如何在JavaScript中从日期中减去分钟？
如何在JavaScript中从日期中减去分钟？
提问于 2009-03-23 18:47:28
我如何将这段伪代码转换成JS不用担心结束日期来自哪里，除非它是一个有效的JavaScript日期。
var myEndDateTime = somedate; //somedate is a valid JS date
var durationInMinutes = 100; //this can be any number of minutes from 1-7200 (5 days)
//this is the calculation I don't know how to do
var myStartDate = somedate - durationInMinutes;
alert("The event will start on " + myStartDate.toDateString() + " at " + myStartDate.toTimeString());回答 7
Stack Overflow用户
发布于 2009-03-23 19:20:22
您也可以使用get和set分钟来实现它：
var endDate = somedate;
var startdate = new Date(endDate);
var durationInMinutes = 20;
startdate.setMinutes(endDate.getMinutes() - durationInMinutes);Stack Overflow用户
发布于 2017-01-22 23:14:36
moment.js有一些非常方便的方法来操作date对象
.subtract方法允许您通过提供数量和时间单位字符串，从日期中减去一定数量的时间单位。
var now = new Date();
// Sun Jan 22 2017 17:12:18 GMT+0200 ...
var olderDate = moment(now).subtract(3, 'minutes').toDate();
// Sun Jan 22 2017 17:09:18 GMT+0200 ...Luxon也有一个API来manipulate它自己的DateTime对象。
var dt = DateTime.now();
// "1982-05-25T00:00:00.000Z"
dt.minus({ minutes: 3 });
dt.toISO();
// "1982-05-24T23:57:00.000Z"Stack Overflow用户
发布于 2016-05-27 21:45:32
这是我发现的：
//First, start with a particular time
var date = new Date();
//Add two hours
var dd = date.setHours(date.getHours() + 2);
//Go back 3 days
var dd = date.setDate(date.getDate() - 3);
//One minute ago...
var dd = date.setMinutes(date.getMinutes() - 1);
//Display the date:
var monthNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var date = new Date(dd);
var day = date.getDate();
var monthIndex = date.getMonth();
var year = date.getFullYear();
var displayDate = monthNames[monthIndex] + ' ' + day + ', ' + year;
alert('Date is now: ' + displayDate);资料来源：
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原文链接：
https://stackoverflow.com/questions/674721
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