blocks|key|547304|text|试试pyplot.setp。我认为你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|547305|x+=+range(len(time))
plt.xticks(x,++time)
locs,+labels+=+plt.xticks()
plt.setp(labels,+rotation=90)
plt.plot(x,+delay)|code-block|syntax|javascript|547306|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try pyplot.setp. I think you could do something like this:

<pre><code>x = range(len(time))
plt.xticks(x, time)
locs, labels = plt.xticks()
plt.setp(labels, rotation=90)
plt.plot(x, delay)
</code></pre>

blocks|key|330539|text|我想出了一个类似的例子。同样，rotation关键字是..这是关键。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|330540|from+pylab+import+*
fig+=+figure()
ax+=+fig.add_subplot(111)
ax.bar(+[0,1,2],+[1,3,5]+)
ax.set_xticks(+[+0.5,+1.5,+2.5+]+)
ax.set_xticklabels(+['tom','dick','harry'],+rotation=45+)+;|code-block|syntax|javascript|330541|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I came up with a similar example. Again, the rotation keyword is.. well, it's key.

<pre><code>from pylab import *
fig = figure()
ax = fig.add_subplot(111)
ax.bar( [0,1,2], [1,3,5] )
ax.set_xticks( [ 0.5, 1.5, 2.5 ] )
ax.set_xticklabels( ['tom','dick','harry'], rotation=45 ) ;
</code></pre>

blocks|key|330573|text|我的回答灵感来自cjohnson318的回答，但我不想提供硬编码的标签列表；我想轮换现有的标签：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|330574|for+tick+in+ax.get_xticklabels():
++++tick.set_rotation(45)|code-block|syntax|javascript|330575|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My answer is inspired by cjohnson318's answer, but I didn't want to supply a hardcoded list of labels; I wanted to rotate the existing labels:

<pre><code>for tick in ax.get_xticklabels():
 tick.set_rotation(45)
</code></pre>

blocks|key|547402|text|这对我来说很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|547403|plt.xticks(rotation=90)|code-block|syntax|javascript|547404|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works for me:

<pre><code>plt.xticks(rotation=90)
</code></pre>

blocks|key|547409|text|import+pylab+as+pl
pl.xticks(rotation+=+90)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|547410|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import pylab as pl
pl.xticks(rotation = 90)
</code></pre>

blocks|key|547445|text|与…分离|type|unstyled|depth|inlineStyleRanges|entityRanges|data|547446|plt.xticks(rotation=90)|code-block|syntax|javascript|547447|这也是可能的：|547448|plt.xticks(rotation='vertical')|547449|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Appart from 

<pre><code>plt.xticks(rotation=90)
</code></pre>

this is also possible:

<pre><code>plt.xticks(rotation='vertical')
</code></pre>

blocks|key|330676|text|如果使用plt|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|330677|plt.xticks(rotation=90)|code-block|syntax|javascript|330678|在使用pandas或seaborn进行绘图的情况下，假设ax作为绘图的轴：|330679|ax.set_xticklabels(ax.get_xticklabels(),+rotation=90)|330680|执行上述操作的另一种方式：|330681|for+tick+in+ax.get_xticklabels():
++++tick.set_rotation(45)|330682|entityMap^0|4|3|0|0|S|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

If using <code>plt</code>:

<pre><code>plt.xticks(rotation=90)
</code></pre>

In case of using pandas or seaborn to plot, assuming <code>ax</code> as axes for the plot:

<pre><code>ax.set_xticklabels(ax.get_xticklabels(), rotation=90)
</code></pre>

Another way of doing the above:

<pre><code>for tick in ax.get_xticklabels():
 tick.set_rotation(45)
</code></pre>

blocks|key|547556|text|这将取决于您正在绘制的内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|547557|import+matplotlib.pyplot+as+plt

+x=['long_text_for_a_label_a',
++++'long_text_for_a_label_b',
++++'long_text_for_a_label_c']
y=[1,2,3]
myplot+=+plt.plot(x,y)
for+item+in+myplot.axes.get_xticklabels():
++++item.set_rotation(90)|code-block|syntax|javascript|547558|对于为您提供Axes对象的pandas和seaborn：|547559|df+=+pd.DataFrame(x,y)
#pandas
myplot+=+df.plot.bar()
#seaborn+
myplotsns+=sns.barplot(y='0',++x=df.index,+data=df)
#+you+can+get+xticklabels+without+.axes+cause+the+object+are+already+a+
#+isntance+of+it
for+item+in+myplot.get_xticklabels():
++++item.set_rotation(90)|547560|如果您需要旋转标签，您可能还需要更改字体大小，您可以使用font_scale=1.0来实现。|offset|length|style|CODE|547561|entityMap^0|0|0|0|0|S|E|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

It will depend on what are you plotting.

