trim+extraneous+spaces+from+the+first+file's+data
string[]+fileAData+=+(from+line+in+File.ReadAllLines(+sFileA+)
++++++++++++++++++++++select+line.Trim()).ToArray();

//+Strip+a+second+unneeded+column+from+the+second+file's+data
string[]+fileBData+=+(from+line+in+File.ReadAllLines(+sFileB+)
++++++++++++++++++++++select+line.Substring(+0,+21+).Trim()).ToArray();|code-block|syntax|javascript|1464763|当然，如果愿意，也可以使用Linq+=>表示法。|1464764|string[]+fileBData+=+File.ReadAllLines(+sFileB+).Select(+line+=>
+++++++++++++++++++++++++++++line.Substring(+0,+21+).Trim()).ToArray();|1464765|虽然我的答案应该是以评论的形式发布的，但我还没有足够的名誉点来评论。但我发现这个讨论在弄清楚如何在使用ReadAllLines()的同时处理数据方面非常有价值。|1464766|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The answer from Bryan Watts is elegant and simple. He implicitly refers to the array of strings created by the Split().

Also note its extensibility if you are reading a file, and want to massage the data while building an array.

<pre><code>string sFileA = @"C:\Documents and Settings\FileA.txt";
string sFileB = @"C:\Documents and Settings\FileB.txt";

// Trim extraneous spaces from the first file's data
string[] fileAData = (from line in File.ReadAllLines( sFileA )
 select line.Trim()).ToArray();

// Strip a second unneeded column from the second file's data
string[] fileBData = (from line in File.ReadAllLines( sFileB )
 select line.Substring( 0, 21 ).Trim()).ToArray();
</code></pre>

Of course, you can use the Linq => notation if you prefer.

<pre><code>string[] fileBData = File.ReadAllLines( sFileB ).Select( line =&gt;
 line.Substring( 0, 21 ).Trim()).ToArray();
</code></pre>

Although my answer should have been posted as a comment, I don't have enough reputation points to comment yet. But I found this discussion invaluable in figuring out how to massage data while using ReadAllLines().

blocks|key|1249441|text|在foreach循环中使用String.Trim，或者在使用.NET+3.5%2B时使用LINQ语句。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1249442|entityMap^0|1|7|D|B|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

Use <code>String.Trim</code> in a <code>foreach</code> loop, or if you are using .NET 3.5+ a LINQ statement.

I have a string that comes in like:

<pre><code>string email = "a@a.com, b@b.com, c@c.com";
</code></pre>

I want to split it into an array of strings

If I do this:

<pre><code>string[] emails = email.Split(',');
</code></pre>

I get spaces in front of each email address (after the first one):

<pre><code>emails[0] = "a@a.com"
emails[1] = " b@b.com"
emails[2] = " c@c.com"
</code></pre>

What is the best way to get this (either a better way to parse or a way to trim all strings in an array)?

<pre><code>emails[0] = "a@a.com"
emails[1] = "b@b.com"
emails[2] = "c@c.com"
</code></pre>

trim all strings in an array

我有一个字符串，如下所示：string email = "a@a.com, b@b.com, c@c.com";我想把它分成一个字符串数组如果我这样做：string[] emails = email.Split(',');我在每个电子邮件地址前面都有空格(在第一个地址之后)：emails[0] = "a@a.com"emails[1] = " b@b.com"emails[2] = " c@c.c

问修剪数组中的所有字符串
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