blocks|key|1524790|text|有72+points+per+inch；如果假设每英寸96像素就足够了，那么公式就相当简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1524791|点数=像素*+72+/+96|1524792|有一种方法可以使用GetDeviceCaps获取视窗中每英寸显示器的配置像素。微软有一个名为"Developing+DPI-Aware+Applications"的指南，查找“创建支持DPI的字体”一节。|style|CODE|1524793|W3C已经将像素测量px定义为精确的1/96th+of+1in，而不考虑显示器的实际分辨率，因此上面的公式应该适用于所有web工作。|1524794|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Point_%2528typography%2529|1|https://msdn.microsoft.com/en-us/library/dd144877(v=vs.85).aspx)|2|http://msdn.microsoft.com/en-us/library/ms838191.aspx|3|https://www.w3.org/TR/css3-values/#absolute-lengths^0|1|I|0|0|0|9|D|9|D|1|1A|Z|2|0|A|2|I|D|3|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|6|7|13|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|14|8|@$A|15|B|16|H|I]]|9|@$A|17|B|18|1|19]|$A|1A|B|1B|1|1C]]|C|$]]|$1|J|3|K|5|6|7|1D|8|@$A|1E|B|1F|H|I]]|9|@$A|1G|B|1H|1|1I]]|C|$]]|$1|L|3|-4|5|6|7|1J|8|@]|9|@]|C|$]]]|M|$N|$5|O|P|Q|C|$R|S]]|T|$5|O|P|Q|C|$R|U]]|V|$5|O|P|Q|C|$R|W]]|X|$5|O|P|Q|C|$R|Y]]]]

There are <a href="http://en.wikipedia.org/wiki/Point_%28typography%29" rel="noreferrer">72 points per inch</a>; if it is sufficient to assume 96 pixels per inch, the formula is rather simple:

points = pixels * 72 / 96

There is a way to get the configured pixels per inch of your display in Windows using <a href="https://msdn.microsoft.com/en-us/library/dd144877(v=vs.85).aspx" rel="noreferrer"><code>GetDeviceCaps</code></a>. Microsoft has a guide called <a href="http://msdn.microsoft.com/en-us/library/ms838191.aspx" rel="noreferrer">"Developing DPI-Aware Applications"</a>, look for the section "Creating DPI-Aware Fonts".

The W3C has defined the pixel measurement <code>px</code> as exactly <a href="https://www.w3.org/TR/css3-values/#absolute-lengths" rel="noreferrer">1/96th of 1in</a> regardless of the actual resolution of your display, so the above formula should be good for all web work.

blocks|key|1524883|text|如果您的代码位于表单中，请尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1524884|Graphics+g+=+this.CreateGraphics();
points+=+pixels+*+72+/+g.DpiX;
g.Dispose();|code-block|syntax|javascript|1524885|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this if your code lies in a form:

<pre><code>Graphics g = this.CreateGraphics();
points = pixels * 72 / g.DpiX;
g.Dispose();
</code></pre>

blocks|key|1525023|text|WPF使用System.Windows.FontSizeConverter将点转换为像素。FontSizeConverter使用System.Windows.LengthConverter。LengthConverter使用系数1.333333333333333333将点(p)转换为像素(x)：x=p*+1.3333333333333333|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1525024|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

WPF converts points to pixels with the System.Windows.FontSizeConverter. The FontSizeConverter uses the System.Windows.LengthConverter. The LengthConverter uses the factor 1.333333333333333333 to convert from points (p) to pixels (x): x = p * 1.3333333333333333

blocks|key|1739884|text|System.Drawing.Graphics具有DpiX和DpiY属性。DpiX是水平方向上每英寸的像素。DpiY表示垂直方向上的像素/英寸。使用它们将点(每英寸72点)转换为像素。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1739885|示例:+14个水平点=+(14+*+DpiX)+/+72像素|1739886|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

System.Drawing.Graphics has DpiX and DpiY properties. DpiX is pixels per inch horizontally. DpiY is pixels per inch vertically. Use those to convert from points (72 points per inch) to pixels.

Ex: 14 horizontal points = (14 * DpiX) / 72 pixels

blocks|key|1524740|text|当然，整个问题应该是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1524741|“如何获得显示器的水平和垂直PPI+(每英寸像素)？”|1524742|一英寸有72个点(根据定义，一个“点”被定义为1/72英寸，同样，"pica“被定义为1/72英尺)。有了这两点信息，你就可以很容易地在px和pt之间来回转换。|1524743|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

Surely this whole question should be:

"How do I obtain the horizontal and vertical PPI (Pixels Per Inch) of the monitor?"