<pre><code>import matplotlib.pyplot as plt

 x=['long_text_for_a_label_a',
 'long_text_for_a_label_b',
 'long_text_for_a_label_c']
y=[1,2,3]
myplot = plt.plot(x,y)
for item in myplot.axes.get_xticklabels():
 item.set_rotation(90)
</code></pre>

For pandas and seaborn that give you an Axes object:

<pre><code>df = pd.DataFrame(x,y)
#pandas
myplot = df.plot.bar()
#seaborn 
myplotsns =sns.barplot(y='0', x=df.index, data=df)
# you can get xticklabels without .axes cause the object are already a 
# isntance of it
for item in myplot.get_xticklabels():
 item.set_rotation(90)
</code></pre>

If you need to rotate labels you may need change the font size too, you can use <code>font_scale=1.0</code> to do that.

blocks|key|547620|text|如果要在轴对象上应用旋转，最简单的方法是使用tick_params。例如。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|547621|ax.tick_params(axis='x',+labelrotation=90)|code-block|syntax|javascript|547622|Matplotlib文档参考here。|547623|当您有一个由plt.subplots返回的轴数组时，这很有用，而且它比使用set_xticks更方便，因为在这种情况下，您还需要设置刻度标签，而且比那些遍历刻度的标签更方便(原因很明显)|547624|entityMap|0|LINK|mutability|MUTABLE|url|https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.tick_params.html^0|M|B|0|0|E|4|0|0|6|C|11|A|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@$9|11|A|12|1|13]]|E|$]]|$1|M|3|N|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

If you want to apply rotation on the axes object, the easiest way is using <code>tick_params</code>. For example.

<pre><code>ax.tick_params(axis='x', labelrotation=90)
</code></pre>

Matplotlib documentation reference <a href="https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.tick_params.html" rel="noreferrer">here</a>.

This is useful when you have an array of axes as returned by <code>plt.subplots</code>, and it is more convenient than using <code>set_xticks</code> because in that case you need to also set the tick labels, and also more convenient that those that iterate over the ticks (for obvious reasons)

blocks|key|330849|text|将x轴标签旋转90度的步骤|type|unstyled|depth|inlineStyleRanges|entityRanges|data|330850|for+tick+in+ax.get_xticklabels():
++++tick.set_rotation(45)|code-block|syntax|javascript|330851|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To rotate the x-axis label to 90 degrees 

<pre class="lang-py prettyprint-override"><code>for tick in ax.get_xticklabels():
 tick.set_rotation(45)
</code></pre>

blocks|key|547671|text|最简单的解决方案是使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|547672|plt.xticks(rotation=XX)|code-block|syntax|javascript|547673|但同时也|547674|#+Tweak+spacing+to+prevent+clipping+of+tick-labels
plt.subplots_adjust(bottom=X.XX)|547675|例如，对于日期，我使用了rotation=45和bottom=0.20，但您可以对您的数据进行一些测试|547676|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The simplest solution is to use:

<pre><code>plt.xticks(rotation=XX)
</code></pre>

but also 

<pre><code># Tweak spacing to prevent clipping of tick-labels
plt.subplots_adjust(bottom=X.XX)
</code></pre>

e.g for dates I used rotation=45 and bottom=0.20 but you can do some test for your data

I can't figure out how to rotate the text on the X Axis. Its a time stamp, so as the number of samples increase, they get closer and closer until they overlap. I'd like to rotate the text 90 degrees so as the samples get closer together, they aren't overlapping.

Below is what I have, it works fine with the exception that I can't figure out how to rotate the X axis text.

<pre><code>import sys

import matplotlib
matplotlib.use('Agg')
import matplotlib.pyplot as plt
import datetime

font = {'family' : 'normal',
 'weight' : 'bold',
 'size' : 8}

matplotlib.rc('font', **font)

values = open('stats.csv', 'r').readlines()

time = [datetime.datetime.fromtimestamp(float(i.split(',')[0].strip())) for i in values[1:]]
delay = [float(i.split(',')[1].strip()) for i in values[1:]]

plt.plot(time, delay)
plt.grid(b='on')

plt.savefig('test.png')
</code></pre>

Rotate axis text in python matplotlib

我想不出如何在X轴上旋转文本。这是一个时间戳，所以随着样本数量的增加，它们会越来越近，直到它们重叠。我想将文本旋转90度，这样当样本越来越近时，它们就不会重叠。下面是我所拥有的，它工作得很好，除了我不知道如何旋转X轴文本。import sysimport matplotlibmatplotlib.use('Agg')i...

问在python matplotlib中旋转轴文本
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