如何使用JavaScript或jQuery滚动选择列表？
如何使用JavaScript或jQuery滚动选择列表？
提问于 2011-08-26 21:52:48
我有一个select标签：
<select size="3">
<option value="1">value 1</option>
<option value="2">value 2</option>
<option value="3">value 3</option>
<option value="4">value 4</option>
<option value="5">value 5</option>
<option value="6">value 6</option>
<select> 现在它显示了前3个选项，如何使用jQuery或纯JavaScript滚动查看3-5或4-6中的元素？
回答 6
Stack Overflow用户
发布于 2011-08-26 22:17:08
$("select").scrollTop($("select").find("option[value=4]").offset().top);只需为select元素和其中的值设置适当的选择器
Stack Overflow用户
发布于 2015-05-09 00:29:11
我构建了这个扩展，它是这个问题的一个更合适的解决方案。它是灵活的，可重用的，并且它建立在jQuery之上。http://jsfiddle.net/db86eu91/4/
;(function(){
/**
The MIT License (MIT)
Copyright (c) 2015 Márcio Reis marcio.reis@outlook.com
Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in
all copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
THE SOFTWARE.
*/
$.fn.ScrollToValue = function(target){
var $select = $(this);
if (!$select.length) return;
var value = target;
//how many pixels is the select list scrolled from the moment we run this code???
var distanceScrolledFromTop = $select.scrollTop();
//how many pixels separate the top of the page from the <select> element that we pretend to manipulate
var offsetSelect = $select.offset().top;
//assuming a offset().top of 0 on our list how many pixels separate our target option from the top of the page?
var offsetElement = $select.find('[value=' + value + ']').offset().top + distanceScrolledFromTop;
//Because the offset of our element is always bigger than the offset of our select box, we must subtract the offset of our target element by the offset of our list. That's it
$select.scrollTop(offsetElement - offsetSelect);
}
})();Stack Overflow用户
发布于 2013-03-23 01:14:13
这是使用jquery的coffescript (coffeescript直接翻译成javascript)
exports.mylist_scroll_to = (value) ->
element = $("#mylist")[0]
item_height = element.scrollHeight/element.length
$("#mylist").scrollTop(item_height*(element.selectedIndex))页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/7205702
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