There are 72 points in an inch (by definition, a "point" is defined as 1/72nd of an inch, likewise a "pica" is defined as 1/72nd of a foot). With these two bits of information you can convert from px to pt and back very easily.

blocks|key|1524899|text|实际上它一定是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1524900|points+=+pixels+*+96+/+72|code-block|syntax|javascript|1524901|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Actually it must be

<pre><code>points = pixels * 96 / 72
</code></pre>

blocks|key|1740136|text|在标准XP/Vista/7计算机上，点数=(像素/+96)+*+72+(出厂默认值)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1740137|在运行OSX的标准Mac上，积分=(像素/+72)+*+72+(出厂默认设置)|1740138|Windows默认以96dpi+(显示器)运行Mac默认以72dpi(显示器)运行|1740139|72个POSTSCRIPT点=1英寸12个POSTSCRIPT点=1个POSTSCRIPT+Pica+6个POSTSCRIPT+Picas+=+72个点=1英寸|1740140|1点=+1⁄72英寸=+25.4⁄72+mm+=+0.3527+mm|1740141|DPI+=每英寸点数PPI+=每英寸像素LPI+=每英寸线数|1740142|更多信息，请使用em进行测量|1740143|16px+=+1em+(普通文本的默认值)+8em+=+16px+*8像素/16=+em|1740144|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|U|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|W|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|X|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|Y|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|Q|$]]

points = (pixels / 96) * 72 on a standard XP/Vista/7 machine (factory defaults)

points = (pixels / 72) * 72 on a standard Mac running OSX (Factory defaults)

Windows runs as default at 96dpi (display)
Macs run as default at 72 dpi (display)

72 POSTSCRIPT Points = 1 inch
12 POSTSCRIPT Points = 1 POSTSCRIPT Pica
6 POSTSCRIPT Picas = 72 Points = 1 inch

1 point = 1⁄72 inches = 25.4⁄72 mm = 0.3527 mm

DPI = Dots Per Inch
PPI = Pixels Per Inch
LPI = Lines per inch

More info if using em as measuring

16px = 1em (default for normal text)
8em = 16px * 8
Pixels/16 = em

blocks|key|1740153|text|这是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1740154|int+pixels+=+(int)((dp)+*+Resources.System.DisplayMetrics.Density+%2B+0.5f);|code-block|syntax|javascript|1740155|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works:

<pre><code>int pixels = (int)((dp) * Resources.System.DisplayMetrics.Density + 0.5f);
</code></pre>

blocks|key|1525161|text|在Mac上使用wxPython获取正确的DPI，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1525162|++++from+wx+import+ScreenDC
++++from+wx+import+Size

++++size:+Size+=+ScreenDC().GetPPI()
++++print(f'x-DPI:+{size.GetWidth()}+y-DPI:+{size.GetHeight()}')|code-block|syntax|javascript|1525163|这会产生以下结果：|1525164|x-DPI:+72+y-DPI:+72|1525165|因此，公式为：|1525166|点数:+int+=+(pixelNumber+*+72)+//+72|1525167|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Using wxPython on Mac to get the correct DPI as follows:
<pre><code> from wx import ScreenDC
 from wx import Size

 size: Size = ScreenDC().GetPPI()
 print(f'x-DPI: {size.GetWidth()} y-DPI: {size.GetHeight()}')
</code></pre>
This yields:
x-DPI: 72 y-DPI: 72
Thus, the formula is:
points: int = (pixelNumber * 72) // 72

blocks|key|1524967|text|高度线转换为点和像素(我自己的公式)。下面是一个在Row+Height字段中手动输入213.67磅的示例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1524968|213.67++Manual+Entry++++
++0.45++Add+0.45++++
214.12++Subtotal++++
213.75++Round+to+a+multiple+of+0.75+
213.00++Subtract+0.75+provides+manual+entry+converted+by+Excel++
284.00++Divide+by+0.75+gives+the+number+of+pixels+of+height|code-block|syntax|javascript|1524969|在这里，手动输入213.67个点会得到284个像素。|1524970|在这里，手动输入213.68个点会得到285个像素。|1524971|(为什么是0.45？我不知道，但它是有效的。)|1524972|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Height lines converted into points and pixel (my own formula).
Here is an example with a manual entry of 213.67 points in the Row Height field:

<pre class="lang-none prettyprint-override"><code>213.67 Manual Entry 
 0.45 Add 0.45 
214.12 Subtotal 
213.75 Round to a multiple of 0.75 
213.00 Subtract 0.75 provides manual entry converted by Excel 
284.00 Divide by 0.75 gives the number of pixels of height
</code></pre>

Here the manual entry of 213.67 points gives 284 pixels. 
Here the manual entry of 213.68 points gives 285 pixels.

(Why 0.45? I do not know but it works.)

I have a need to convert Pixels to Points in C#. I've seen some complicated explanations about the topic, but can't seem to locate a simple formula. Let's assume a standard 96dpi, how do I calulate this conversion?

Convert Pixels to Points

Windows

我需要在C#中将像素转换为点。我看过一些关于这个主题的复杂解释，但似乎找不到一个简单的公式。让我们假设一个标准的96dpi，我如何计算这个转换？

问将像素转换为点
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